On Wed, May 25, 2016 at 10:23:23PM +0000, Politis Archontis wrote: > So is this how it is usually done? Convolving all (N+1)^2 HOA > channels of order N with the set of binaural filters and summing > for the left ear, and then doing the same for the right but with > inverted polarity for the (N^2+N)/2 HOA channels of m<0 ?
There's no need to store all the convolution results and do the summing twice: let M = sum of components with m >= 0 S = sum of compomemts with m < 0 L = M + S R = M - S Ciao, -- FA A world of exhaustive, reliable metadata would be an utopia. It's also a pipe-dream, founded on self-delusion, nerd hubris and hysterically inflated market opportunities. (Cory Doctorow) _______________________________________________ Sursound mailing list Sursound@music.vt.edu https://mail.music.vt.edu/mailman/listinfo/sursound - unsubscribe here, edit account or options, view archives and so on.
