You cannot directly compare 11 to 80 GHz. Totally different market. I can't do beyond 2.5 km at real five to six nines uptime with 80 GHz (even with +18 Tx power radios).
I can do 60 km with 11 if the link will tolerate some ACM. On Aug 9, 2016 9:31 PM, "John Blake" <[email protected]> wrote: > It's obviously pricier than the B11, but if you want true symmetrical and > a ton of throughput, you could look at the Huawei RTN-380 radios. These > will do 4Gbps (2Gbps symmetrical) at full licensing, or there are 1, 2, > 3Gbps licensing options. They use 71-76 GHz and 81-86 GHz and so are super > easy and cheap to get (lightly) licensed. These are very popular with > carriers outside the US, but not so much in the US because of all the > Huawei/Ciscolobby disputes, but that has largely been resolved and they > have been getting traction here. Let me know if you want more info, we are > Huawei VAR. > > John > > > On Wed, Aug 3, 2016 at 9:54 PM, <[email protected]> wrote: > >> Gino, >> >> That seems to be the only configuration that meets the requirement. The >> way I see it, in a traditional FDD system you would license an XPIC pair of >> frequencies, say 11075 H/V at point A and 11565 H/V at point B. Assuming >> an 820 running 256QAM you might get 500mbps per polarity per direction, for >> a two-way aggregate of 2gpbs. You would have licensed 160MHz at each end >> of the system, for a system efficiency of 2gbps/320MHz = 6 b/s/hz. >> If you operate a B11 on the same pair of frequencies, you have to use >> their FD mode which a typical PCN claims will deliver 736mbps. It would >> seem that this can be viewed as a two-way aggregate rate, because the >> radios still take turns transmitting as in a true TDMA system. So, the >> system efficiency here is 736mbps/320MHz = 2.3 b/s/hz -- below the >> requirement of 3 b/s/hz. >> >> If you switch the B11 to the normal TDMA mode you will need to transmit >> on the same frequency from each end of the link. So, in addition to >> licensing 11075 H and V transmitting from point A, you also need to license >> 11075 H and V transmitting from point B, which adds another 160MHz at each >> end. The PCNs show this configuration giving 1.47gbps (again assumed to be >> an aggregate figure due to the TDMA mode). This is an efficiency of >> 1.47gbps/640MHz = 2.3 b/s/hz again. However, because you have licensed two >> frequency pairs, each site can also transmit and receive on the unused >> 11565 H and V frequencies. If you do this then you get 2*1.47gbps/640MHz = >> 4.6 b/s/hz. This seems to be the only valid configuration, but does this >> take two radios at each end, or just one? >> >> Mike Black >> >> Black & Associates >> >> 727-773-9016 >> >> >> ---------------------------- Original Message ---------------------------- >> Subject: Re: [AFMUG] B11 >> From: "Gino Villarini" <[email protected]> >> Date: Wed, August 3, 2016 3:38 pm >> To: "Animal Farm" <[email protected]> >> ------------------------------------------------------------ >> -------------- >> >> >> > but the radio tx in both channels in the both polarites in both ends ... >> > >> > On Wed, Aug 3, 2016 at 1:31 PM, Eric Kuhnke <[email protected]> >> wrote: >> > >> >> No, it is just as spectrally efficient as any 256QAM radio... One 80 >> MHz >> >> "low" channel in both polarities and one 80 MHz "high" channel in both >> >> polarities, as a typical FDD band plan such as you would use with a >> >> configuration with 2 dishes, 2 orthomode transducers and 4 radio heads >> >> (each radio operating in a single polarity) in a 2+0 configuration. >> >> >> >> You're arriving at the figure of 320 MHz by counting everything twice. >> >> >> >> On Wed, Aug 3, 2016 at 10:28 AM, <[email protected]> wrote: >> >> >> >>> We haven't had the pleasure of coordinating a B11 link yet, but they >> >>> certainly seem to be popular based upon the number of PCNs we are >> >>> seeing. So, a dumb question hopefully based upon a simple >> misunderstanding >> >>> of the numbers: I don't see how this meets the FCC minimum efficiency >> >>> standards for wide channels at 11GHz: >> >>> >> >>> 80MHz channels x H and V = 160MHz, but with high/low pairing you >> double >> >>> this? to 320MHz occupied per end? So, to meet the 3 b/s/hz >> requirement at >> >>> 11GHz your symmetrical throughput would need to be >= 960mbps. What >> am I >> >>> missing? >> >>> >> >>> Mike Black >> >>> >> >>> Black & Associates >> >>> >> >>> 727-773-9016 >> >>> >> >>> >> >>> ---------------------------- Original Message >> ---------------------------- >> >>> Subject: Re: [AFMUG] B11 >> >>> >> From: "Jaime Fink" <[email protected]> >> >>> Date: Tue, August 2, 2016 4:49 pm >> >>> To: "SmarterBroadband" <[email protected]> >> >>> "[email protected]" <[email protected]> >> >>> ------------------------------------------------------------ >> -------------- >> >>> >> >>> > The PHY is 1733 Mbps aggregate, so depending on the chosen window >> >>> sizes, the top real world TCP speeds we’ve seen are between 1200-1300 >> Mbps >> >>> aggregate (75/25 or 50/50 mode), or 600-650 Mbps symmetric (50/50). >> >>> > >> >>> > For 11 GHz this assumes high/low pairing of 80 MHz and both >> >>> polarizations coordinated. >> >>> > >> >>> > Jaime Fink • Mimosa<http://www.mimosa.co> • CPO & Co-Founder >> >>> > >> >>> > >> >>> > On August 2, 2016 at 1:34:31 PM, SmarterBroadband ( >> >>> [email protected]<mailto:[email protected]>) wrote: >> >>> > Can the B11 do 1Gbps Symmetrical? >> >>> > If not what is best Symmetrical? >> >>> > Thanks >> >>> > >> >>> > >> >>> > >> >>> >> >> >> >> >> > >> >> >
