Robin,
I do not see a problem with what Eric is suggesting. Regardless of how many charges and moving charges reside in the universe, only the net vector fields due to all of them is present at the location of the D reactions. The superposition of all of the individual fields results in one final value that interacts. The various vectors of the total could arise far away from the D site, but their levels would drop off very fast with distance so only the nearest ones would generally dominate. For example, the total magnetic field vector at a point determines how a moving charged particle's path is curved at that point. The potentially far off source of that field does not have to get information about the movement of that particle before the force is felt. This type of thought fits into the concept that local time is what counts for a reference frame. Distance makes the local times different between the "friend" nucleus and the interacting D's. If you follow up on the momentum and energy pulses detected by the "friends" nearby, then they would not see any reaction forces until the time required for light speed fields to reach them. After that period has elapsed, they would be subject to potentially large dynamic forces. Dave -----Original Message----- From: mixent <mix...@bigpond.com> To: vortex-l <vortex-l@eskimo.com> Sent: Sun, Jun 23, 2013 5:06 pm Subject: Re: [Vo]:Rossi and DGT Similarity? In reply to Eric Walker's message of Sun, 23 Jun 2013 12:09:38 -0700: Hi, [snip] >Thinking about this a little more, I want to argue that the influence of >nearby nuclei on a nuclear reaction that is underway is inherently faster >than light in a sense. Consider a point in time t, at which a two-deuteron >resonance is about to decay into one of the various branches. Suppose that >t+dt is a point later in time, at which the decay will occur, and that the >interval is shorter than the time required for light to travel from the >nucleus to the unstable two-deuteron resonance. At that point in time >there will still be an "image" of the nearby nucleus at some earlier time >t' in the background. I'm guessing that the two-deuteron resonance will >interact electrostatically with that earlier image and that it does not >matter that the influence does not originate at time t, when the reaction >started, as we are considering a force that is relatively constant over >time and does not changing much. > >So I suppose this implies that the two-deuteron resonance, in branching >towards kinetic energy for the 4He and the palladium nucleus, is pushing >off of the ghost image of a nucleus that preceded the start of the reaction? > >Eric What you are essentially saying is that momentum is exchanged with the field, rather than the particle itself. My initial reaction to this was to agree, however I am left wondering. There are always fields of all particles in the universe present at every point in the universe, so if such interaction were possible, then wouldn't it completely alter what we understand as Newton's laws? (or just explain them?) I suspect that your model would make it possible to "push off" against the entire universe, which clearly doesn't happen in reality, or we would never see the T / 3He reaction at all. I think that if you are correct, then the strength of the interaction must depend on the distance, as in Coulomb's law. BTW I think what you are talking about is the basis of Quantum Electrodynamics (QED). Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
