try parse.toString(); ________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED] Sent: 15 September 2008 15:09 To: [email protected] Subject: RE: Very simple question (I think) I will try again :-) Sorry for my pore english skills. When I say invalid i mean that the generated hash value no longer is valid...I can work with the xml beans structure but I need acces to the untouched, native, raw xml string that I used as a argument to the factory. XmlObject parse = XmlObject.Factory.parse(xml); /Nicolai CSC * This is a PRIVATE message. If you are not the intended recipient, please delete without copying and kindly advise us by e-mail of the mistake in delivery. NOTE: Regardless of content, this e-mail shall not operate to bind CSC to any order or other contract unless pursuant to explicit written agreement or government initiative expressly permitting the use of e-mail for such purpose * CSC Danmark A/S * Registered Office: Retortvej 8, DK -1780 Copenhagen V , Denmark * Registered in Denmark No: 15231599 "Andrew Mansfield" <[EMAIL PROTECTED]> 15-09-2008 15:58 Please respond to [email protected] To <[email protected]> cc Subject RE: Very simple question (I think) I just ran the following Junit test with no problems... public void test() throws XmlException, IOException{ String xmltext = new String("<test><element1>testvalue</element1></test>"); XmlObject xmlObject = XmlObject.Factory.parse(new ByteArrayInputStream(xmltext.getBytes())); Node rootnode = xmlObject.getDomNode().getFirstChild(); assertEquals("test",rootnode.getNodeName()); } ________________________________ From: Nicolai Odum [mailto:[EMAIL PROTECTED] Sent: 15 September 2008 14:41 To: [email protected] Subject: RE: Very simple question (I think) Sorry bad example It's was just suppose to be psudo code String xml = "big xml document"; I have tried it with many big valid xml documents - without luck. /Nicolai "Andrew Mansfield" <[EMAIL PROTECTED]> 15-09-2008 15:36 Please respond to [email protected] To <[email protected]> cc Subject RE: Very simple question (I think) I think you need to parse a valid source document first. Then you can get access to the underlying XmlObject. Regards, ________________________________ From: Nicolai Odum [mailto:[EMAIL PROTECTED] Sent: 15 September 2008 14:32 To: [email protected] Subject: Very simple question (I think) Hello On xmlbeans.apache.org <http://xmlbeans.apache.org/docs/2.0.0/guide/conGettingStartedwithXMLBea ns.html> it says that XMLBeans provide <quote> It provides a familiar Java object-based view of XML data without losing access to the original, native XML structure </quote> I am using XMLBeans on a xml structure that is signed with a hash value so *nothing* must change before the xml is invalid. The question is: *HOW* do i get access to the original, native XML structure. because this doesn't work String xml = "big xml document"; XmlObject parse = XmlObject.Factory.parse(xml); String newXml = parse.xmlText(); if (xml.equals(newXml) System.out.println("jubii"); else System.out.println("damn"); Please help :-) Cheers Nicolai ________________________________ This email with all information contained herein or attached hereto may contain confidential and/or privileged information intended for the addressee(s) only. If you have received this email in error, please contact the sender and immediately delete this email in its entirety and any attachments thereto. (W1) ________________________________ This email with all information contained herein or attached hereto may contain confidential and/or privileged information intended for the addressee(s) only. If you have received this email in error, please contact the sender and immediately delete this email in its entirety and any attachments thereto. (W1) -------------------------------------------------------------------------- This email with all information contained herein or attached hereto may contain confidential and/or privileged information intended for the addressee(s) only. If you have received this email in error, please contact the sender and immediately delete this email in its entirety and any attachments thereto. (W1)
