Hi guys: I would like to save my SPARQL result coming from ResultSet into new rdf. (new rdf resources) cause I want to do more work on this subgraph and it has to be in the original rdf format.
I tried outputAsRDF function and it worked however the result I got the following: <rdf:Description rdf:nodeID="A5"> <rs:value rdf:resource=" https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.owl#genotypePhenotype "/> <rs:variable>omimt</rs:variable> </rdf:Description> <rdf:Description rdf:nodeID="A6"> <rs:value rdf:resource=" https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.rdf#C0007589 "/> <rs:variable>w</rs:variable> </rdf:Description> <rdf:Description rdf:nodeID="A7"> <rs:binding rdf:nodeID="A8"/> <rs:binding rdf:nodeID="A9"/> <rs:binding rdf:nodeID="A10"/> <rs:binding rdf:nodeID="A11"/> <rs:binding rdf:nodeID="A12"/> <rs:binding rdf:nodeID="A13"/> <rs:binding rdf:nodeID="A14"/> <rs:binding rdf:nodeID="A15"/> <rs:binding rdf:nodeID="A16"/> <rs:binding rdf:nodeID="A17"/> <rs:binding rdf:nodeID="A18"/> <rs:binding rdf:nodeID="A19"/> <rs:binding rdf:nodeID="A20"/> <rs:binding rdf:nodeID="A21"/> <rs:binding rdf:nodeID="A22"/> <rs:binding rdf:nodeID="A23"/> <rs:binding rdf:nodeID="A24"/> <rs:binding rdf:nodeID="A25"/> <rs:binding rdf:nodeID="A26"/> <rs:binding rdf:nodeID="A27"/> </rdf:Description> how I can remove this nodes things and make it something like: <rdf:Description rdf:about=" https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.rdf#C3229174"> <j.0:label>Cytra-K Oral Product</j.0:label> <rdf:type rdf:resource=" https://csel.cs.colorado.edu/~noor/Drug_Disease_ontology/DDID.owl#chemical "/> </rdf:Description> please help me out -- Adeeb Noor Ph.D. Candidate Dept of Computer Science University of Colorado at Boulder Cell: 571-484-3303 Email: adeeb.n...@colorado.edu