@Nikhil
why is Address of long double : starts at 11 address locations from char
variable ??
is shud start from 3rd adress location from char variable bcoz memory cycle
involves a word so are you padding 11bytes ??
On Mon, Jul 18, 2011 at 1:24 AM, Nikhil Gupta <nikhilgupta2...@gmail.com>wrote:
> @Sagar
>
> Memory sizes of long double variables are compiler and system configuration
> dependent. So obviously, in accordance with your compiler, the size of long
> double is 8 bytes.
>
>
> On Mon, Jul 18, 2011 at 1:22 AM, Nikhil Gupta
> <nikhilgupta2...@gmail.com>wrote:
>
>> @Aditya
>>
>> Here is the padding effect :
>>
>> Address of char : starts anywhere
>> Address of long double : starts at 11 address locations from char variable
>> --> 1+11+12=24 bytes
>>
>>
>> On Mon, Jul 18, 2011 at 1:10 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>
>>> @aditya
>>> actually first see your post, you have written o/p=24 accordingly padding
>>> done is perfect. But actually its printing 16.
>>> So now question arises of padding
>>>
>>> and its pareek not prateek :)
>>>
>>>
>>> On Mon, Jul 18, 2011 at 12:38 AM, aditya kumar <
>>> aditya.kumar130...@gmail.com> wrote:
>>>
>>>> @prateek . can you explain me ?? i dint get padding logic in this
>>>> example of mine.
>>>>
>>>> On Mon, Jul 18, 2011 at 12:30 AM, sagar pareek
>>>> <sagarpar...@gmail.com>wrote:
>>>>
>>>>> sizeof long double is 12. So padding concept is perfectly working
>>>>>
>>>>>
>>>>> On Mon, Jul 18, 2011 at 12:26 AM, aditya kumar <
>>>>> aditya.kumar130...@gmail.com> wrote:
>>>>>
>>>>>> struct st
>>>>>> {
>>>>>> char ch1;
>>>>>> long double ld;
>>>>>> }s;
>>>>>> printf("%d",sizeof(s));
>>>>>> //output : 24 (for 32-bit compiler)
>>>>>> ->as i have mentioned above the behaviour is undefined in case of
>>>>>> sizeof (struct)
>>>>>> can any one explain me why the padding concept does not work here ??
>>>>>>
>>>>>> On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <jega...@gmail.com>wrote:
>>>>>>
>>>>>>> @Abhi:
>>>>>>> Answers:
>>>>>>> 1. whenever a 'const' qualifier is added previously to a variable
>>>>>>> declaration it means that the value of the variable is automatically
>>>>>>> initialized to '0'(because of the 'auto' type of the const variable)
>>>>>>> and
>>>>>>> cannot be changed in any of the following assignment statements to the
>>>>>>> const
>>>>>>> variable.
>>>>>>>
>>>>>>> 2.
>>>>>>> Here for the structure struct s1 since the entire structure is ending
>>>>>>> within 8 bytes no padding is done which means
>>>>>>> s1: [char a]
>>>>>>> 1byte
>>>>>>> but for the structure struct s2 consider the following:
>>>>>>> s2: [ char a
>>>>>>> 1byte
>>>>>>> ------ int a-------
>>>>>>> ------4bytes----]
>>>>>>> so here the concept of padding comes to make all the variable aligned
>>>>>>> in even boundaries and so the structure after aligning will look as:
>>>>>>> s2: [ ------ char b----
>>>>>>> ------4byte-----
>>>>>>> ------ int a-------
>>>>>>> ------4bytes----]
>>>>>>>
>>>>>>> so the size of strcut s2 will be 8bytes..........
>>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> **Regards
>>>>> SAGAR PAREEK
>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>> NIT ALLAHABAD
>>>>>
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>>>
>>>
>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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>>
>>
>>
>> --
>> Nikhil Gupta
>> Senior Co-ordinator, Publicity
>> CSI, NSIT Students' Branch
>> NSIT, New Delhi, India
>>
>>
>
>
> --
> Nikhil Gupta
> Senior Co-ordinator, Publicity
> CSI, NSIT Students' Branch
> NSIT, New Delhi, India
>
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