Sorry for per destination load balancing does it mean that all packets go
through one path if all the packets are of the same destination, which in
other words does not load balance ?
Jason
-----Original Message-----
From: Atif Awan [mailto:[EMAIL PROTECTED]]
Sent: Friday, September 01, 2000 5:15 PM
To: Benny Leong (HTHK - Senior Engineer II - iServices Development,
NNSD); [EMAIL PROTECTED]; Yee, Jason
Subject: RE: ip route
The router either does per packet or per destination load balancing. If
process switching is the active switching path then the router will perform
per packet switching ( that is send one packet through one destination and
the other through the next destination ); but if the router is configured
for fast switching then the router will perform per destination load
balancing.
Regards
Atif
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
Benny Leong (HTHK - Senior Engineer II - iServices Development, NNSD)
Sent: Friday, September 01, 2000 1:35 PM
To: '[EMAIL PROTECTED]'; 'Yee, Jason'
Subject: RE: ip route
For the load balancing issue, is it based on load or based on round robin ?
Thanks.
----------
From: Yee, Jason [SMTP:[EMAIL PROTECTED]]
Sent: Friday, September 01, 2000 4:42 PM
To: 'Benny Leong (HTHK - Senior Engineer II - iServices
Development, NNSD)'; '[EMAIL PROTECTED]'
Subject: RE: ip route
It will do load balancing provided both links are of equal costs,
also the
type of routing protocols you used is also important
As for 2. I think it will stop routing thro 2.2.2.1 and fall back to
1.1.1.1
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf
Of
Benny Leong (HTHK - Senior Engineer II - iServices Development,
NNSD)
Sent: Friday, September 01, 2000 3:51 PM
To: '[EMAIL PROTECTED]'
Subject: ip route
Ip route 150.10.0.0 255.255.0.0 1.1.1.1
Ip route 150.10.0.0 255.255.0.0 2.2.2.1
Will these 2 statements :
1. perform load balancing ?
2. if the link to 2nd route fails, will the router stop routing
the
traffic through 2.2.2.1 ?
Thanks.
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