I think you have to use group by with a count(). Something like Account.query.join(Account.users).group_by(Account.id).filter(func.count(User.id) > 1)
On Mon, Jan 26, 2009 at 12:59 PM, Jon Nelson <jnel...@jamponi.net> wrote: > > Let's assume I have a 1:many relationship between Accounts and Users. > > What I want (for example) is a list of Accounts with > 1 User. > > Ideally, I'd do this: > > Account.query().filter( len(Account.users) > 1 ).all() > > but of course that doesn't work. > > Instead of describing the myriad ways I've tried, I thought I'd ask instead: > > What's the easiest/best way to go about that without lots of hoop-jumping? > > I'm using 0.5.2 > > -- > Jon > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
