@prateek . can you explain me ?? i dint get padding logic in this example of
mine.
On Mon, Jul 18, 2011 at 12:30 AM, sagar pareek <sagarpar...@gmail.com>wrote:
> sizeof long double is 12. So padding concept is perfectly working
>
>
> On Mon, Jul 18, 2011 at 12:26 AM, aditya kumar <
> aditya.kumar130...@gmail.com> wrote:
>
>> struct st
>> {
>> char ch1;
>> long double ld;
>> }s;
>> printf("%d",sizeof(s));
>> //output : 24 (for 32-bit compiler)
>> ->as i have mentioned above the behaviour is undefined in case of sizeof
>> (struct)
>> can any one explain me why the padding concept does not work here ??
>>
>> On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <jega...@gmail.com> wrote:
>>
>>> @Abhi:
>>> Answers:
>>> 1. whenever a 'const' qualifier is added previously to a variable
>>> declaration it means that the value of the variable is automatically
>>> initialized to '0'(because of the 'auto' type of the const variable) and
>>> cannot be changed in any of the following assignment statements to the const
>>> variable.
>>>
>>> 2.
>>> Here for the structure struct s1 since the entire structure is ending
>>> within 8 bytes no padding is done which means
>>> s1: [char a]
>>> 1byte
>>> but for the structure struct s2 consider the following:
>>> s2: [ char a
>>> 1byte
>>> ------ int a-------
>>> ------4bytes----]
>>> so here the concept of padding comes to make all the variable aligned in
>>> even boundaries and so the structure after aligning will look as:
>>> s2: [ ------ char b----
>>> ------4byte-----
>>> ------ int a-------
>>> ------4bytes----]
>>>
>>> so the size of strcut s2 will be 8bytes..........
>>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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