Ya, duplexers will have insertion loss. Typically you get more insertion loss with more rejection, so its a balancing act.
Insertion loss can range from .1 dB (very good) to 3 dB. Typically if I can get a duplexer to less than a dB I'm happy. *Insertion loss (dB) = 10 log ( P**IN** / P**OUT** ) * So Pout = Pin x 10^(Insertion Loss/10) So for 50 Watts: .1 dB = 48.9 Watts .3 = 46.7 .5 = 44.6 .8 = 41.6 1 = 39.7 1.2 = 37.9 1.5 = 35.4 2 = 31.5 2.5 = 28.1 3 = 25 Jesse **** On 8/29/07, skipp025 <[EMAIL PROTECTED]> wrote: > > Hi Joel, > > In the real world it depends on the duplexer type, size, quality, > operation and setup values, which may be fixed or adjustable. > > Just throwing out a generic rule of thumb... you will find many > duplexers lose about 15% to 35% of the input power. One would hope > for near zero loss but that will never happen. > > A common quality duplexer has adjustable probes or coax ports (the > name used is based on the duplexer type), which often trade what we > generic call insertion loss for increased performance. > > Loss through a duplexer is not always a linear graph of power in > vs power out. > > Just to put something out... be happy if a properly setup and > working duplexer delivers 75% to maybe 95% of the input power. > Be grateful if you receive better than 85% of the rated power. > A really "tight" duplexer might eat as much as 35% to 40% of > your input power and there are much worse possible examples. > > cheers, > s. > > > "Joel" <[EMAIL PROTECTED]> wrote: > > Is there a table or formula or ratio for power input to a duplexer, > > to the resulting output power of the said? For instance, if I put > > 10, 20, 50, 100 watts to the input, what should be the output, with > > a 50 Ohms at the load? > > > > example 10,20, 50, 100 watts in = x output @ 50 Ohms. "BASED > > ON A PROPERLY TUNED DUPLEXER" > > > > I think someone had a short for-instance on this, can't find it, > > and will like some insight on this. > > v44kai.....Joel. > > >
