1) you cannot change the const variable .
2) generally sizeof behaviour in case of structure is just undefined. Either
it follows the summation of size of members or it uses padding concept ie in
your example 4 byte each for character(1 byte for char rest of the 3 bytes
is padded up) and 4 byte for integer .This is more efficient
On Sun, Jul 17, 2011 at 11:38 PM, Abhi <abhi123khat...@gmail.com> wrote:
> 1.When I declare a variable as const then any subsequent assignment of it
> gives an error "assignment of read only variable". Is a const variable
> treated as a read only variable?
>
>
> 2.
>
> #include<stdio.h>
> struct s1 {
> char a;
> };
>
> char s2 {
> char b;
> int c;
> };
>
> printf("%d",sizeof(struct s1)); // output : 1
> printf("%d",sizeof(struct s2)); // output : 8
>
> please explain..
>
>
>
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