> I.e., *all* columns from "th" are being added to the columns clause of > the select. According to the SQL standard, these names all need to > be added to the GROUP BY as well - if MS-SQL is allowing only a > partial GROUP BY list, thats just poor behavior on the part of MS-SQL > (MySQL has this bug as well). What this query really looks like is: > > SELECT *, count(somecol) FROM table GROUP BY * > > where the "*" includes the primary key column of the table, and > therefore it groups by the full set of columns on the table which > renders the count() meaningless.
so a=session.query(th).filter(sqlalchemy.and_(th.APPLIED_TEST==1,th.CODING_DATE=='20080325')).group_by(th.RECORD_NO)._values(th.RECORD_NO,sqlalchemy.func.count(th.RECORD_NO)).all() is just a slightly more complicated way of saying: s=sqlalchemy.select([th.RECORD_NO,sqlalchemy.func.count(th.RECORD_NO)],sqlalchemy.and_(th.APPLIED_TEST==1,th.CODING_DATE=='20080404')).group_by(th.RECORD_NO).execute().fetchall() If I had to pick I would just go with select. (unless there is other reason to use query) Is there a way to get this ? SELECT RECORD_NO, count(RECORD_NO) FROM table GROUP BY RECORD_NO (primary key is RECORD_ID) The only way I know how to do it is via sqlalchemy.select but I would like the query type of the return where my results are type(a) <type 'list'> >>> type(a[0]) <class '__main__.th'> How would I do that? Lucas --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
