On Fri, 14 Jan 2011, Peter Taps wrote:

Thank you for sharing the calculations. In lay terms, for Sha256, how many blocks of data would be needed to have one collision?

Two.

Bob
--
Bob Friesenhahn
bfrie...@simple.dallas.tx.us, http://www.simplesystems.org/users/bfriesen/
GraphicsMagick Maintainer,    http://www.GraphicsMagick.org/
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