Assuming that is actually stored in the file as one long line, one
possibility would be:
cut -d, -f4,8,9 filename | sed 's/ PeerAddress //'
> Dear Joseph / All
> what would you sugest to do in this case. In my log file I have this:
>
> Oct 5 11:43:42 65.113.59.250 1960: Oct 5 15:43:41.837 UTC:
> %VOIPAAA-5-VOIP_CALL_HISTORY: CallLegType 2, ConnectionId 2DE762A9 FC100F3F
> 0 841C1B4, SetupTime 15:43:26.700 UTC Sat Oct 5 2002, PeerAddress
> 091422594759#, PeerSubAddress , DisconnectCause 3 , DisconnectText no
> route to destination., ConnectTime 15:43:41.700 UTC Sat Oct 5 2002,
> DisconnectTime 15:43:41.700 UTC Sat Oct 5 2002, CallOrigin 1, ChargedUnits
> 0, InfoType 2, TransmitPackets 0, TransmitBytes 0, ReceivePackets 0,
> ReceiveBytes 0
>
>
> But I need only this fields:
>
> 091422594759#, ConnectTime 15:43:46.330 UTC Sat Oct 5 2002, DisconnectTime
> 15:43:46.330 UTC Sat Oct 5 2002
>
>
>
> Thanks
>
>
> From: "Joseph V Moss" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, October 15, 2002 3:56 AM
> Subject: Re: Log filtering
>
>
> > > I have a file like this
> > >
> > > aaaaaaaaaaaaa
> > > bbbbbbbbbbbbb
> > > aaaaaaaaaaaaa
> > > bbbbbbbbbbbbb
> > >
> > > How I can filter this file, so that all the lines containing
> bbbbbbbbbbbbb, were deleted.
> > > Is there any way to do it ?
> > > Thanks in advance.
> > >
> >
> > There are *lots* of ways to do it. Here are just three examples:
> >
> > grep -v bbbbbbbbbbbbb filename
> >
> > sed '/bbbbbbbbbbbbb/d' filename
> >
> > awk '/bbbbbbbbbbbbb/ {next} {print}' filename
> >
> >
> >
> > --
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>
>
>
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