Jacques --
Huh? I thought the question was, "give me all the usrs where there exists a
record containing a 1,5, and 7". How can that return one record, when there
are two users -- and only two users -- who have the 1,5,7 combination? The
data provided shows that both GAP and GPA have a 1, 5 and 7 and that no
other users do. My query provides that answer. If that wasn't the
question, then that won't be the answer; but if it *was* the question, then
the query is correct.
HTH,
Bambi.
=====================
create table gab (usr char(3),val number);
insert into gab values ('GAP',1);
insert into gab values ('GAP',5);
insert into gab values ('GAP',5);
insert into gab values ('GAP',7);
insert into gab values ('PAG',1);
insert into gab values ('PAG',7);
insert into gab values ('PAG',2);
insert into gab values ('JKL',1);
insert into gab values ('JKL',5);
insert into gab values ('JKL',5);
insert into gab values ('GPA',1);
insert into gab values ('GPA',5);
insert into gab values ('GPA',7);
insert into gab values ('GPA',8);
select usr from gab
where val=1
intersect
select usr from gab
where val=5
intersect
select usr from gab
where val=7;
USR
---
GAP
GPA
-----Original Message-----
Sent: Friday, November 14, 2003 7:24 PM
To: Multiple recipients of list ORACLE-L
> -----Original Message-----
> Bellow, Bambi
>
> Why not do it like this...
>
> select usr from gab
> where val=1
> intersect
> select usr from gab
> where val=5
> intersect
> select usr from gab
> where val=7;
Because that way you would get the wrong answer. With the sample data as
kindly provided by Mr. Begun the correct query would return one row, but
your query returns two rows.
SQL> select * from gab ;
USR VAL
---------- ---------
GAP 1
GAP 5
GAP 5
GAP 7
PAG 1
PAG 7
PAG 2
JKL 1
JKL 5
JKL 5
GPA 1
GPA 5
GPA 7
GPA 8
14 ligne(s) sélectionnée(s).
SQL> select usr from gab
2 where val=1
3 intersect
4 select usr from gab
5 where val=5
6 intersect
7 select usr from gab
8 where val=7;
USR
----------
GAP
GPA
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