I just ran the following Junit test with no problems...
public void test() throws XmlException, IOException{
String xmltext = new
String("<test><element1>testvalue</element1></test>");
XmlObject xmlObject = XmlObject.Factory.parse(new
ByteArrayInputStream(xmltext.getBytes()));
Node rootnode = xmlObject.getDomNode().getFirstChild();
assertEquals("test",rootnode.getNodeName());
}
________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED]
Sent: 15 September 2008 14:41
To: [email protected]
Subject: RE: Very simple question (I think)
Sorry bad example
It's was just suppose to be psudo code
String xml = "big xml document";
I have tried it with many big valid xml documents - without luck.
/Nicolai
"Andrew Mansfield" <[EMAIL PROTECTED]>
15-09-2008 15:36
Please respond to
[email protected]
To
<[email protected]>
cc
Subject
RE: Very simple question (I think)
I think you need to parse a valid source document first. Then you can
get access to the underlying XmlObject.
Regards,
________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED]
Sent: 15 September 2008 14:32
To: [email protected]
Subject: Very simple question (I think)
Hello
On xmlbeans.apache.org
<http://xmlbeans.apache.org/docs/2.0.0/guide/conGettingStartedwithXMLBea
ns.html> it says that XMLBeans provide
<quote>
It provides a familiar Java object-based view of XML data without losing
access to the original, native XML structure
</quote>
I am using XMLBeans on a xml structure that is signed with a hash value
so *nothing* must change before the xml is invalid.
The question is: *HOW* do i get access to the original, native XML
structure.
because this doesn't work
String xml = "big xml document";
XmlObject parse = XmlObject.Factory.parse(xml);
String newXml = parse.xmlText();
if (xml.equals(newXml)
System.out.println("jubii");
else
System.out.println("damn");
Please help :-)
Cheers
Nicolai
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