That is again compiler dependent. Usually when hardware configuration is
taken into account, the compiler uses padding of 3 bytes. But in some cases,
for the ease of hardware access and faster implementation, 11 bytes are
padded. Possibly depends on your system hardware's synchronization with the
compiler.
On Mon, Jul 18, 2011 at 1:27 AM, aditya kumar
<aditya.kumar130...@gmail.com>wrote:
> @Nikhil
> why is Address of long double : starts at 11 address locations from char
> variable ??
> is shud start from 3rd adress location from char variable bcoz memory cycle
> involves a word so are you padding 11bytes ??
>
>
> On Mon, Jul 18, 2011 at 1:24 AM, Nikhil Gupta
> <nikhilgupta2...@gmail.com>wrote:
>
>> @Sagar
>>
>> Memory sizes of long double variables are compiler and system
>> configuration dependent. So obviously, in accordance with your compiler, the
>> size of long double is 8 bytes.
>>
>>
>> On Mon, Jul 18, 2011 at 1:22 AM, Nikhil Gupta
>> <nikhilgupta2...@gmail.com>wrote:
>>
>>> @Aditya
>>>
>>> Here is the padding effect :
>>>
>>> Address of char : starts anywhere
>>> Address of long double : starts at 11 address locations from char
>>> variable --> 1+11+12=24 bytes
>>>
>>>
>>> On Mon, Jul 18, 2011 at 1:10 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>>
>>>> @aditya
>>>> actually first see your post, you have written o/p=24 accordingly
>>>> padding done is perfect. But actually its printing 16.
>>>> So now question arises of padding
>>>>
>>>> and its pareek not prateek :)
>>>>
>>>>
>>>> On Mon, Jul 18, 2011 at 12:38 AM, aditya kumar <
>>>> aditya.kumar130...@gmail.com> wrote:
>>>>
>>>>> @prateek . can you explain me ?? i dint get padding logic in this
>>>>> example of mine.
>>>>>
>>>>> On Mon, Jul 18, 2011 at 12:30 AM, sagar pareek
>>>>> <sagarpar...@gmail.com>wrote:
>>>>>
>>>>>> sizeof long double is 12. So padding concept is perfectly working
>>>>>>
>>>>>>
>>>>>> On Mon, Jul 18, 2011 at 12:26 AM, aditya kumar <
>>>>>> aditya.kumar130...@gmail.com> wrote:
>>>>>>
>>>>>>> struct st
>>>>>>> {
>>>>>>> char ch1;
>>>>>>> long double ld;
>>>>>>> }s;
>>>>>>> printf("%d",sizeof(s));
>>>>>>> //output : 24 (for 32-bit compiler)
>>>>>>> ->as i have mentioned above the behaviour is undefined in case of
>>>>>>> sizeof (struct)
>>>>>>> can any one explain me why the padding concept does not work here ??
>>>>>>>
>>>>>>> On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <jega...@gmail.com>wrote:
>>>>>>>
>>>>>>>> @Abhi:
>>>>>>>> Answers:
>>>>>>>> 1. whenever a 'const' qualifier is added previously to a variable
>>>>>>>> declaration it means that the value of the variable is automatically
>>>>>>>> initialized to '0'(because of the 'auto' type of the const variable)
>>>>>>>> and
>>>>>>>> cannot be changed in any of the following assignment statements to the
>>>>>>>> const
>>>>>>>> variable.
>>>>>>>>
>>>>>>>> 2.
>>>>>>>> Here for the structure struct s1 since the entire structure is
>>>>>>>> ending within 8 bytes no padding is done which means
>>>>>>>> s1: [char a]
>>>>>>>> 1byte
>>>>>>>> but for the structure struct s2 consider the following:
>>>>>>>> s2: [ char a
>>>>>>>> 1byte
>>>>>>>> ------ int a-------
>>>>>>>> ------4bytes----]
>>>>>>>> so here the concept of padding comes to make all the variable
>>>>>>>> aligned in even boundaries and so the structure after aligning will
>>>>>>>> look as:
>>>>>>>> s2: [ ------ char b----
>>>>>>>> ------4byte-----
>>>>>>>> ------ int a-------
>>>>>>>> ------4bytes----]
>>>>>>>>
>>>>>>>> so the size of strcut s2 will be 8bytes..........
>>>>>>>>
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>>>>>>
>>>>>>
>>>>>> --
>>>>>> **Regards
>>>>>> SAGAR PAREEK
>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>> NIT ALLAHABAD
>>>>>>
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>>>>
>>>> --
>>>> **Regards
>>>> SAGAR PAREEK
>>>> COMPUTER SCIENCE AND ENGINEERING
>>>> NIT ALLAHABAD
>>>>
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>>>
>>>
>>>
>>> --
>>> Nikhil Gupta
>>> Senior Co-ordinator, Publicity
>>> CSI, NSIT Students' Branch
>>> NSIT, New Delhi, India
>>>
>>>
>>
>>
>> --
>> Nikhil Gupta
>> Senior Co-ordinator, Publicity
>> CSI, NSIT Students' Branch
>> NSIT, New Delhi, India
>>
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CSI, NSIT Students' Branch
NSIT, New Delhi, India
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