No but you could group them on some simple function (like the last n digits). Perhaps just the last 5 digits then you have 10k nodes with 35k index entries each.
(And you can of course index those nodes with those 5 last digits so you can quickly retrieve them) (for adding to the index - or you keep them in a list or array). You can of course experiment with that. Michael Am 01.07.2011 um 14:22 schrieb Massimo Lusetti: > On Tue, Jun 28, 2011 at 2:25 PM, Rick Bullotta > <rick.bullo...@thingworx.com> wrote: > >> Ah! Got it. That makes sense, and that most definitely is an EXTREME edge >> case!!! ;-) > > Does it make more sense to have each hash index point to its own node > ... so I end up having more then 350.000.000 of nodes. So does this > will help? > > Cheers > -- > Massimo > http://meridio.blogspot.com > _______________________________________________ > Neo4j mailing list > User@lists.neo4j.org > https://lists.neo4j.org/mailman/listinfo/user _______________________________________________ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user
