I'm now looking to prove that `( abs " ( F " RR ) ) =/= (/)` given `F : RR --> RR`. From my exploration of the definition of --> I believe this should be enough but I don't see an easy path towards that? Would anybody have an example in mind that could give me a little bit of inspiration?
Thanks for the continued support! -stan On Wed, Mar 4, 2020 at 6:29 PM Benoit <[email protected]> wrote: > Stan: you're right about the need to prove this (if using explicit > substitution): look for the utility theorems exchanging [. / ]. with other > symbols (quantifiers, operations). As said by Jim and Thierry, who are > more experienced in proof building, implicit substitution might be easier > to use. I think it is instructive to compare the details of both proving > styles on a specific example (e.g. ralbidv, suggested by Thierry, would be > analogous to exchanging [. / ]. with A.). > > Still, I think adding what I called rspesbcd could prove useful (if it is > not already in set.mm under another label; I cannot search now, but it > probably is already somewhere). > > Benoît > > -- > You received this message because you are subscribed to the Google Groups > "Metamath" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > https://groups.google.com/d/msgid/metamath/ebdd296f-6bcd-49e0-88c8-c7fef3628cdd%40googlegroups.com > <https://groups.google.com/d/msgid/metamath/ebdd296f-6bcd-49e0-88c8-c7fef3628cdd%40googlegroups.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Metamath" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/metamath/CACZd_0zFiVT5n-7%2BYh-YL2mDCLMom6R66gq7gbMT7tgJzTzadQ%40mail.gmail.com.
