Just a guess:
select distinct
usr
from
xxx
where
(select
count(*)
from
xxx
group by Usr)
=
(select
count(*)
from
xxx
group by Usr, val)
-----Original Message-----
Sent: Thursday, November 13, 2003 3:29 PM
To: Multiple recipients of list ORACLE-L
Gabriel Aragon wrote:
>
> I have a table with like this:
>
> Usr val
> ----------
> GAP 1
> GAP 5
> GAP 7
> JKL 8
> JKL 5
>
> I need a query that returns the user (GAP o JKL) that
> has ALL the values in a list. Example: Having the
> list: 1,5,7 the result will be GAP, but with the
> values 1,5 or 1,5,7,8 there will be no result.
>
> select distinct usr
> from xxx
> where val = All (1,3,5)
>
> I was trying the ALL operator but it works with part
> of the list, I need the user that has (exactly) all
> the values in the list. Any idea?
>
> Maybe it's a simple solution, but after several hours
> I feel blocked.
>
> TIA
> Gabriel
>
select usr
from XXX
where val in (list)
group by usr
having count(*) = number of values in list
does it but assumes that (usr, val) is unique (which can be easily
worked-around :
select usr
from (select distinct usr, val
from XXX)
group by ... )
and also that you know both the list and the number of items in the
list, which looks reasonable.
If your intent is to build the queries and the list dynamically, I'd
rather suggest storing the list into a temporary table.
--
Regards,
Stephane Faroult
Oriole Software
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