Jones--
Your idea is similar to the one I had in mind, however, I was thinking the
Li in the ceramic may be released as a vapor and be forced under a pressure
gradient to the interior or at least near the interior surface where it
could circulate in the porous ceramic matrix. The circulation would
maintain a reasonable temperature around the reactive cites, whatever they
may be, as they produce the significant energy being reported.
The formation of an SPP active interface could be a possibility and is a new
idea. This is the first concrete idea I have heard as to what the SPP
active structure might be. Others have assumed the surfaces of nano
particles are where the SPP could form, however it was always a concern that
where were 2-D surfaces in the case of the nano particles. You may have
identified a potential 2-D surface.
Bob
----- Original Message -----
From: "Jones Beene" <jone...@pacbell.net>
To: <vortex-l@eskimo.com>
Sent: Sunday, December 28, 2014 8:15 AM
Subject: RE: [Vo]:Russian scientist reports replicating hot-cat excess heat
From: Bob Cook
* It seems to me that there must be a separate cooling mechanism
happening to remove or redistribute the heat within the reactor.
Well, if you are assuming that the net gain derives from 1/10th gram of
hydride fuel, which starts off as a powder, then it is possible that the
powder is first liquefied - and in a few hours, before the H2 has
dissipated, is trapped on the inner surface, due to a liquid film layer
deposited by the vapor pressure of Li-Al, and this alloy would be uniformly
coating the wall of the reactor.
The coating would “redistribute the heat”, no? It would also provide a
perfect surface layer for SPP formation on the interface with the alumina.
On another forum, it was suggested that the number (6.7e21) of lithium and
hydrogen atoms, if giving up only 4 eV per atom which is the chemical
maximum - would be 4.2 kilojoules, while the observed excess heat during 8
min “heat after death” was about 380 kilojoules - and during the whole
experiment much more.
This is one of several details indicating that the reaction could also be
related to fractional hydrogen f/H, dark matter, or Mills’ hydrino, which
would release the amount of energy which is seen. This level of energy is
much less than nuclear but much more than chemical.
In the famous Thermacore paper, for instance - the excess energy is shown to
be ~54.4 eV per active proton, which is similar to what is seen here. A
longer run is possible since the f/H is not depleted in the first few levels
of redundancy.
In fact, if the ash in the Russian experiment does not turn up the isotopes
which Rossi claims, and it probably will not IMHOI, then the underlying
reaction could be related to hydrogen “shrinkage” (ground state redundancy)
with the energy coming from electron angular momentum instead of the
nucleus.
Jones
