On Tuesday, November 5, 2024 at 3:34:12 PM UTC-7 Russell Standish wrote:

On Tue, Nov 05, 2024 at 01:26:10AM -0800, Alan Grayson wrote: 
> 
> 
> On Tuesday, November 5, 2024 at 12:27:55 AM UTC-7 Russell Standish wrote: 
> 
> Sorry Brent - the measured momentum values are still eigenvalues. 
> 
> Pick 3 orthogonal directions to measure the momentum, say x, y and z. 
> 
> Then the momentum operators are -iℏ∂/∂x, -iℏ∂/∂y and -iℏ∂/∂z, and the 3 
> eigenvalues are the 3 components of momentum. 
> 
> One could also write it in vector form iℏ∇, in which case the operator 
> has a vector-valued eigenvalue. 
> 
> 
> I don't think this is correct. Quantum operators are chosen to be 
Hermitian, 
> that is, self-adjoint IIRC, so that their eigenvalues will be 
> real. This is something that can be proven. So the question remains; how 
can a 
> real eigenvalue be a measured momentum, which 
> is a vector? AG  

You missed my point completely. Momentum is a 3-vector, so the 
momentum operator is 3-vector of hermitian operators, applied 
elementwise over the wavefuction. The "eigenvalue" is a 3-vector, 
applied elementwise over the state vector.


Thanks. Yes, I missed your point but I get it now, and Brent's link also
helped. AG


This is quantum mechanics 101 - any of the introductory books will 
tell you the same - Ramamurti Shankar, Leonard Schiff, Emile 
Durand. I'm surprised Brent made such a howler, but we're all human 
(for how long, I wonder, give JC's comments), and he's picked up 
plenty of howlers I've made over the years. 

Cheers 


-- 

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Principal, High Performance Coders [email protected] 
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