1. Yes, you cannot modify a const variable. This itself means that it is
read-only.
2.Google structure padding. It is done to make sure that variables start in
memory at addresses that are a multiple of their size. This is more
efficient at hardware level.
'char' (1 byte) variables can be byte aligned and appear at any byte
boundary.
'int' (4 byte) variables must be 4 byte aligned ( they can only appear at
byte boundarys that are a multiple of 4 bytes). So, here
char b --- At any available byte
int c ------ 3 bytes from b.
So, a total of 1+3+4 = 8 bytes.
On Sun, Jul 17, 2011 at 11:38 PM, Abhi <abhi123khat...@gmail.com> wrote:
> 1.When I declare a variable as const then any subsequent assignment of it
> gives an error "assignment of read only variable". Is a const variable
> treated as a read only variable?
>
>
> 2.
>
> #include<stdio.h>
> struct s1 {
> char a;
> };
>
> char s2 {
> char b;
> int c;
> };
>
> printf("%d",sizeof(struct s1)); // output : 1
> printf("%d",sizeof(struct s2)); // output : 8
>
> please explain..
>
>
>
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7th Semester, CSE Dept.
NIT Surathkal, India.
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