Jones--
I agree. In thinking about alignment and then jumbling of particle
alignment there is first energy absorption and then energy distribution,
however, I think the net input of energy from the driving H field must be
positive. Of course, if in the reaction, mass is lost, the total energy
output may be much greater than the driving H field input.
Bob
----- Original Message -----
From: "Jones Beene" <jone...@pacbell.net>
To: <vortex-l@eskimo.com>
Sent: Wednesday, March 26, 2014 9:43 AM
Subject: RE: [Vo]:Magnetic permeability and LENR
To clarify:
If the LENR reaction, at any stage, involves hydrogen
flipping rapidly from ortho to para alignment (THz) then that spin-energy
could be converted to heat by Mu Metal foil as both the electrode and flux
sink.... the tritium reaction which occurs with deuterium (Claytor) could
be
the result of heat having been extracted instead of the cause of that
heat.
This is not as crazy as it sounds, at least not in QM.
Imagine a large number of nanocavities which have been formed into nickel,
using Mizuno's glow discharge technique. The SEM images indicate that
these
cavities are like surface blisters, raised on the formerly flat surface.
D2 is contained therein and at a threshold temperature, can go into a
spin-flipping mode where the molecules flip from ortho-to-para alignment
rapidly and/or from atomic to molecular form (or both) like a see-saw. The
effective magnetic field of any atom of deuterium is 12.5 T but the
molecule
is diamagnetic. That creates a strong changing flux pattern (which may not
be conserved) but that near-field flux would not be noticed unless the
cavity walls can convert it into heat.
IOW - an oscillation between bound and unbound modes of two atoms in a
nanocavity creates a strong near-field magnetic flux at terahertz
frequency
which diminishes rapidly with distance. Thus the magnetic permeability of
the walls of the cavity are important to capture a percentage of that
flux.
Mu metal is at least 10 times more capable (higher permeability) than
nickel
to capture near field flux.
Once the two deuterium atoms have given up significant levels of spin
energy
to their surroundings, then the Oppenheimer-Philips effect happens at a
reduced threshold to give tritium. OP is a quantum effect - not a
thermonuclear effect. It is the result of excess heat having been already
extracted - and not the cause of that heat.
In the case of hydrogen, no secondary fusion reaction (or side-effect
reaction) is possible as is the case with bosonic deuterium (due to Pauli
exclusion). The result with H2 is two energy depleted protons which can no
longer shed energy and effectively go cold, or else they capture
fractional
electrons at close radius and go dark.
Mills defines dark energy as highly redundant ground state hydrogen - but
he
may have missed that the primary way protons can do this is via magnetic
spin coupling - and not his way - which involves impossibly high levels of
ionization. Both ways are possible, even in the same reaction - but the
Rossi effect does not require extreme ionization, and Mills does require
it.