What price range is a Huawei link in? On Wed, Aug 10, 2016 at 2:47 AM, Eric Kuhnke <[email protected]> wrote:
> You cannot directly compare 11 to 80 GHz. Totally different market. I > can't do beyond 2.5 km at real five to six nines uptime with 80 GHz (even > with +18 Tx power radios). > > I can do 60 km with 11 if the link will tolerate some ACM. > > On Aug 9, 2016 9:31 PM, "John Blake" <[email protected]> wrote: > >> It's obviously pricier than the B11, but if you want true symmetrical and >> a ton of throughput, you could look at the Huawei RTN-380 radios. These >> will do 4Gbps (2Gbps symmetrical) at full licensing, or there are 1, 2, >> 3Gbps licensing options. They use 71-76 GHz and 81-86 GHz and so are super >> easy and cheap to get (lightly) licensed. These are very popular with >> carriers outside the US, but not so much in the US because of all the >> Huawei/Ciscolobby disputes, but that has largely been resolved and they >> have been getting traction here. Let me know if you want more info, we are >> Huawei VAR. >> >> John >> >> >> On Wed, Aug 3, 2016 at 9:54 PM, <[email protected]> wrote: >> >>> Gino, >>> >>> That seems to be the only configuration that meets the requirement. The >>> way I see it, in a traditional FDD system you would license an XPIC pair of >>> frequencies, say 11075 H/V at point A and 11565 H/V at point B. Assuming >>> an 820 running 256QAM you might get 500mbps per polarity per direction, for >>> a two-way aggregate of 2gpbs. You would have licensed 160MHz at each end >>> of the system, for a system efficiency of 2gbps/320MHz = 6 b/s/hz. >>> If you operate a B11 on the same pair of frequencies, you have to use >>> their FD mode which a typical PCN claims will deliver 736mbps. It would >>> seem that this can be viewed as a two-way aggregate rate, because the >>> radios still take turns transmitting as in a true TDMA system. So, the >>> system efficiency here is 736mbps/320MHz = 2.3 b/s/hz -- below the >>> requirement of 3 b/s/hz. >>> >>> If you switch the B11 to the normal TDMA mode you will need to transmit >>> on the same frequency from each end of the link. So, in addition to >>> licensing 11075 H and V transmitting from point A, you also need to license >>> 11075 H and V transmitting from point B, which adds another 160MHz at each >>> end. The PCNs show this configuration giving 1.47gbps (again assumed to be >>> an aggregate figure due to the TDMA mode). This is an efficiency of >>> 1.47gbps/640MHz = 2.3 b/s/hz again. However, because you have licensed two >>> frequency pairs, each site can also transmit and receive on the unused >>> 11565 H and V frequencies. If you do this then you get 2*1.47gbps/640MHz = >>> 4.6 b/s/hz. This seems to be the only valid configuration, but does this >>> take two radios at each end, or just one? >>> >>> Mike Black >>> >>> Black & Associates >>> >>> 727-773-9016 >>> >>> >>> ---------------------------- Original Message >>> ---------------------------- >>> Subject: Re: [AFMUG] B11 >>> From: "Gino Villarini" <[email protected]> >>> Date: Wed, August 3, 2016 3:38 pm >>> To: "Animal Farm" <[email protected]> >>> ------------------------------------------------------------ >>> -------------- >>> >>> >>> > but the radio tx in both channels in the both polarites in both ends >>> ... >>> > >>> > On Wed, Aug 3, 2016 at 1:31 PM, Eric Kuhnke <[email protected]> >>> wrote: >>> > >>> >> No, it is just as spectrally efficient as any 256QAM radio... One 80 >>> MHz >>> >> "low" channel in both polarities and one 80 MHz "high" channel in both >>> >> polarities, as a typical FDD band plan such as you would use with a >>> >> configuration with 2 dishes, 2 orthomode transducers and 4 radio heads >>> >> (each radio operating in a single polarity) in a 2+0 configuration. >>> >> >>> >> You're arriving at the figure of 320 MHz by counting everything twice. >>> >> >>> >> On Wed, Aug 3, 2016 at 10:28 AM, <[email protected]> wrote: >>> >> >>> >>> We haven't had the pleasure of coordinating a B11 link yet, but they >>> >>> certainly seem to be popular based upon the number of PCNs we are >>> >>> seeing. So, a dumb question hopefully based upon a simple >>> misunderstanding >>> >>> of the numbers: I don't see how this meets the FCC minimum efficiency >>> >>> standards for wide channels at 11GHz: >>> >>> >>> >>> 80MHz channels x H and V = 160MHz, but with high/low pairing you >>> double >>> >>> this? to 320MHz occupied per end? So, to meet the 3 b/s/hz >>> requirement at >>> >>> 11GHz your symmetrical throughput would need to be >= 960mbps. What >>> am I >>> >>> missing? >>> >>> >>> >>> Mike Black >>> >>> >>> >>> Black & Associates >>> >>> >>> >>> 727-773-9016 >>> >>> >>> >>> >>> >>> ---------------------------- Original Message >>> ---------------------------- >>> >>> Subject: Re: [AFMUG] B11 >>> >>> >>> From: "Jaime Fink" <[email protected]> >>> >>> Date: Tue, August 2, 2016 4:49 pm >>> >>> To: "SmarterBroadband" <[email protected]> >>> >>> "[email protected]" <[email protected]> >>> >>> ------------------------------------------------------------ >>> -------------- >>> >>> >>> >>> > The PHY is 1733 Mbps aggregate, so depending on the chosen window >>> >>> sizes, the top real world TCP speeds we’ve seen are between >>> 1200-1300 Mbps >>> >>> aggregate (75/25 or 50/50 mode), or 600-650 Mbps symmetric (50/50). >>> >>> > >>> >>> > For 11 GHz this assumes high/low pairing of 80 MHz and both >>> >>> polarizations coordinated. >>> >>> > >>> >>> > Jaime Fink • Mimosa<http://www.mimosa.co> • CPO & Co-Founder >>> >>> > >>> >>> > >>> >>> > On August 2, 2016 at 1:34:31 PM, SmarterBroadband ( >>> >>> [email protected]<mailto:[email protected]>) >>> wrote: >>> >>> > Can the B11 do 1Gbps Symmetrical? >>> >>> > If not what is best Symmetrical? >>> >>> > Thanks >>> >>> > >>> >>> > >>> >>> > >>> >>> >>> >> >>> >> >>> > >>> >>> >>
