@pareek..my compiler gives 24 . newazz if ansa is 16 acc to you then it
follows padding principle perfectly. since memory cycle invloves 1 word
hence char will take 1 byte nd 3 bytes will be padded up . rest 12 bytes
will come from long double so 4+12=16 bytes :)
n ya sry abt d name .
On Mon, Jul 18, 2011 at 1:10 AM, sagar pareek <sagarpar...@gmail.com> wrote:
> @aditya
> actually first see your post, you have written o/p=24 accordingly padding
> done is perfect. But actually its printing 16.
> So now question arises of padding
>
> and its pareek not prateek :)
>
>
> On Mon, Jul 18, 2011 at 12:38 AM, aditya kumar <
> aditya.kumar130...@gmail.com> wrote:
>
>> @prateek . can you explain me ?? i dint get padding logic in this example
>> of mine.
>>
>> On Mon, Jul 18, 2011 at 12:30 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>
>>> sizeof long double is 12. So padding concept is perfectly working
>>>
>>>
>>> On Mon, Jul 18, 2011 at 12:26 AM, aditya kumar <
>>> aditya.kumar130...@gmail.com> wrote:
>>>
>>>> struct st
>>>> {
>>>> char ch1;
>>>> long double ld;
>>>> }s;
>>>> printf("%d",sizeof(s));
>>>> //output : 24 (for 32-bit compiler)
>>>> ->as i have mentioned above the behaviour is undefined in case of sizeof
>>>> (struct)
>>>> can any one explain me why the padding concept does not work here ??
>>>>
>>>> On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <jega...@gmail.com> wrote:
>>>>
>>>>> @Abhi:
>>>>> Answers:
>>>>> 1. whenever a 'const' qualifier is added previously to a variable
>>>>> declaration it means that the value of the variable is automatically
>>>>> initialized to '0'(because of the 'auto' type of the const variable) and
>>>>> cannot be changed in any of the following assignment statements to the
>>>>> const
>>>>> variable.
>>>>>
>>>>> 2.
>>>>> Here for the structure struct s1 since the entire structure is ending
>>>>> within 8 bytes no padding is done which means
>>>>> s1: [char a]
>>>>> 1byte
>>>>> but for the structure struct s2 consider the following:
>>>>> s2: [ char a
>>>>> 1byte
>>>>> ------ int a-------
>>>>> ------4bytes----]
>>>>> so here the concept of padding comes to make all the variable aligned
>>>>> in even boundaries and so the structure after aligning will look as:
>>>>> s2: [ ------ char b----
>>>>> ------4byte-----
>>>>> ------ int a-------
>>>>> ------4bytes----]
>>>>>
>>>>> so the size of strcut s2 will be 8bytes..........
>>>>>
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>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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