No one knows, because the only guy with the data (Rossi) is so secretive. And all of us can understand why.
The best available evidence suggests that there is a danger of radioactive release. But that will be stepped over like the local republican Roman children who complained when Julius Caesar cross the Rubicon river. On Mon, May 20, 2013 at 5:07 PM, Mark Gibbs <mgi...@gibbs.com> wrote: > So, in run away mode the reactor can do/always does emit radiation (of > what type? X-rays and/or gamma?) is it possible that the casing of the > reactor and the other components would not become radioactive? Is there any > information as to what type of detector Celani used? If the spectators at > the demo were unharmed yet radiation was detected, what does that tell us > about the type and intensity of the radiation? > > [mg] > > > On Mon, May 20, 2013 at 2:59 PM, Jed Rothwell <jedrothw...@gmail.com>wrote: > >> James Bowery <jabow...@gmail.com> wrote: >> >> Gibbs asked about "melt down" which has a particular meaning in the >>> context of nuclear reactors. Clearly, the E-Cat does not, in this meaning, >>> melt down. >>> >> >> Oh Yes It Does. >> >> Quite remarkable considering there is only 283 W of input power. Anyone >> who has heated a stainless steel object of this size with that much power, >> such an electric frying pan, will know that you cannot possibly melt it >> with 283 W. You cannot even fry an egg. It does does not become >> incandescent. Assuming the power measurements are right to within an order >> of magnitude, there is no way this thing could be incandescent. >> >> That should give Mary Yugo nightmares, if she pauses to think about it, >> which she will not. >> >> Several cold fusion devices have melted, vaporized or exploded. I know of >> 6. Informed sources tell several others in China did that, but the Chinese >> do not wish to discuss the matter. >> >> - Jed >> >> >
