Robin, The problem at hand is that the skeptic claims that power due to the DC current can be very large and not detected. There has been no discussion of the AC current reading being affected by the DC so far. That is a different issue entirely.
I would like for them to answer the questions because then they might realize that their position is invalid. I can explain this if required. No one is suggesting that Rossi actually has a DC power supply hidden within the wall I hope. This would be beyond reality since it would be so easy to measure with a voltmeter or any monitor that looks at the voltage. The testers did a visual look at the voltage from what I have determined. So, skeptics, what say you? Dave -----Original Message----- From: mixent <mix...@bigpond.com> To: vortex-l <vortex-l@eskimo.com> Sent: Sun, May 26, 2013 11:08 pm Subject: Re: [Vo]:Re: [Vo]:Re: [Vo]:Re: [Vo]:Torbjörn Hartman describes power measurments In reply to David Roberson's message of Sun, 26 May 2013 22:35:09 -0400 (EDT): Hi, This is a little different. A full bridge rectifier will allow for both halves of the AC current to pass, and so it should be measured as little different to a purely resistive load. However a single diode will only allow one half to pass, which *may* mess up magnetic field based current measurements. (I guess whether if does or not depends on the sophistication of the device.) > >Assume that you have a bridge rectifier in the blue box. This is followed by >a filtering capacitor. The DC is then used by the electronics connected to the capacitor. Are you saying that it is not possible to determine the power input to this type of network by measuring the input AC voltage and current? Or are you saying that someone has performed a scam and put a DC supply in series with the normal AC voltage? > >You do know that this could easily be measured by a simple DC voltmeter, right? > >Dave [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
