Hi Olaf,

OK, thanks, that works fine indeed.

> Well, as with any other (single-value-returning) Sub-Select
It is just that saw SQL's where the update part came after the CTE, eg:
https://stackoverflow.com/questions/27637278/how-to-remove-duplicate-rows-with-cte-when-partitioning-by-another-tables-colum

WITH cte AS
( SELECT ROW_NUMBER() OVER
(PARTITION BY GroupId ORDER BY Created) AS Rnk FROM
  @Item AS i JOIN @ItemType AS it ON i.ItemTypeId = it.Id )
DELETE FROM cte WHERE Rnk > 1;

RBS


On Fri, Oct 18, 2019 at 8:26 PM Olaf Schmidt <n...@vbrichclient.com> wrote:

> Am 18.10.2019 um 19:45 schrieb Bart Smissaert:
>
> > Regarding:
> >
> > With r(s2, s, i) As (Select 2, 1, 1 Union All
> >     Select s2, (s2>0)*(s+s2/s)*.5, i+1 From r Where Abs(s2-s*s)>1e-12
> > Limit 32
> > ) Select s From r Order By i Desc Limit 1
> >
> > How would this work if I wanted to update all the values in a table
> column
> > to have the square root?
>
> Well, as with any other (single-value-returning) Sub-Select
> (which was enclosed in parentheses)...
>
> E.g.
>       "Update MyTable Set MyCol = (Select 1)"
> would update MyCol with the value 1 across the whole table...
>
> Same thing basically (only "a bit larger") with a CTE-based
> "Single-Value-SubSelect"...
>
> BTW, I've updated and tuned the thing a bit (which should now
> offer more precision, and ~20% more performance as well):
>
> With  r (x, y, i) As (
>    Select ?, 1, 1  Union All
>    Select x,(x>0)*(y+x/y)/2 yi,i+1 From r Where Abs(yi-y)>1e-12 Limit 32
> ) Select y From r Order By i Desc Limit 1
>
> Note the question-marked "Parameter" for the "squared Input-Value"
> (in the first Select Statement of the CTEs triple).
>
> Integrated into an Update-Query it could look this way:
>
> Update MyTable Set MySquareRoot = ( -- SubSelect-Opening-Paren...
>   With  r (x, y, i) As (
>     Select MySquaredValue, 1, 1  Union All
>     Select x,(x>0)*(y+x/y)/2 yi,i+1 From r Where Abs(yi-y)>1e-12 Limit 32
>   ) Select y From r Order By i Desc Limit 1
> ) -- SubSelect-Closing-Paren...
>
> HTH
>
> Olaf
>
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