Dear Joseph / All what would you sugest to do in this case. In my log file I have this:
Oct 5 11:43:42 65.113.59.250 1960: Oct 5 15:43:41.837 UTC: %VOIPAAA-5-VOIP_CALL_HISTORY: CallLegType 2, ConnectionId 2DE762A9 FC100F3F 0 841C1B4, SetupTime 15:43:26.700 UTC Sat Oct 5 2002, PeerAddress 091422594759#, PeerSubAddress , DisconnectCause 3 , DisconnectText no route to destination., ConnectTime 15:43:41.700 UTC Sat Oct 5 2002, DisconnectTime 15:43:41.700 UTC Sat Oct 5 2002, CallOrigin 1, ChargedUnits 0, InfoType 2, TransmitPackets 0, TransmitBytes 0, ReceivePackets 0, ReceiveBytes 0 But I need only this fields: 091422594759#, ConnectTime 15:43:46.330 UTC Sat Oct 5 2002, DisconnectTime 15:43:46.330 UTC Sat Oct 5 2002 Thanks From: "Joseph V Moss" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, October 15, 2002 3:56 AM Subject: Re: Log filtering > > I have a file like this > > > > aaaaaaaaaaaaa > > bbbbbbbbbbbbb > > aaaaaaaaaaaaa > > bbbbbbbbbbbbb > > > > How I can filter this file, so that all the lines containing bbbbbbbbbbbbb, were deleted. > > Is there any way to do it ? > > Thanks in advance. > > > > There are *lots* of ways to do it. Here are just three examples: > > grep -v bbbbbbbbbbbbb filename > > sed '/bbbbbbbbbbbbb/d' filename > > awk '/bbbbbbbbbbbbb/ {next} {print}' filename > > > > -- > redhat-list mailing list > unsubscribe mailto:[EMAIL PROTECTED]?subject=unsubscribe > https://listman.redhat.com/mailman/listinfo/redhat-list -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED]?subject=unsubscribe https://listman.redhat.com/mailman/listinfo/redhat-list