-----Original Message----- From: Edmund Storms > Bob,
ES: these three particles create a deuteron after all of the excess mass energy has been emitted as photons. The neutrino has very little energy because very little remains when the d forms. The creation process is unique to lenr and applies to all the isotopes of hydrogen, at least that is my model. if lenr is to be explained, you need to stop thinking in conventional terms. This is a new kind of nuclear process. Ed, Bob I fully agree with this summary to the extent that when Ed's proposal is slanted slightly more into the f/H (fractional hydrogen) version, which is another way to look at a variation of Mills' CQM - and the deuteron loses energy as the ground state collapses, then it makes far more sense to imagine gammaless fusion as the QM result of the lowest state of two deuterons in the deep Dirac layer (DDL). This is the state that then goes to helium - via QM time reversal and recaptures the energy already expended in the prior "shrinkage" where UV photons have been shed "all the way down". Very elegant ... at least with deuterium, this is very elegant. However, it is probably wise to acknowledge Mills' contribution and notably the argument does not explain more than necessary. The He nucleus is essentially paying back energy already shed so the lack of gamma can be explained away. This makes sense with bosons, but Pauli prevents this from happening with protons. There is no spin problem with deuterium going to helium. That would be another way of looking at Bob Cook's spin objection. However, one cannot transfer this lovely deuteron vehicle over to protons, without getting a speeding ticket. Instead "something else" must happen for energy to occur without the problems of spin and other major difficulties. The solution is obvious to me - and it is also unproved but suffers fewer objections when looking at experimental results. That something else, can indeed be based on the solar model and without a problem with spin. It is RPF which is also known as the diproton reaction. P+P <-> 2He There is no permanent fusion in RPF and no gamma. The two protons are ultimately unbound but this is not elastic collision and they do fuse for a tiny amount of time. QCD (the strong nuclear force) replaces the energy which has been shed on the atomic shrinkage, and that energy comes from excess proton mass. Again there is no proof of RPF either - but it comes with less baggage than P-e-P. That is the crux of the argument which Ed and I have several times per week - to the annoyance of others, no doubt. However, the ongoing argument has allowed both of us to hone our approaches- by focusing on the obvious weaknesses of the alternative. Jones
