Holmlid has left out the most important experimental detail.

What is the laser like? I suspect it is chirped into the exowatt range where 
anything can happen.


This is a rich field that does not require any suppositions about dense 
hydrogen.  Large accelerators became nearly obsolete by the chirped laser 
capabilities since 1998.


The failure to describe the laser input casts a pall on everything he has 
posted in the last 20 years.


________________________________
From: Axil Axil <janap...@gmail.com>
Sent: Monday, January 23, 2017 12:12 AM
To: vortex-l
Subject: Re: [Vo]:Fast particles

I don.t think that Holmlid is producing a hydrogen plasma at the place where 
the LASER strikes the collection foil, because the Ultra Dense hydrogen on the 
collection foil is not ionized as it falls by gravity from the iron oxide 
catalyst into the collection foil, A plasma would be too energetic to allow 
that collection process, especially a wakefield energized plasma.

On Sun, Jan 22, 2017 at 10:21 PM, 
<mix...@bigpond.com<mailto:mix...@bigpond.com>> wrote:
Dear Professor,

The conventional means of producing muons is through bombardment with GeV
particles in a particle accelerator.
So if one had a cheap and efficient means of producing muons, then muon
catalyzed D-D fusion might be economic.
It seems you may have built such a particle accelerator, see

https://phys.org/news/2015-11-discovery-enable-portable-particle.html

The process upon which this is based bombards a very dense plasma, with a pulsed
laser which seems to describe your experimental setup quite well.

The particle accelerator might explain the energetic particles that you are
detecting, while the muon catalyzed fusion may explain the excess energy.

I might add that while muons catalyze fusion reactions, the same might also be
true of negatively charged mesons, since they are even heavier than muons, so
the tunneling time should be even further reduced. True, the  lifetime of pions
is very short, but this may not matter in a very dense plasma, since the density
means that the travel distance to the next atom is also very short.

Regards,

Robin van Spaandonk <mix...@bigpond.com<mailto:mix...@bigpond.com>>


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