Sorry - but no good

>From the javadoc

toString
String toString()
Returns an XML string for this XML object. 
The string is pretty-printed. If you want a non-pretty-printed string, or 
if you want to control options precisely, use the xmlText() methods. 

/Nicolai

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"Andrew Mansfield" <[EMAIL PROTECTED]> 
15-09-2008 16:13
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RE: Very simple question (I think)






try parse.toString();

From: Nicolai Odum [mailto:[EMAIL PROTECTED] 
Sent: 15 September 2008 15:09
To: user@xmlbeans.apache.org
Subject: RE: Very simple question (I think)


I will try again :-) 

Sorry for my pore english skills. 

When I say invalid i mean that the generated hash value no longer is 
valid...I can work with the xml beans structure but I need acces to the 
untouched, native, raw xml string that I used as a argument to the 
factory. 

XmlObject parse = XmlObject.Factory.parse(xml); 


/Nicolai 

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"Andrew Mansfield" <[EMAIL PROTECTED]> 
15-09-2008 15:58 

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I just ran the following Junit test with no problems... 
 
public void test() throws XmlException, IOException{ 
String xmltext = new String("<test><element1>testvalue</element1></test>"
); 
XmlObject xmlObject = XmlObject.Factory.parse(new 
ByteArrayInputStream(xmltext.getBytes())); 
Node rootnode = xmlObject.getDomNode().getFirstChild(); 
assertEquals("test",rootnode.getNodeName()); 
} 


From: Nicolai Odum [mailto:[EMAIL PROTECTED] 
Sent: 15 September 2008 14:41
To: user@xmlbeans.apache.org
Subject: RE: Very simple question (I think)


Sorry bad example 

It's was just  suppose to be psudo code 

String xml = "big xml document"; 

I have tried it with many big valid xml documents - without luck. 

/Nicolai 


"Andrew Mansfield" <[EMAIL PROTECTED]> 
15-09-2008 15:36 

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RE: Very simple question (I think)










I think you need to parse a valid source document first. Then you can get 
access to the underlying XmlObject. 
 
Regards, 

From: Nicolai Odum [mailto:[EMAIL PROTECTED] 
Sent: 15 September 2008 14:32
To: user@xmlbeans.apache.org
Subject: Very simple question (I think)


Hello 

On xmlbeans.apache.org it says that XMLBeans provide 

<quote> 
It provides a familiar Java object-based view of XML data without losing 
access to the original, native XML structure 
</quote> 

I am using XMLBeans on a xml structure that is signed with a hash value so 
*nothing* must change before the xml is invalid. 

The question is: *HOW* do i get access to the original, native XML 
structure. 

because this doesn't work 

String xml = "big xml document"; 
XmlObject parse = XmlObject.Factory.parse(xml); 
String newXml = parse.xmlText(); 

if (xml.equals(newXml) 
      System.out.println("jubii"); 
else 
      System.out.println("damn"); 



Please help :-) 

Cheers 

Nicolai 
  
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