Thanks for the clarification, this makes perfect sense.. Archontis
On 26 May 2016, at 10:06, Fons Adriaensen <f...@linuxaudio.org<mailto:f...@linuxaudio.org>> wrote: On Wed, May 25, 2016 at 10:23:23PM +0000, Politis Archontis wrote: So is this how it is usually done? Convolving all (N+1)^2 HOA channels of order N with the set of binaural filters and summing for the left ear, and then doing the same for the right but with inverted polarity for the (N^2+N)/2 HOA channels of m<0 ? There's no need to store all the convolution results and do the summing twice: let M = sum of components with m >= 0 S = sum of compomemts with m < 0 L = M + S R = M - S Ciao, -- FA A world of exhaustive, reliable metadata would be an utopia. It's also a pipe-dream, founded on self-delusion, nerd hubris and hysterically inflated market opportunities. (Cory Doctorow) _______________________________________________ Sursound mailing list Sursound@music.vt.edu<mailto:Sursound@music.vt.edu> https://mail.music.vt.edu/mailman/listinfo/sursound - unsubscribe here, edit account or options, view archives and so on. -------------- next part -------------- An HTML attachment was scrubbed... URL: <https://mail.music.vt.edu/mailman/private/sursound/attachments/20160526/a816f391/attachment.html> _______________________________________________ Sursound mailing list Sursound@music.vt.edu https://mail.music.vt.edu/mailman/listinfo/sursound - unsubscribe here, edit account or options, view archives and so on.
