Gabriel,
How about this untested code?
Alan.
select
usr
from
(
select
usr,
sum(decode(val,1,1,0)) look1, -- flag for 1
sum(decode(val,5,5,0)) look2, -- flag for 5
sum(decode(val,7,7,0)) look3, -- flag for 7
sum(decode(val,1,0,5,0,7,0,1)) look4 -- flag for others
from the_table
group by usr
)
where
look1 = 1 AND
look2 = 1 AND
look3 = 1 AND
look4 = 0
/
-----Original Message-----
Sent: Thursday, November 13, 2003 2:05 PM
To: Multiple recipients of list ORACLE-L
I have a table with like this:
Usr val
----------
GAP 1
GAP 5
GAP 7
JKL 8
JKL 5
I need a query that returns the user (GAP o JKL) that
has ALL the values in a list. Example: Having the
list: 1,5,7 the result will be GAP, but with the
values 1,5 or 1,5,7,8 there will be no result.
select distinct usr
from xxx
where val = All (1,3,5)
I was trying the ALL operator but it works with part
of the list, I need the user that has (exactly) all
the values in the list. Any idea?
Maybe it's a simple solution, but after several hours
I feel blocked.
TIA
Gabriel
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