Dear all,
I have recently upgraded to R 2.14.0 with Windows 7. I wish to use the command
'cph' but the Design library is no longer on the list of installable packages.
How can I install Design so that I may use the 'cph' function?
Many thanks,
Laura
[[alternative HTML version
Le mercredi 04 janvier 2012 à 09:04 +, Bonnett, Laura a écrit :
Dear all,
I have recently upgraded to R 2.14.0 with Windows 7. I wish to use
the command 'cph' but the Design library is no longer on the list of
installable packages. How can I install Design so that I may use the
'cph'
Thank you!
-Original Message-
From: Milan Bouchet-Valat [mailto:nalimi...@club.fr]
Sent: 04 January 2012 09:23
To: Bonnett, Laura
Cc: 'r-help@r-project.org'
Subject: Re: [R] R 2.14.0 Design library
Le mercredi 04 janvier 2012 à 09:04 +, Bonnett, Laura a écrit :
Dear all,
I have
Dear all,
As I said in my previous email I have just upgraded to R 2.14.0 on Windows 7.
I have just run the 'coxph' function and notice that a Concordance statistic is
produced. Is there any way to extract this information from the output?
E.g. can I call the concordance value independently
On 03.01.2012 21:22, Li SUN wrote:
Thanks, Rolf, Justin and Uwe!
Actually I wanted to run .R file as a script, just like what people do
for bash scripts or python scripts. It seems to me that adding
#!/usr/bin/R -f at the first line is what I need. Is this true?
Perhaps even Rscript rather
On 04/01/2012 01:52, Peter Langfelder wrote:
On Tue, Jan 3, 2012 at 4:03 PM, Carl Baribaultcrlbr...@gmail.com wrote:
Dear All,
I've seen posts to the effect that..
1) choose.dir is only available for windows, and
2) tk_choose.dir would be the linux equivalent.
I'm still having trouble with
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 04/01/12 10:39, Uwe Ligges wrote:
On 03.01.2012 21:22, Li SUN wrote:
Thanks, Rolf, Justin and Uwe!
Actually I wanted to run .R file as a script, just like what
people do for bash scripts or python scripts. It seems to me that
adding
Le mercredi 04 janvier 2012 à 09:27 +, Bonnett, Laura a écrit :
Dear all,
As I said in my previous email I have just upgraded to R 2.14.0 on Windows 7.
I have just run the 'coxph' function and notice that a Concordance statistic
is produced. Is there any way to extract this
Dear R helpers,
I need to use KS and AD test for Generalized Pareto and Generalized extreme
value.
E.g. if I need to use KS for Weibull, I have teh syntax
ks.test(x.wei,pweibull, shape=2,scale=1)
Similarly, for AD I use
ad.test(x, distr.fun, ...)
My problem is fir given data, I have
Brett, Spencer,
I replied to Brett on the R-SIG-GUI mailing list, suggesting to use the
proto package. I found it most useful to structure the code when
developing my R2STATS interface.
2. Have you reviewed the other R projects with a graphical user
interface for R? Several are
I would like to make a meta analysis based on metafor package. If I only have
the data of RR, 95%CI of every study, could I finish the meta analysis? If
possible, how to do it? Millions of thanks!
--
View this message in context:
I'm new to R and I'm not a Statistician I'm an Accountant, but I'm finding it
an excellent tool for the business analysis work I do.
I need to run LM() where both response and predictor are held in matrices.
The model follows the form:-
regression1 = matrix1.col1 - matrix2.col1
regression2 =
data-matrix(rnorm(10))
data[c(1,4,6)]-NA
print(data)
data-matrix(data[!is.na(data)])
print(data)
-
Isaac
Research Assistant
Quantitative Finance Faculty, UTS
--
View this message in context:
http://r.789695.n4.nabble.com/problem-in-R-tp4260254p4260976.html
Sent from the R help mailing
I am running the nnet package as
neural.soft-nnet(custcat~region+ed+marital+tenure+age+address+income,size=3,softmax=TRUE)
This returns the error message : formal argument softmax matched by
multiple actual arguments
Here the dependent variable custcat is a factor with 4-levels. This
I've done a lot of research on this very topic and found a few solutions. But
all the ways I've discovered involve loops.
Applying it to what you want, the best way I've found is to do (stolen from
an experienced R user, of course):
y-array(rnorm(100),dim=c(10,10))
On 12-01-03 2:39 PM, gregory benison wrote:
If one attempts to install RODBC (via install.packages('RODBC'))
without having an ODBC driver installed, this error message results:
checking sqlext.h presence... no
checking for sqlext.h... no
configure: error: ODBC headers sql.h and sqlext.h not
See http://biostat.mc.vanderbilt.edu/Rrms for a list of changes that the user
needs to deal with, especially with respect to plotting predicted values.
Frank
Bonnett, Laura wrote
Thank you!
-Original Message-
From: Milan Bouchet-Valat [mailto:nalimilan@]
Sent: 04 January 2012
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to make sum(!is.na(x)) a function in a
separate line prior to this call? If not, please advise.
N.Valid=sapply(x,sum(!is.na(x)))
Error in match.fun(FUN) :
'sum(!is.na(x))' is
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to make sum(!is.na(x)) a function in a
separate line prior to this call? If not, please advise.
Hello all,
I looking at package dse or vars or mAr
I know how to simulate a VAR(p) process, my problem is that most of those
processes are unstable (not weakly stationary).
Do anybody know how to generate a random VAR (or VARMA even better) process
that is weakly stationary?
Thanks
--
View this
More specifically.
I know that a condition for a VAR(p) process to be stable (weakly
stationary) is that the companion form of the equation (see AWESOME Pfaff
book analysis of integrated and cointegrated time series in R) as
eigenvalues of modulus 1.
My problem is that I want to generate such
On Jan 4, 2012, at 7:41 AM, Dan Abner dan.abne...@gmail.com wrote:
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to make sum(!is.na(x)) a function in a
separate line prior to this call?
Yes or inline using an
Le mardi 03 janvier 2012 à 11:39 -0800, gregory benison a écrit :
If one attempts to install RODBC (via install.packages('RODBC'))
without having an ODBC driver installed, this error message results:
checking sqlext.h presence... no
checking for sqlext.h... no
configure: error: ODBC headers
Hi
Being able to do object oriented programming in R is really good. I now
started using the Reference Classes and really like it.
Though, I have one problem: I cannot find a way to update a method on an
existing object.
The flexibility that scripting gives (really needed for interactive data
Dan,
It depends on what you want to achieve. I suspect you just want to remove
missing values before summing; if so, consider
sapply(x, sum, na.rm=TRUE)
instead. To make your code running, try
sapply(x, function(x) sum(!is.na(x)))
However, this would just count the number of non-missing
OK thanks.
In my case I think it might be possible to work around this by reshaping my
data and then using lmlist() to run separate regressions for each data
group. lmlist() is new to me but it looks like it will do the job.
--
View this message in context:
On 1/3/2012 9:36 PM, maximilian.mueller wrote:
Here is the syntax:
options(contrasts=c(contr.sum, contr.poly))
read.csv2(test21.csv) - dat3
mod3 - lm(cbind(umsatz_t1, umsatz_t2, umsatz_t3, umsatz_t4) +
cbind(ebitda_t1, ebitda_t2, ebitda_t3, ebitda_t4)
+ ~ 1, data=dat3)
idata3 -
On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to make sum(!is.na(x)) a function in a
separate line
On Jan 4, 2012, at 5:49 AM, Vincy Pyne wrote:
Dear R helpers,
I need to use KS and AD test for Generalized Pareto and Generalized
extreme value.
When I searched on these names Generalized Pareto and Generalized
extreme value I got plenty of hits (over 90 in one case and over 100
in
On Jan 4, 2012, at 8:02 AM, Milan Bouchet-Valat wrote:
Le mardi 03 janvier 2012 à 11:39 -0800, gregory benison a écrit :
If one attempts to install RODBC (via install.packages('RODBC'))
without having an ODBC driver installed, this error message results:
checking sqlext.h presence... no
Hello everyone,
After running the following code, I obtain this error message.
mydata - read.table(textConnection(mystring),
+header=TRUE, sep=,,
+row.names=id, na.strings= )
mydata
Warning message:
closing unused connection 3 (mystring)
=
However, when I attempt to run
On Jan 4, 2012, at 9:53 AM, Dan Abner wrote:
Hello everyone,
After running the following code, I obtain this error message.
mydata - read.table(textConnection(mystring),
+header=TRUE, sep=,,
+row.names=id, na.strings= )
mydata
Warning message:
closing unused connection 3
Dear Max,
I'm having a little trouble following what you did and am also confused by the
subject of your posting. Is this a response to another message? Is it really
about getting sphericity tests?
In addition:
(1) Why are you adding together the response matrices cbind(umsatz_t1,
umsatz_t2,
Hi
Being able to do object oriented programming in R is really good. I
now started using the Reference Classes and really like it.
Though, I have one problem: I cannot find a way to update a method on
an existing object.
The flexibility that scripting gives (really needed for interactive
data
Hi, I have to forecast some value of a time series using an ARIMA(5,1,3)
model.
I saw in Matlab there isn't a function for ARIMA models because ARIMA
models are a type of Box-Jenkins models. But how to set parameters?
In the Box-Jenkins models
m = bj(data,[nb nc nd nf nk])
How to set nb, nc,
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I didn't find
how to do it.
I want to write sm as normal text and w,grass in the subscript. Can
anybody help me?
And a more general question: I read the help to
Hi,
A simple question I hope. I wish to add a single vertical line to a plot
with several density plots.
Here is a simplified example.
thedata - data.frame(x1=rnorm(100,1,1),x2=rnorm(100,3,1)) #create data
thedata.m-melt(thedata)
densityplot(~value, thedata.m,
Perhaps you are confusedthis is R-help
that said, it's very easy with
forecast:::forecast.Arima
in R
Michael
On Wed, Jan 4, 2012 at 8:38 AM, Antonio Tirri antonio.ti...@gmail.com wrote:
Hi, I have to forecast some value of a time series using an ARIMA(5,1,3)
model.
I saw in Matlab
On Jan 4, 2012, at 9:17 AM, peter dalgaard wrote:
On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to
Maximizing f(x) = x'Ax makes sense only when A is negative-definite.
Therefore, this is the same as minimizing x'Bx, where B = -A, and B is
positive-definite.
In other words, you should be able to simply flip the sign of the original
matrix . This should yield a positive-definite matrix
On 04.01.2012 16:12, suse wrote:
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I didn't find
how to do it.
I want to write sm as normal text and w,grass in the subscript. Can
anybody help me?
And a more
Hello everyone,
I have two questions:
1)
I want to create a subset of a data frame column-wise and simultaneously
extract the row names into a proper variable. I tried this, but received
an error:
myleft-mydata[c(id=row.names(mydata),workshop,gender,q1,q2)]
Error in `[.data.frame`(mydata,
Hi
Hi,
A simple question I hope. I wish to add a single vertical line to a plot
with several density plots.
Here is a simplified example.
thedata - data.frame(x1=rnorm(100,1,1),x2=rnorm(100,3,1)) #create data
thedata.m-melt(thedata)
densityplot(~value, thedata.m,
Hi
As you did not provide any data you probably can not get canned solution
Hello everyone,
I have two questions:
1)
I want to create a subset of a data frame column-wise and simultaneously
extract the row names into a proper variable. I tried this, but
received
an error:
Hi R helpers!
I have a question. I'm trying to create a function for an exercise. Here are
the arguments I should include:
x and y are numeric
z is a name (plus,minus,multiply,divide)
and swap is logical.
Here is what the function should do:
When z=plus, then x+y is performed and so on for the
thank you very much Petr. Yes, I meant densityplot form lattice.
The code I gave plots the densities of both x1 and x2 in one panel.
Could you show me how to integrate the function addline into the code so
that a vertical line v=0 is added?
On 4 January 2012 15:55, Petr PIKAL
I'm not a huge fan of this sort of solution because it doesn't make
sense for non-vector-shaped (i.e., matrix or data.frame) data. It only
works here because the matrix produced is a special 1xN case.
E.g.,
# Set up some data (and yes, I realize I'm using the trick I'm
speaking out against, but
thank you very much Petr. Yes, I meant densityplot form lattice.
The code I gave plots the densities of both x1 and x2 in one panel.
Could you show me how to integrate the function addline into the code so
that a vertical line v=0 is added?
The function is used after you make a plot.
Unfortunately, there's a general no-homework rule because we never
know what your instructor wants you to figure out on your own (though,
a sincere thanks for admitting this was hw rather than trying to trick
us like so many). That said, I think your second function, while a
little clumsy, does
hi: does anyone know if it's possible and, if so, where there's an example,
of putting the output of summary(lm) right on the plot of the data itself.
If the answer is to use capture.output and then text, I'll try that but I
was thinking there might be an example somewhere ? thanks.
Dear all
I am trying to make an interaction plot among 6 variables; e.g. PH to be in
the x axis and the rest 5 variables in the y axis. The code that I am using is
the below:
The name of my file is e.g. spec so
spec-read.csv(spec.csv)
head (spec)
str(spec)
names-names(spec)[2:6]
fExtremes::pgpd pgev have always worked for me. Though, if I
remember right, the physical sciences and finance tend to use
reciprocal definitions for one of the parameters (can't remember which
-- xi in gpd perhaps?) so tread lightly.
Michael
On Wed, Jan 4, 2012 at 8:21 AM, David Winsemius
Re
How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove things that are not theirs to remove.
Calling gc() will close all unused connections, so
no
On Tue, 3 Jan 2012, David Winsemius wrote:
burns.tds[ !duplicated(burns.tds) , ]
Apparently it does not matter if the site column in the data frame is a
factor or a character, read.zoo() generates the same error. Applying the
above produces a long list starting with:
On 04/01/2012 17:12, William Dunlap wrote:
Re
How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove things that are not theirs to remove.
Calling
On Jan 4, 2012, at 10:51 AM, Uwe Ligges wrote:
On 04.01.2012 16:12, suse wrote:
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I
didn't find
how to do it.
I want to write sm as normal text and w,grass
On Jan 4, 2012, at 12:21 PM, Rich Shepard wrote:
On Tue, 3 Jan 2012, David Winsemius wrote:
burns.tds[ !duplicated(burns.tds) , ]
Apparently it does not matter if the site column in the data frame
is a
factor or a character, read.zoo() generates the same error. Applying
the
above
On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of David Winsemius
Sent: Wednesday, January 04, 2012 9:53 AM
To: Uwe Ligges
Cc: r-help@r-project.org; suse
Subject: Re: [R] subscript with comma
On Jan 4, 2012, at 10:51 AM,
On 04/01/2012 18:21, Duncan Murdoch wrote:
On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to
Anne,
Thank you for writing back, and for including your data.
I have two things here. First, I ran an a analysis of your data and have
my observations
on interpretation. Second, I answer your general question about glht and
TukeyHSD when there are interactions.
I illustrate how to get the
On Wed, 4 Jan 2012, David Winsemius wrote:
You didn't ask for what was duplicated, but rather what was NOT duplicated
with that code. In the case of a dataframe it is the entire row that is
tested.
My original question was what was duplicated, but ... I changed the
function by dropping the
That works, but if all you want is one vertical line at 0, this will work
densityplot(~value, thedata.m, groups=variable,auto.key=list(columns=2),
panel = function(x, y, ...) {
panel.densityplot(x, ...)
panel.abline(v=0)
}
)
On Jan 4, 2012, at 19:21 , Duncan Murdoch wrote:
On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
Rather than using a sledgehammer, use showConnections(all=TRUE) to see
all connections, and close the ones you want to (and its help page shows
you how).
In older versions that do give the
Nothing attached. I don't know what you entitled teh compressed dput
output but it did not pass the filters of the mailserver and you did
not copy me. If chemdata is available as a text file, hten make sure
its extension is .txt and then attach it.
--
David.
On Jan 4, 2012, at 1:31 PM,
On Jan 4, 2012, at 16:32 , David Winsemius wrote:
On Jan 4, 2012, at 9:17 AM, peter dalgaard wrote:
On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call to sapply() and error
On Wed, 4 Jan 2012, David Winsemius wrote:
Nothing attached. I don't know what you entitled teh compressed dput output
but it did not pass the filters of the mailserver and you did not copy me.
David,
It must have been stripped off as too large (14K).
Regardless, I solved the problem:
On Jan 4, 2012, at 3:21 PM, Rich Shepard wrote:
On Wed, 4 Jan 2012, David Winsemius wrote:
Nothing attached. I don't know what you entitled teh compressed
dput output but it did not pass the filters of the mailserver and
you did not copy me.
David,
It must have been stripped off as
Hello everyone,
How does one pass multiple arguments of a user defined function to that
function when called within sapply()?
I have the following:
myna-function(x,miss.val) {x[x %in% miss.val]-NA;x}
mydataNA3-sapply(mydataNA,c(x=myna,miss.val=c(9,99)))
Error in match.fun(FUN) :
'c(x =
On Jan 4, 2012, at 3:47 PM, Dan Abner wrote:
Hello everyone,
How does one pass multiple arguments of a user defined function to
that
function when called within sapply()?
I have the following:
myna-function(x,miss.val) {x[x %in% miss.val]-NA;x}
On Jan 4, 2012, at 11:30 AM, Mark Leeds wrote:
hi: does anyone know if it's possible and, if so, where there's an
example,
of putting the output of summary(lm) right on the plot of the data
itself.
If the answer is to use capture.output and then text, I'll try that
but I
was thinking
On 01/04/2012 09:25 AM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove
summary: Specifically, how does one do stack/FIFO operations in R?
Generally, how does one code functions with side effects in R?
details:
I have been a coder for years, mostly using C-like semantics (e.g.,
Java). I am now trying to become a scientist, and to use R, but I don't
yet have the
do s[1] and s[-1] do what you're looking for?
those are just to display... if you want to change s, you need to reassign
it or fiddle with namespacing. however, I'd say it is better to write R
code as though data structures are immutable until you explicitly re-assign
them rather than trying to
Brian,
FYI, I had previously installed tcl-devel but had overlooked tk-devel
on the OS. Now that I've installed tk-devel on the OS, the following
sequence of commands has succeeded:
sudo ./configure --with-tcltk
sudo make
sudo make check
sudo make install
R
...
library(tcltk)
Loading Tcl/Tk
Am Dienstag, 3. Januar 2012, 19:51:36 schrieb Prof. Dr. Matthias Kohl:
D - AbscontDistribution(d = function(x) dbeta(x, 2, 6) + dbeta(x,6,2),
low = 0, up = 1, withStand = TRUE)
Dear all,
thank you all again for your help.
So, summing up, (in case this might be useful to other beginners -
Hi, i try to plot ts data on x-y coordiante
I want my data to be points, but somehow it always comes out with lines and
# linked bwtween data,
i used plot(lag(x,-9),y,type=p), x and y are time series data
is there anyway to remove those lines?
Thanks a lot
--
View this message in context:
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in order to get concatenation of
x[1] y[1] z[1] (one yellow apple)
x[1] y[1] z[2] (one yellow cheese)
x[1] y[2] z[1](one blue apple)
...
x[length(x)]
Hi,
Is there an easy way to add symbols to a line in a scatter plot, so that
only a few symbols are added per line (a line drawn based on a large set of
data points) , in order to distinguish several lines in one graph (not a
symbol for each data point as is the default in plot()).
Thanks a lot!
Thank you! It works now.
But I still don't understand, how all these expressions, , paste, group,
eval... have to be used together. (For example, I first tried
expression(sm[w,grass]) but it didn't work, and I couldn't find, why (and
when) commas are interpreted here differently). So: Is there
thanks, it works!
--
View this message in context:
http://r.789695.n4.nabble.com/problem-on-plotting-ts-data-tp4261865p4262179.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hello,
Try 'as.vector' or 'as.numeric'
x - as.ts(rnorm(20))
y - as.ts(rnorm(20))
plot(x)
plot(as.vector(lag(x,-9)),as.vector(y),type=p) # works
plot(as.numeric(lag(x,-9)),as.numeric(y),type=p) # also works
Rui Barradas
--
View this message in context:
Hi Michael,
Thanks for your answer! sorry I didn't see this rule... No problem,
I'll try to figure it out by myself.
Thanks for your indication though!
Thomas
2012/1/4, Michael Weylandt [via R] ml-node+s789695n4261894...@n4.nabble.com:
Unfortunately, there's a general no-homework rule
Dear Community,
I'd like to plot an rq object the same way I do with a lm one, is it
possible? Something like this
plot(rqmodel , 1:4, id.labels=rownames(pga1)); where
rqmodel - rq(log(vd) ~ v1 + log(v2) +log(v3) + v4 + v5 ,data =dat)
Thanks in advance and apologies, I'm pretty newbie with
Thank you for the advice; this is very helpful. I will see how they feel
about installing Inkscape. I'll also work on getting R installed in a
Windows environment so I can produce .emf and .wmf files. I found one
old message on this list from someone who had luck doing this by running
R with
Hello,
If you want to apply the same procedure to all elements of an object, check
out the '*apply' functions.
In this case,
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
lapply(x, function(x) paste(x, y))
gives a good picture of what you want to do, just transform it into a
Dear R users,
This probably a really noob question, but I'm stuck. I'd like to pass some
variables from bash to R as strings. I can successfully pass variables using
commandArgs(), the problem is that I end up with an array. So, for example:
Args - commandArgs(TRUE)
Args
[1] one two three
One thing R could do better is to provide a standard way to view README and
similar files before installing a package. That might have helped here.
Agreed... right now, the R documentation points to a straightforward,
one-line way to download and install packages from the R command line,
but
Hi. You can use expand.grid here
expand.grid(x,y,z)
Andrija
On Wed, Jan 4, 2012 at 5:32 PM, jeremy jeremynamer...@gmail.com wrote:
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in order to get
? expand.grid
Michael
On Wed, Jan 4, 2012 at 10:32 AM, jeremy jeremynamer...@gmail.com wrote:
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in order to get concatenation of
x[1] y[1] z[1] (one
On Jan 4, 2012, at 10:32 AM, jeremy wrote:
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in order to get concatenation of
x[1] y[1] z[1] (one yellow apple)
x[1] y[1] z[2] (one yellow
Try expand.grid() to create all the combinations. Then just collapse
them with paste():
apply(expand.grid(x, y, z), 1, paste, collapse = )
Cheers,
Josh
On Wed, Jan 4, 2012 at 8:32 AM, jeremy jeremynamer...@gmail.com wrote:
Hi all,
I'm trying to combine exhaustively several character
apply(expand.grid(x, y, z, stringsAsFactors=F), 1, paste, collapse=' ')
On Wed, Jan 4, 2012 at 8:32 AM, jeremy jeremynamer...@gmail.com wrote:
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in
On Jan 4, 2012, at 3:08 PM, dood wrote:
Dear R users,
This probably a really noob question, but I'm stuck. I'd like to pass some
variables from bash to R as strings. I can successfully pass variables using
commandArgs(), the problem is that I end up with an array. So, for example:
Args
Hi,
Is there an easy way to add symbols to a line in a scatter plot, so that
only a few symbols are added per line (a line drawn based on a large set
of
data points) , in order to distinguish several lines in one graph (not a
symbol for each data point as is the default in plot()).
Hi
Hello, I have the following code using rbinom, but I don't understand what
*+1* means in the code. Could someone help? Thanks so much,
X1-c(A,B)[rbinom(n,1,0.6)+1]
X2-c(C,D)[rbinom(n,1,0.1)+1]
--
View this message in context:
Homework?
If not, context?
-- Bert
On Wed, Jan 4, 2012 at 1:38 PM, lynn.tsai vernal@gmail.com wrote:
Hello, I have the following code using rbinom, but I don't understand what
*+1* means in the code. Could someone help? Thanks so much,
X1-c(A,B)[rbinom(n,1,0.6)+1]
homework or not,
?rbinom
should be plenty.
On Wed, Jan 4, 2012 at 1:38 PM, lynn.tsai vernal@gmail.com wrote:
Hello, I have the following code using rbinom, but I don't understand what
*+1* means in the code. Could someone help? Thanks so much,
X1-c(A,B)[rbinom(n,1,0.6)+1]
On 12-01-04 11:41 AM, suse wrote:
Thank you! It works now.
But I still don't understand, how all these expressions, , paste, group,
eval... have to be used together. (For example, I first tried
expression(sm[w,grass]) but it didn't work, and I couldn't find, why (and
when) commas are
Thanks, guys!
I am using Rscript at the moment and will definitely try littler.
Li Sun
2012/1/4 Rainer M Krug r.m.k...@gmail.com:
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On 04/01/12 10:39, Uwe Ligges wrote:
On 03.01.2012 21:22, Li SUN wrote:
Thanks, Rolf, Justin and Uwe!
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