struct st
{
char ch1;
long double ld;
}s;
printf("%d",sizeof(s));
//output : 24 (for 32-bit compiler)
->as i have mentioned above the behaviour is undefined in case of sizeof
(struct)
can any one explain me why the padding concept does not work here ??
On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <jega...@gmail.com> wrote:
> @Abhi:
> Answers:
> 1. whenever a 'const' qualifier is added previously to a variable
> declaration it means that the value of the variable is automatically
> initialized to '0'(because of the 'auto' type of the const variable) and
> cannot be changed in any of the following assignment statements to the const
> variable.
>
> 2.
> Here for the structure struct s1 since the entire structure is ending
> within 8 bytes no padding is done which means
> s1: [char a]
> 1byte
> but for the structure struct s2 consider the following:
> s2: [ char a
> 1byte
> ------ int a-------
> ------4bytes----]
> so here the concept of padding comes to make all the variable aligned in
> even boundaries and so the structure after aligning will look as:
> s2: [ ------ char b----
> ------4byte-----
> ------ int a-------
> ------4bytes----]
>
> so the size of strcut s2 will be 8bytes..........
>
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