Thanks for trying to help, but as I wrote:

1) I just passed the data

2272 x 1704 size
35 mm focal
1 crop factor


2) I did not run the optimization process

>From data in 1) Hugin computes 52.62 degrees
Have you tried the test I proposed in the previous post ?


On Apr 13, 5:52 am, "Ir. Hj. Othman bin Hj. Ahmad" <othm...@lycos.com>
wrote:
> Sorry for my earlier response.
>
> I'm not an authority on Hugin since I have not studied its source code
> but since nobody is responding to your post, I can volunteer to
> explain with my experience in numerical methods.
>
> Without any clue as to the FOV of an image, Hugin must have been hard
> coded to give 35mm as the initial estimate, and it is a good value
> indeed. The closer this estimate to the actual FOV, the faster pano
> tools will optimise. Most pano pictures use wide angle lenses of at
> most 35mm.
>
> On Apr 11, 2:55 pm, alf <liquidt...@gmail.com> wrote:
>
>
>
> > No. I didn't even run the optimization process. The fov I'm referring
> > to was computed in the file dialog after loading the images.
> > You can verify this by simply creating an image of size2272x1704
> > without exif data (simply save in PPM format for example) and upon
> > loading it give it a focal length of35mm and a crop factor of1.
> > Hugin automatically fills the fov entry box with52.62degrees.
>
> > On Apr11,5:17 am, "Ir. Hj. Othman bin Hj. Ahmad" <othm...@lycos.com>
> > wrote:
>
> > > This data is from the optimisation process of the control points.
>
> > > This fov gives the least error in all the control points.
> > > hugin or any numeral method systems, need to know the boundaries for
> > > the fov or any data. In a360x180, it is360degrees horizontally and
> > >180% vertically.
>
> > > So it is good if you have a set of pictures linked with control points
> > > that wrap around vertically or horizontally. hugin will have
> > > additional data to adjust fov.
>
> > > hugin can still minimise the errors by giving estimates to the fov but
> > > these estimates may be completely wrong to a human being, but you can
> > > help hugin by giving it the initial estimates for the fov for hugin to
> > > quickly minimise the errors.
>
> > > On Apr9,9:27 pm, alf <liquidt...@gmail.com> wrote:
>
> > > > Hmmmm, so here's the data for my camera
>
> > > > width2272
> > > > height1704
> > > > focal length (35mm equivalent)  35mm
>
> > > > From this only data Hugin gives me52.62degrees of FOV : I can not
> > > > understand where this number comes from
>
> > > > I tried the suggested Javascript with the same data and I get  176°
> > > > of hfov ! Obviously wrong because the script needs data to be
> > > > expressed in the same units (pixels), so the focal length should be in
> > > > pixels (?)
>
> > > > On Apr9,2:36 pm, Harry van der Wolf <hvdw...@gmail.com> wrote:
>
> > > > > Hi,
>
> > > > > I can explain it to you, but if you take a look at 
> > > > > <http://imaginatorium.org/stuff/angle.htm>, you can do some 
> > > > > calculations for
> > > > > yourself and see the calculation if you do a "view page source" (or 
> > > > > whatever
> > > > > the command in your browser is). It is in the simple javascript where 
> > > > > you
> > > > > can find how to calculate the FOV, both HFOV and VFOW, based on the 
> > > > > focal
> > > > > length.
>
> > > > > Please note that this calculation is for a rectilinear lens. I don't 
> > > > > know
> > > > > the calculation for a fisheye lens (don't have one, never bothered to 
> > > > > know).
> > > > > I assume when you google you will find the answer soon enough.
>
> > > > > Harry
>
> > > > >2009/4/9alf <liquidt...@gmail.com>
>
> > > > > > I have some images without exif data, for which I know that the35mm
> > > > > > equivalent focal length was...35mm. I've seen that Hugin with this
> > > > > > data computes automatically a FOV when I input the images. How
> > > > > > possible, if the only thing the software knows is the focal length 
> > > > > > and
> > > > > > the image size in pixels ???? Can someone explain me how ? Thanks.
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