Hi Guys, I have saved a whole lot of information (about duplexers) from all the engineer's explanations here for my radio club classes. Now I don't want to change the topic, but I have one simple question to asked.
Is there a table or formula or ratio for power input to a duplexer, to the resulting output power of the said? For instance, if I put 10, 20, 50, 100 watts to the input, what should be the output, with a 50 Ohms at the load? example 10,20, 50, 100 watts in = x output @ 50 Ohms. "BASED ON A PROPERLY TUNED DUPLEXER" I think someone had a short for-instance on this, can't find it, and will like some insight on this. v44kai.....Joel. ----- Original Message ----- From: "Jeff DePolo" <[EMAIL PROTECTED]> To: <Repeater-Builder@yahoogroups.com> Sent: Wednesday, August 29, 2007 10:39 AM Subject: RE: RE: Re: Re: RE: [Repeater-Builder] Re: Duplexers >> The 300 Ohm or 50 Ohm is not part of the R in IR losses. > > No, but the Z (300 or 50 or whatever) is what determines the *I* for a > given > amount of power. The actual losses are due to that I squared, and the R > of > the conductors themselves. Z is impedance. R is resistance. > >> I think we are getting somewhat confused here,hi. > > I'm not, at least not yet, but it's still early in the day. > > --- Jeff >
