Re: [Vo]:Black Holes from Newtonian Gravity? - discs.gif

[Robin van Spaandonk]

In reply to  Horace Heffner's message of Mon, 13 Oct 2008 01:31:05 -0800:
Hi,
[snip]
>But it is so for a very thin disc, therefore a very thin disc can not  
>exist in the vicinity of the black hole. A thin disc's field is not a  
>1/r^2 field, nor even a 1/r field, but rather a uniform field  
>directed at the disc.

Actually, it is precisely the opposite. The gravitational field of the disc is
only perpendicular to the surface for an infinitely *thick* disk, because then
the centre of gravity (halfway down the length of what has become a column), is
at an angle which approaches 90 degrees to the "plane" of the disc.

Regards,

Robin van Spaandonk <[EMAIL PROTECTED]>