Not yet Eric. Perhaps you can give that technique a try. The cell consists of a lot of pieces that I do not know how to handle in that manner.
I performed a quick calculation since my request for a sanity check and came up with the following concept: If the power is applied for a period of 1000 seconds and all of it is stored within the cell you obtain 48.22 joules/second x 1000 seconds or 48 kilo joules. The measurements suggest that the device has a reasonably consistent time constant of 360 seconds. If I can capture half of the energy of 48 kilo joules I would have 24 kilo joules. It appears that my model estimate of 28 kilo joules might actually be in the ballpark once a significant time has elapsed to capture energy. I hope to find a simple way to ensure that my model is correct, but so far I only have an approximation to back up the simulation results. I suppose I could use a simple RC model and give that a try since I like to have two independent calculations if possible to support new concepts. Dave -----Original Message----- From: Eric Walker <eric.wal...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Mon, Dec 10, 2012 11:47 pm Subject: Re: [Vo]:Energy Stored Within MFMP Celani Cell On Mon, Dec 10, 2012 at 8:02 PM, David Roberson <dlrober...@aol.com> wrote: This seems to be a bit high, so I was hoping someone in the group could give me a sanity check. If my simulation accurately calculates the stored energy then it would be very useful. I recall that chemical binding energy maxes out at around 4eV per atom in a material; so perhaps 10eV is a safe upper limit. Have you calculated what 28 KJ would be, divided among the approximate number of atoms contained within the mass that is possibly acting as a storage device? Eric
