On 2012-09-24 22:45, Nick Sabalausky wrote:
Because 'b' is neither being assigned to an (int) nor passed into a
template/func parameter that's expecting an (int).
Either I'm just stupid or I've failed completely to understand "implicit
convertible to".
Another example:
struct Foo
{
int[] arr;
alias arr this;
}
void main ()
{
auto foo = Foo([3, 4]);
auto i = foo[0];
}
Have a look at the last line. In that line "foo" is implicitly converted
to "int[]" with the help of the "alias this" in Foo, because the context
requires something "indexable". Since you cannot index a struct the
implicit conversion kicks in. What's the difference?
--
/Jacob Carlborg
