Thank you so much for playing the game Tomasz, and bothering to check the 
calculations.

It can also be done with DC a meter or scope that shows True RMS when DC is 
present. [Check by reading a battery on the AC range.]

You can set up a sine wave that is offset by a DC value. You make a voltage 
waveform that is the same shape as the power waveform that we are talking 
about. Then you measure it.

 

There is a useful electronics website.

https://masteringelectronicsdesign.com/how-to-derive-the-rms-value-of-a-sine-wave-with-a-dc-offset/

On that page he shows the mathematics involved. Notice that a very simple 
formula right at the end/bottom covers what we are doing.

It gives an answer very close to yours too.

 

Regarding audio and perceived loudness: if you ever want to increase that 
impact of the sound without “cheating” by using a compressor, then just record 
to magnetic tape. You could even use a deck that has replay monitor heads 
immediately after the record heads so that it is close to real time.

To get up out of the noise they had to set up magnetic to work in a rather 
non-linear region. It automatically compressed. This was one of the things that 
made full digital audio sound different. They didn’t set out to compress “old” 
audio but it happened anyway.

 

That consistent loudness thing really annoys me too. Unfortunately some of the 
normalising programs cause other problems. Some of the problem is caused by 
people using the scope view in their digital software. When you have 20dB 
headroom it looks like you are working so far down that you must be in the 
noise. They also think that you are wasting that space. This is where metering 
methods become so important too. And some training/awareness.

 

Thanks to all the Nixie guys for tolerating this OT discussion too.

Regards,

John K

 

From: neonixie-l@googlegroups.com [mailto:neonixie-l@googlegroups.com] On 
Behalf Of Tomasz Kowalczyk
Sent: Thursday, 18 April 2019 04:04
To: neonixie-l
Subject: Re: [neonixie-l] OT: audio levels

 



W dniu wtorek, 16 kwietnia 2019 15:57:35 UTC+2 użytkownik johnk napisał:

Well, how do I say this Thomas?

It is NOT to be called Watts RMS !

They left the vital word out – it is Watts [RMS derived]. They left out 
“derived”.

 

The RMS volts and RMS amps that you mention when multiplied together produce 
Watts. Just plain Watts.

These Watts are actually the average power of the power waveform that resulted 
from your two sinewaves.

Remember too, that the RMS value of the voltage waveform gives the DC voltage 
that provides the same heating effect. And that is average power.

Gee, I didn’t say that well. I have just spent a while fighting with Win 10 and 
drivers for CH340 on Arduino clone boards – I haven’t recovered !

 

You might think that I am nit picking. However you did say this, “RMS power of 
a sine wave is 0,5 times peak power.”

And the power waveform isn’t really a sinewave in the way we mean it. The 
values of interest here lie in the area under the curve (notice it is twice the 
frequency too?]. In a sine wave [like the Voltage one]  the areas of interest 
are the equal sized ‘lobes’ above and below the zero line. 

I invite you to draw out the two sinewaves [Volts and Current] and the 
resulting power waveform and perform an actual root-mean-square calculation on 
it to prove your statement.  [Graphically is more reliable because it shows the 
workings J  ]

Spoiler: you will NOT get 0.5 x pk as the answer.

 

The VERY rough sketch that I sent Charles shows what I mean about the average 
value [the green bit tipped over into the trough].

(Rough because I was on a new touch screen laptop and NOT in tablet mode. I was 
experimenting; made it tricky to draw with the pen. )

 

I know that you know what you mean when you refer to amplifiers this way, but 
you could add the extra word and be ‘more right’  J

Thanks for nibbling on the hook. But, I really do wish that someone had been 
willing to do the graphical maths thing. Someone must want to prove me wrong, 
surely.

 

John Kaesehagen

Australia

 

 

OK, I see your point. The right way to spell power is just watts (V RMS * I RMS 
= W)
I've ran a little excel excercise - I calculated voltage and current with peak 
value equal to sqrt(2) for 360 points of a sine wave. If I run RMS calculation 
(from definition) on voltage or current, it is equal to 1 (so one times the 
other is 1W), but running it on voltage*current gives a value of about 1,22W 
RMS. 
I admit this is a mistake to use W RMS.

 

When it comes to Loudness War - I am also for dynamic range, but mostly, I am 
for consistent loudness between digital files, so I don't have to change volume 
for each track. Fortunately, loudness war is being actively fought against - as 
far as I know, Spotify attenuates a track if it is too loud, which eliminates 
the whole reason songs were overcompressed. So now those tracks are left with 
their poor dynamic range, but being no louder than slightly compressed or not 
compressed at all songs.
I'm currently building a vacuum tube amplifier, which works greatly with 
uncompressed tracks - it compresses them itself via soft clipping! That's the 
reason 15-20W tube amp can sound like 50W solid state, vocals and most 
instruments can stay at the same SPL, but vacuum tube amp will compress the 
short spikes from percussion or other instrument instead of grossly distorting 
them. Solid state needs that power headroom to prevent going into clipping, 
because you can easily hear it and it isn't pleasurable.
Of course, I could also just build a simple Gainclone amp with higher output 
power for more headroom... but high voltage is fun!

 

Coming back on topic of audio signal level - I think that if I worked in 
proffesional audio, all the different standards would make more sense to me. 
But being a hobbyist who just wants to build an amp, it is straight up annoying.

 

By the way - you can keep calling me Thomas. It is practically the same name. 
Also when I was a kid I used to live in USA for over a year, so I was called 
Thomas a lot in my life :) 

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