More generally, in a crontab, you'll need to set both the PYTHONPATH
and give the location of the relevant Django settings.
-Ted
On Jan 17, 2010, at 8:22 PM, "eric.frederich"
wrote:
Is there some setting somewhere to set the prefix?
Can it be set via an
Hey harijay,
A little warning up front, im fairly new to django as well so if
there is some issue with my response sorry in advance.
"return HttpResponse()" actually returns just an HttpResponse
object. If you are coming from ROR its functionality is not identical to
render (which
:: bump ::
On Jan 14, 1:59 pm, "eric.frederich" wrote:
> My django urls work nicely when browsing around, clicking things, and
> when my views generate emails. They all have the appropriate prefix.
>
> In apache's conf file I have the following...
>
> WSGIScriptAlias
On Mon, Jan 18, 2010 at 8:14 AM, Malcolm Box wrote:
> On Sat, Jan 16, 2010 at 4:58 AM, Russell Keith-Magee
> wrote:
>>
>> On Sat, Jan 16, 2010 at 6:32 AM, Malcolm Box
>> wrote:
>>
>> > It seems to me that Django should
On 2010-01-16 at 14:37:38 -0800, Tomasz Zieliński wrote:
> On 16 Sty, 20:31, "Aaron C. de Bruyn" wrote:
> > Am I missing an easy way to check if an application is installed
> > so I can make decisions in a template?
>
> AFAIK there is no such feature, but I think you could
Hi i have a question about django and I am afraid it is a slighty
academic question.
I am a newbie at django and I am trying to hand off control from one
view_func1 to another function ( test code below)
I am wondering why although the aunthenticate_user function i.e the
second function returns
On Mon, Jan 18, 2010 at 12:41 AM, nameless wrote:
> Thank you for tips.
> Now I want that when an user upload an image ( through forms ), then
> it will be saved in media.example.com.
> This is the point that I don't understand :-\
>
>
Does the computer running Django have
Thank you for tips.
Now I want that when an user upload an image ( through forms ), then
it will be saved in media.example.com.
This is the point that I don't understand :-\
---
On Jan 18, 1:08 am, Malcolm Box wrote:
> On Sat, Jan 16, 2010 at 3:20 PM, nameless
Hi,
The default behaviour of FileField that causes underscores to be
appended to the file name (excluding the extension) when the desired
file name is taken does come in handy, but sometimes I would like to
overwrite the file instead of uploading a file that is given nearly
the same name. What is
if I were you,
I also will create a django command to call the utility,
it much easier that way.
-djibon-
On Mon, Jan 18, 2010 at 7:20 AM, nek4life wrote:
> On Jan 17, 4:58 pm, lance wrote:
>> Python/Django newbie question:
>>
>> I need to create a cron
On Jan 17, 4:58 pm, lance wrote:
> Python/Django newbie question:
>
> I need to create a cron job that fetches json data from a URL, parses
> it (presumably using simplejson) and then load the data into my
> database using the Django models I've defined.
>
> I'm having trouble
On Sat, Jan 16, 2010 at 4:58 AM, Russell Keith-Magee wrote:
> On Sat, Jan 16, 2010 at 6:32 AM, Malcolm Box
> wrote:
>
> > It seems to me that Django should process POST and PUT requests the same
> -
> > i.e. the request.FILES attribute should be
On Sat, Jan 16, 2010 at 3:20 PM, nameless wrote:
> I have a site developed with django at www.example.com
>
> I want that django insert/serve static files ( images, css, js, ect )
> in/from media.example.com.
>
>
Are these files that Django is managing (e.g. via an
On Sat, Jan 16, 2010 at 7:56 PM, Praveen wrote:
You seem to have forgotten to ask a question, provide an answer or start a
thread of conversation.
Malcolm
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2010/1/16 Détour Olivier :
> Hi,
> I would create my own auth backend. I tried to understand and trace
> source code.
> I want to create an internal DB with SHA1 and username.
> But I cannot login, Django says me I do not set DB ENGINE. I would not
> use something like
Thanks fantastic thank you
I was also able to do:
result = obj.task_set.aggregate(Count('id'))['id__count']
to get the a count of the tasks for quote
I don't suppose you know any good books regarding Python/Django that I
could buy to help me learn the syntax better?
Many thanks
On Jan 17, 10:15
On Jan 17, 8:28 pm, pfwd wrote:
> Hi am very new to Django/Python and I need some help with a model
> method
>
> I have two tables Linked by a foreign key and their forms are embedded
> in the admin interface.
> One table is called Quote and one table is called Task. The
Python/Django newbie question:
I need to create a cron job that fetches json data from a URL, parses
it (presumably using simplejson) and then load the data into my
database using the Django models I've defined.
I'm having trouble finding any tips, examples, or documentation on how
to do this...
Hi everyone,
I have something that works, but I'm guessing it's *very* inefficient,
I'm guessing that nested for-loops for two layers of many to many
fields is bad, but how could I go about this better?
The aim is for my admin users to fill in the sub-categories (classes),
and for the system to
Fantastic, thank you :)
On Jan 16, 9:02 pm, Tomasz Zieliński
wrote:
> On 16 Sty, 06:15, Kieran Brownlees wrote:
>
> > Firstly thank you, secondly, how to get around it? I assume I need to
> > force a commit for the transaction my thread is
Hi am very new to Django/Python and I need some help with a model
method
I have two tables Linked by a foreign key and their forms are embedded
in the admin interface.
One table is called Quote and one table is called Task. The task table
has a field called time_taken
In the Quote list I want to
On 16 Jan, 23:05, "pjrhar...@gmail.com" wrote:
> It's not as bad as you fear! Just escape it, then apply your filter,
> then mark it all safe.
Genius! This is so obvious in hindsight. Much better than all of the
outrageously complicated possible solutions I have been going
> I am putting same pattern because both tellfriend and hero belongs to
> same template.
>
> refer template has two form.
Okay, so want to display two forms on one template and want some logic
that depends on which of the two "Submit" buttons the user pressed. Is
that assumption right?
urls.py
The urls define wich views should be executed when the user access an
address (url).
Different urls can point to the same view.
But if you specify two different views for the same url, wich one
should be executed when the user enters that url? Django can't know.
It's invalid.
2010/1/17 Bhaskar
Thank you,
I am putting same pattern because both tellfriend and hero belongs to
same template.
refer template has two form.
Thank you
Bhaskar
On Jan 17, 11:25 am, Andreas Pfrengle wrote:
> > url(r'^member/refer/$', direct_to_template,
> > {'template':
Hello people,
How can I access the value of a form field in the template ? I'm
having
two different use cases :
- display a field value as simple text (the field is not meant to be
edited
by the user, therefore i don't want to use a input field)
- use the field value for generating a link
(
Alessandro Ronchi wrote:
I cannot use an SMS gateway for my app (I must use a SIM and an hardware
modem).
Why? This is not a sane requirement for a web app...
Chris
--
Simplistix - Content Management, Batch Processing & Python Consulting
- http://www.simplistix.co.uk
--
You
What is the best way to debug templates when data is not showing?
Here is my problem. I'm using Google App Engine with app-engine-patch
so I realize it may not be a Django specific issue. I have one
property on a model that will not display on my template yet all the
model's other properties
> url(r'^member/refer/$', direct_to_template,
> {'template': 'member_refer.html'}, name='member_refer'),
>
> url(r'^refer/$', 'erp_site.views.tellfriend', name='tell_friend'),
> url(r'^refer/$', 'erp_site.views.hero', name='hero'),
tell_friend and hero have the same pattern r'^refer/$',
We are working on a django-project that shall support several
languages. i18n works so far, translation strings are marked, po-files
can be created and LocaleMiddleware is also installed. We've decided
to start with German as default locale (so all translation strings in
python code and templates
For a multilingual project, I have a ChoiceField and want to display
the choices in alphabetical order - according to the current language.
Example:
choices = ((1, _('Some choice')), (2, _('Another choice')), (3, _('One
more choice')))
In English it should be ordered 'Another choice', 'One more
You could try
myDevices = Device.objects.filter(group__in=groups)
see:
http://docs.djangoproject.com/en/1.1/ref/models/querysets/#in
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Your urls.py needs to contain sth. like that:
urlpatterns = patterns('your_app.views',
url(r'^the_url_you_want_for_tellfriend$', 'name_of_viewfunction',
name='tellfriend'),
)
the last argument, name='tellfriend', is what the {% url %} tag is
searching for in your urlpatterns, and
hi i ve heard you can provide with free django hosting
http://www.jjude.com/2008/06/10/a-free-but-superb-django-hosting/
if this service is still actual
can i afford torequest one account provided by you?
for the Django-based cms delopment and testing
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many thanks in advance and best regards
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I have this query:
myDevices=Device.objects.filter(group=groups)
where groups is a list. What I want is get all the devices that is in
one of the groups in the list groups. If group only has one element,
everything goes as expected. But if groups has more than one element,
which is often the
You are in for a treat my friend. I will say that my short 4 or 5
encounters with Joomla were the reason took up django. I had never
seen a line of python code in my life, but I was so thoroughly
frustrated and irritated with Joomla that I took up a new language so
I could use django.
The good
Thank you Lan, I am pretty new to the Django.
How do I know its needs an argument? which file will have that, is
that in URL.py?
On Jan 17, 12:30 am, Ian Lewis wrote:
> Bhaskar,
>
> The error means that there is either no defined URL called
> 'tellfriend' or it requires
On Jan 17, 3:44 am, AlK wrote:
> Hi !
>
> I developed a small Website querying some other sites in background
> like a "cron". The queries are handled in a separate thread that I can
> start and stop when I want from a simple web-interface. It works great
> on my
When editing an object using ModelForm, the best way I know is
def my_view(request):
obj_id = request.POST.get('obj_id', '')
old_object = MyModel.objects.get(pk=obj_id)
form = MyModelForm(request.POST, instance=old_object)
...
but I'm thinking the first two lines are a pain to
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