On Mon, Sep 10, 2012 at 1:59 PM, Ted Dunning <[email protected]> wrote: > No. It is the inverse. V' V = I
Pseudoinverse has the same property afaik. The difference as i have it from school is that strictly speaking regular inverse is defined for square matrices only (nxn) and V is not square... But i guess it is a matter of interpretation.. > > On the other hand, V V' != I. We do know that norm(A V V' - A) is small. > > On Mon, Sep 10, 2012 at 1:57 PM, Dmitriy Lyubimov <[email protected]> wrote: > >> Actually i think it is Penrose pseudo-inverse but for our purposes i >> think it has the same effect as actual inverses... >> >> On Mon, Sep 10, 2012 at 1:35 PM, Pat Ferrel <[email protected]> wrote: >> > >> >> The inverse of V is trivial. It is orthonormal so the inverse is the >> >> transpose. >> >> >> > >> > D'oh, that brain cell has been dormant since Linear Algebra 101, which >> is good. I thought it had died. >>
