Michael Bayer wrote: > your best bet with this mapping right now is: > > print > Media > .query > .select_from > (media_table > .join > (catalog_table > ).join > (catalog_channel_table > )).filter(CatalogChannel.c.id_channel==playlist.id_channel).all() > > which is really how select_from() was intended to be used.
This works with SQLite, but not MySQL: (1054, "Unknown column 'catalog_channels.id_channel' in 'on clause'") You'd say this is a MySQL bug ? Darn... Also, "select_from" still makes us play with tables. At first, I was looking at an alternative to fully use classes rather than tables for doing the joins. I remember I already played with that "select_from" syntax, which was working. Regards, -- Alexandre CONRAD --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
