Yes, probably, you are right. I've overlooked example section, given by Gabriel.
DROP TABLE gab;
CREATE TABLE gab (usr VARCHAR2(10) NOT NULL, val NUMBER NOT NULL);
INSERT INTO gab VALUES('GAP', 1);
INSERT INTO gab VALUES('GAP', 5);
INSERT INTO gab VALUES('GAP', 5);
INSERT INTO gab VALUES('GAP', 7);INSERT INTO gab VALUES('PAG', 1);
INSERT INTO gab VALUES('PAG', 7);
INSERT INTO gab VALUES('PAG', 2);INSERT INTO gab VALUES('JKL', 1);
INSERT INTO gab VALUES('JKL', 5);
INSERT INTO gab VALUES('JKL', 5);INSERT INTO gab VALUES('GPA', 1);
INSERT INTO gab VALUES('GPA', 5);
INSERT INTO gab VALUES('GPA', 7);
INSERT INTO gab VALUES('GPA', 8);
COMMIT;PL/SQL is not needed to solve this task as SQL task. There reason when it would be wise to rewrite it is out of scope of this topic (but the reason is obvious).
I'm just thinking that the query proposed by you is a bit expensive. So, I've re-scribbled mine:
SELECT usr
FROM (
SELECT DISTINCT usr, val, COUNT(DISTINCT val) OVER (PARTITION BY usr) cnt
FROM gab
)
WHERE val IN (1, 5, 7)
AND cnt = 3
GROUP BY
usr
, cnt
HAVING COUNT(*) = cnt
/HTH, -- Vladimir Begun The statements and opinions expressed here are my own and do not necessarily represent those of Oracle Corporation.
Jacques Kilchoer wrote:
Mr. Begun: I'm not convinced that your answer is quite the right one.
I tried
INSERT INTO gab VALUES ('GAP', 9) ;
and then this query
SELECT usr
FROM (
SELECT DISTINCT usr, val FROM gab
)
WHERE val IN (1, 5, 7)
GROUP BY
usr
HAVING COUNT(*) = 3 -- number of elements in the list
/
returned the value 'GAP' even though 'GAP' has 4 "val"s in the table.
The HAVING COUNT (*) = should also match the number of distinct rows for usr.
-- Please see the official ORACLE-L FAQ: http://www.orafaq.net -- Author: Vladimir Begun INET: [EMAIL PROTECTED]
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