date:20090331


Since php_value was causing the 500, perhaps you should try
restoring the .htaccess files to the ones from the old server (but
without the php_value naturally).

The 1.1 files have to be downloaded from the svn repository afaik.
https://trac.cakephp.org/browser/branches/1.1.x.x
You can open each .htaccess file and choose download.. ( centered
at the bottom of the while space) or download the whole thing as an
archive.

If the standard files don't work could you perhaps detail the folder
structure you have on the server now? Which folder is the apache
document root (aka public_html) and where all the Cake-related folders
are in relation to that.

The standard production deploy is to have the document root point to
webroot. On shared hosts this will usually be a bit tricky and involve
rearranging the folder a bit and making configurations to match.

Folder structure can be seen at (half way down)
http://book.cakephp.org/view/308/Installing-CakePHP


Or, if you are in a trusting mood, send me some login-info in an email
and I'll have a quick look. I have installed 1.1 apps on a number of
servers so I might see the problem immediately and know the magic
trick. I am a pretty trustworthy guy... as long as I get my cup of
coffee ;)

/Martin


On Mar 31, 10:04 am, jmdesign webmas...@jmdesignsolutions.com wrote:
 Hi Jon,

 Okay I'll try downloading the 1.1 htaccess files, stupid question but
 where do I get them from? I can only see the 1.2 download links on the
 main Cake site?

 The only log files I've got access to are the standard erorr logs
 which aren't picking up anything now.

 Thanks,

 James
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Re: How to silently redirects to login page ?

2009-03-31 Thread burzum


$this-Auth-authError = null?

But in my opinion its a real bad idea to redirect an already logged in
(!) user to a login again. That will look to the user like the app is
acting wrong and is confusing. If hes logged in but not allowed to
access a certain area he should get a notice that can't be overlooked
displayed telling him Sorry, you dont have permissions to access this
area!.

I would do a check if the user is logged in, change the AuthError
message in this case and redirect him back to the page from where he
came.

On Mar 30, 9:28 pm, iFeghali igor.fegh...@gmail.com wrote:
 Hi Martin,

 Yes I am talking exactly about that message. Changing it the way you
 suggest would make it very weird to users already logged in that are
 trying to access resources they are not allowed to. Also, I would like
 to have no message at all... just the login form.

 Thank you.

 On 30 mar, 15:28, Martin Westin martin.westin...@gmail.com wrote:



  That would be the authError message you are seeing.

  You can set it (from AppController::beforeFilter for example) like
  this:

  $this-Auth-authError = 'Hi, and welcome. Please login before
  proceeding.';
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Re: How to silently redirects to login page ?



Since you only mentioned a problem on the index page I did not go
into anything more complicated.

You can either remove it from the session before displaying the login
screen. Then it will pop up anywhere else.

Alternatively you can make an if-clause:
if ( $this-Auth-user() ) {
 // user is logged in show error message if needed
$this-Auth-authError = 'Hey, be nice, only admins can do that';
} else {
// no user logged in, show nice message
$this-Auth-authError = 'Hi, and welcome. Please login before
proceeding.';
}

... or something similar.


On Mar 30, 9:28 pm, iFeghali igor.fegh...@gmail.com wrote:
 Hi Martin,

 Yes I am talking exactly about that message. Changing it the way you
 suggest would make it very weird to users already logged in that are
 trying to access resources they are not allowed to. Also, I would like
 to have no message at all... just the login form.

 Thank you.

 On 30 mar, 15:28, Martin Westin martin.westin...@gmail.com wrote:

  That would be the authError message you are seeing.

  You can set it (from AppController::beforeFilter for example) like
  this:

  $this-Auth-authError = 'Hi, and welcome. Please login before
  proceeding.';
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Re: Hosting Migration Problem - The requested address was not found on this server

2009-03-31 Thread jmdesign


Hi Martin,

Thanks for your offer, email on it's way to you.

James
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I need to compare how I work to how you work

2009-03-31 Thread Delirium tremens


Hi!

Once, I created a topic here, asking for help, then I got one reply.
Unfortunately, it was not enough help to solve the problem. I kept
posting my progress, waiting for a reply and I must have posted three
times, but I waited days to get one reply again. Fortunately, It was
enough help to solve the problem.

I am afraid of waiting. Regarding waiting...

Before waiting: how much do you google? While you are waiting: do you
keep trying to solve the problem yourself? or other problems in your
project? or other people's problems (in message boards, in chat rooms
etc)? how often do you check your inbox for a reply? After waiting: do
you work around? or delay? or quit?

How dependent / independent are you? How I can I be more like you???

Thanks!
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Re: Webroot problem when accessing cake app through service provider's SSL

2009-03-31 Thread karma


Thanks for your help!

I still can't get it to work however. I tried any possible settings in
the .htaccess.

The problem is that cake defines the webroot directory in views as /
ssl/application_name/ when it shoud be because of the SSL /
thesite.com/application_name/.

Because that directory is set wrong all includes (css, javascript) and
form actions point to that wrong directory. Where does cake get this
directory? It can be echoed in a view (echo $this-webroot). Is there
some setting where I can change this value?



On Mar 30, 3:45 pm, Martin Westin martin.westin...@gmail.com wrote:
 Just guessing but try this:

 http://book.cakephp.org/view/37/Apache-and-mod_rewrite-and-htaccess

 The last part about setups that have already been rewritten. Your
 provider might be using mod_rewrite for it's ssl urls and then Cake's
 rewriting will not work as expected.

 /Martin

 On Mar 29, 8:02 pm, karma karma@gmail.com wrote:

  Hi!

  I have a problem getting cakephp to set correct webroot directory.
  I've the webroot installed in /ssl/application_name
  /webroot folder at the service providers server. The application
  works perfectly when I access it through
  www.thesite.com/ssl/application_name.

  BUT

  The service provider offers SSL-encryption through this centered
  service, where the site is accessed through address https://
  ssl.serviceprovider.com/thesite.com/application_name/. This messes
  the application up cause the webroot is not set correctly. I tried to
  change WWW_ROOT constant but it doesn't help. If I echo $this-webroot
  in a view it says /ssl/application_name/. I need to get this
  application to work through this centered SSL.

  So, how could I get the application work correctly in this kind of a
  setup? I'm in quite a hurry to get this to work so any help is
  appreciated!
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Re: How to silently redirects to login page ?


I misunderstood you!

My solution is to use a route, defined as:

   Router::connect('/', array('controller' = 'users', 'action' =
'logout'));

in my routes.php, thus any access at the root gives me the login form
using the users controllers logout function, which contains only:

  $this-Session-destroy();
  $this-redirect($this-Auth-logout());

Thus producing no message upon showing the login form!

On the other hand, if the visitor tries to reach for example /requests/
index, the auth correctly directs the user to the login form, with a
message to login first!

Enjoy,
   John

On Mar 30, 10:25 pm, iFeghali igor.fegh...@gmail.com wrote:
 Hello John,

 Thanks for the answer but I don't see how it could help me. Can you
 please clarify ?

 On 30 mar, 15:13, John Andersen j.andersen...@gmail.com wrote:

  Use thishttp://book.cakephp.org/view/385/logoutasthe redirect!
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Re: Querying / filtering an array done by find('threaded')

2009-03-31 Thread toka...@gmail.com


Okay, I got it!! I don't know if there is some Cake's better solution
but this works fine for me
I have made my own function that goes trough the whole threaded array
and extracts childs for top level section specified by ID.

/**
 * Extracts child node(s) for specific top level section id
 *
 * @param $Sections - an array outputed from $this-Section-find
('threaded');  Includes all branches generated with nested arrays.
 * @param $id - id of the top level section whose childs will be
returned
 * @return an array of childs of section specified
 */
function getSectionChilds($Sections, $id){

foreach($Sections as $Section)
{
  if( $Section['Section']['id'] == $id ) return $Section
['children'];
}
return false;
}


On Mar 30, 8:39 pm, toka...@gmail.com toka...@gmail.com wrote:
 I have tried also $this-Section-children($id), that seems to be ok,
 but it doesnt generate such nice nested structure like find
 ('threaded').  Is there any change to filter threaded array similar
 way like getting childs from the tree? Tnkx Tomas
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Re: Webroot problem when accessing cake app through service provider's SSL

2009-03-31 Thread karma


I can get the system to work with a VERY ugly fix:

In layout if i replace these:

echo $html-css('cake.generic');  = echo preg_replace( /ssl/,
thesite.com, $html-css('cake.generic') );
echo $content_for_layout; = echo preg_replace( /ssl/,
thesite.com, $content_for_layout );
etc.

But I really don't like doing it like this. If anyone has a better
suggestion please tell me!

On Mar 31, 12:37 pm, karma karma@gmail.com wrote:
 Thanks for your help!

 I still can't get it to work however. I tried any possible settings in
 the .htaccess.

 The problem is that cake defines the webroot directory in views as /
 ssl/application_name/ when it shoud be because of the SSL /
 thesite.com/application_name/.

 Because that directory is set wrong all includes (css, javascript) and
 form actions point to that wrong directory. Where does cake get this
 directory? It can be echoed in a view (echo $this-webroot). Is there
 some setting where I can change this value?

 On Mar 30, 3:45 pm, Martin Westin martin.westin...@gmail.com wrote:

  Just guessing but try this:

 http://book.cakephp.org/view/37/Apache-and-mod_rewrite-and-htaccess

  The last part about setups that have already been rewritten. Your
  provider might be using mod_rewrite for it's ssl urls and then Cake's
  rewriting will not work as expected.

  /Martin

  On Mar 29, 8:02 pm, karma karma@gmail.com wrote:

   Hi!

   I have a problem getting cakephp to set correct webroot directory.
   I've the webroot installed in /ssl/application_name
   /webroot folder at the service providers server. The application
   works perfectly when I access it through
   www.thesite.com/ssl/application_name.

   BUT

   The service provider offers SSL-encryption through this centered
   service, where the site is accessed through address https://
   ssl.serviceprovider.com/thesite.com/application_name/. This messes
   the application up cause the webroot is not set correctly. I tried to
   change WWW_ROOT constant but it doesn't help. If I echo $this-webroot
   in a view it says /ssl/application_name/. I need to get this
   application to work through this centered SSL.

   So, how could I get the application work correctly in this kind of a
   setup? I'm in quite a hurry to get this to work so any help is
   appreciated!
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Double left join?

2009-03-31 Thread Richard


Hi,

I'm fairly new to CakePHP so if this is a stupid mistake forgive me.

A user will post a complaint against a company, so the complaint table
has company_id. I use a left join to get the company data. Then the
company has a field category_id which is simply the industry of the
company (categories have id / name). When I load a complaint I want to
grab the category name. I manage to get the category ID but cannot do
another left join within this left join.

Hope this makes sense.

At the moment I have;
company.php
var $belongsTo = array('Category');

category.php
var $hasMany = array('Company');

complaint.php
var $belongsTo = array('Company', 'User');


view/complaints/view.thtml
echo $complaint['Company']['category_id']

which i want it to grab Category.name

Appreciate any help.

Thanks.
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Re: Adding/Deleting HABTM on existing records

2009-03-31 Thread mscdex


For deleting, you can use the model function deleteAll to remove
directly from the join table, as long as you know both IDs. Example
(if you haven't specified a different join model name):

$this-Question-GamesQuestion-deleteAll(array('question_id' =
$q_id, 'game_id' = $g_id), false);

Where $q_id is the Question ID and the $g_id is the Game ID.
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Re: Hosting Migration Problem - The requested address was not found on this server


For public knowlegde in case anyone does a search for similar
problems:

The problem jmdesign was experiencing was dure to a missing
RewriteBase since the website was hosted under a user account.
( www.example.com/~username/ )
Setting the RewriteBase to /~username/ in both the cake root folder (=
public_html) and app/webroot/ brought the app back to life.

/Martin


On Mar 31, 11:02 am, jmdesign webmas...@jmdesignsolutions.com wrote:
 Hi Martin,

 Thanks for your offer, email on it's way to you.

 James
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Re: I need to compare how I work to how you work



The thing with Google Groups is that it is a mailing list that many
people access like a forum... I think people don't page back to
yesterday and read every message since their last login as many do
in forums. I know I don't.

This is a debated god / bad aspect of the group.

The time and day you post a problem greatly affect the number of
people reading it. It is mid-day for me here in Sweden right now and
if you had posted 5-6 hours later I would never have seen your
message.

I loosely follow this path most of the time:

Search the google group.
Search Google.
Ask the google group.
Search the core test-cases. (these are a very good source of knowledge
at times)
Start reading the source of related core-files (if I have a bug or
strange behaviour)
Check for an answer.
Update question with my current findings from the core
Ask on irc sometimes (I'm not a big chatter-bug but there are some
nice helpful people there... in realtime!)
Workaround the problem or post a ticket if I think I really found a
bug... which is very rare.


I rarely do all of it and most often I find the answer on the top
three steps. But I always keep playing around on my own while I wait
or if I am really stuck work on some other part of my application for
a while. I have also been known to ask my question again after a day
or two of silence.


/Martin



On Mar 31, 11:27 am, Delirium tremens pedbe...@gmail.com wrote:
 Hi!

 Once, I created a topic here, asking for help, then I got one reply.
 Unfortunately, it was not enough help to solve the problem. I kept
 posting my progress, waiting for a reply and I must have posted three
 times, but I waited days to get one reply again. Fortunately, It was
 enough help to solve the problem.

 I am afraid of waiting. Regarding waiting...

 Before waiting: how much do you google? While you are waiting: do you
 keep trying to solve the problem yourself? or other problems in your
 project? or other people's problems (in message boards, in chat rooms
 etc)? how often do you check your inbox for a reply? After waiting: do
 you work around? or delay? or quit?

 How dependent / independent are you? How I can I be more like you???

 Thanks!
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Re: media view and files on the fly



I have so far lest MediaView alone and gone a different way for
fake, dynamic, files.

I have made use of parseExtensions to output files. The examples
mostly show rss feeds but you can just as easily use it to generate an
Excel sheet full of statistics about something on your site or any
other dynamic output.

/Martin


On Mar 30, 7:05 pm, Mark (Germany) dereurom...@googlemail.com
wrote:
 i tried to use the media view for files generated on the fly (some
 exported text inside a export.txt or whatever)
 but it seems like the media view can only handle downloads of
 existing files on the server

 trying to rewrite it did not turn out very well
 so, did anyone manage to create a txt file to download, that is filled
 with the echoed content

 echo 'blabla'
 or
 $content = 'blabla' transfered to the media view

 without creating locale (temp.) files on the server?
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Re: How to silently redirects to login page ?

2009-03-31 Thread iFeghali


Hello All,

Many thanks for the help so far. Let's try to be a bit more clear...
that's my scenario:

1) only authenticated users have access to the site (but the login
form, of course)

for a visitor (non auth user):
2) example.com should redirect to example.com/users/login with no
error message at all
3) example.com/anything should redirect to example.com/users/login
with no error message at all, and them redirect the user to /anything
after logging in
4) providing the wrong credentials should pop up an error message

for an authenticated user:
5) example.com should redirect to example.com/foo/index
6) trying to access a resource denied to this user should get him the
authError (but no login form, clear now burzum?)

So far I have 1, 3, 4, 5 and 6 working fine. But I couldn't think of a
way to implement (2) without breaking one of the others. Currently
root (/) routes to /foo/index and I would prefer to keep it this
way. Routing / to /users/login would bring (2) but break (5).
Routing / to /users/login *and* finding a way to redirect the path
to /foo/index inside the users controller sounds an ugly hack that i
would like to avoid. Any more ideas left ?

Thank you.
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Re: Adding/Deleting HABTM on existing records

2009-03-31 Thread RyOnLife


That's how I handle my deletes.

If you don't want to read the existing relationships before your save
(meaning you don't want Cake to delete existing relationships before
inserting new ones), in the models where you define the HABTM
associations, set the 'unique' array key to 'false' and you'll no
longer need to re-pass them.

On Mar 31, 7:09 am, mscdex msc...@gmail.com wrote:
 For deleting, you can use the model function deleteAll to remove
 directly from the join table, as long as you know both IDs. Example
 (if you haven't specified a different join model name):

 $this-Question-GamesQuestion-deleteAll(array('question_id' =
 $q_id, 'game_id' = $g_id), false);

 Where $q_id is the Question ID and the $g_id is the Game ID.
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Re: I need to compare how I work to how you work

2009-03-31 Thread Delirium tremens


omg Martin, I am relieved! Sometimes, my posts don't make sense or ask
too much or nobody finds interesting (or like you said are asked at
the wrong time) or whatever, but I know from your post that this time
it went alright!!!

By the way, there is a link to reply to author... should I use it AND
use the link to just reply?

I had made a list of places where I can get help, but had not used it.
Maybe, one or two itens in the list are new to you. Check it out!

1 Cookbook - http://book.cakephp.org/
2 Bakery - http://bakery.cakephp.org/
3 CakeForge- http://www.cakeforge.org/
4 API - http://api.cakephp.org/1.2
5 Test Cases - http://api.cakephp.org/tests
6 Wiki - https://trac.cakephp.org/
7 FAQ - http://groups.google.com/group/cake-php/web/faq

On 31 mar, 08:41, Martin Westin martin.westin...@gmail.com wrote:
 The thing with Google Groups is that it is a mailing list that many
 people access like a forum... I think people don't page back to
 yesterday and read every message since their last login as many do
 in forums. I know I don't.

 This is a debated god / bad aspect of the group.

 The time and day you post a problem greatly affect the number of
 people reading it. It is mid-day for me here in Sweden right now and
 if you had posted 5-6 hours later I would never have seen your
 message.

 I loosely follow this path most of the time:

 Search the google group.
 Search Google.
 Ask the google group.
 Search the core test-cases. (these are a very good source of knowledge
 at times)
 Start reading the source of related core-files (if I have a bug or
 strange behaviour)
 Check for an answer.
 Update question with my current findings from the core
 Ask on irc sometimes (I'm not a big chatter-bug but there are some
 nice helpful people there... in realtime!)
 Workaround the problem or post a ticket if I think I really found a
 bug... which is very rare.

 I rarely do all of it and most often I find the answer on the top
 three steps. But I always keep playing around on my own while I wait
 or if I am really stuck work on some other part of my application for
 a while. I have also been known to ask my question again after a day
 or two of silence.

 /Martin

 On Mar 31, 11:27 am, Delirium tremens pedbe...@gmail.com wrote:

  Hi!

  Once, I created a topic here, asking for help, then I got one reply.
  Unfortunately, it was not enough help to solve the problem. I kept
  posting my progress, waiting for a reply and I must have posted three
  times, but I waited days to get one reply again. Fortunately, It was
  enough help to solve the problem.

  I am afraid of waiting. Regarding waiting...

  Before waiting: how much do you google? While you are waiting: do you
  keep trying to solve the problem yourself? or other problems in your
  project? or other people's problems (in message boards, in chat rooms
  etc)? how often do you check your inbox for a reply? After waiting: do
  you work around? or delay? or quit?

  How dependent / independent are you? How I can I be more like you???

  Thanks!
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Re: How to silently redirects to login page ?


In your case I would change your route / as I specified earlier and
in the app_controller-beforeFilter function, add:

  $this-Auth-loginRedirect = array('controller' = 'foo',
'action' = 'index');

Thus when a user provides a valid login, the user is automatically
directed to /foo/index
Enjoy,
   John


On Mar 31, 3:13 pm, iFeghali igor.fegh...@gmail.com wrote:
 Hello All,

 Many thanks for the help so far. Let's try to be a bit more clear...
 that's my scenario:

 1) only authenticated users have access to the site (but the login
 form, of course)

 for a visitor (non auth user):
 2) example.com should redirect to example.com/users/login with no
 error message at all
 3) example.com/anything should redirect to example.com/users/login
 with no error message at all, and them redirect the user to /anything
 after logging in
 4) providing the wrong credentials should pop up an error message

 for an authenticated user:
 5) example.com should redirect to example.com/foo/index
 6) trying to access a resource denied to this user should get him the
 authError (but no login form, clear now burzum?)

 So far I have 1, 3, 4, 5 and 6 working fine. But I couldn't think of a
 way to implement (2) without breaking one of the others. Currently
 root (/) routes to /foo/index and I would prefer to keep it this
 way. Routing / to /users/login would bring (2) but break (5).
 Routing / to /users/login *and* finding a way to redirect the path
 to /foo/index inside the users controller sounds an ugly hack that i
 would like to avoid. Any more ideas left ?

 Thank you.
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Re: How to silently redirects to login page ?


By the way, you probably have to add the following in the
app_controller-beforeFilter in order to ensure that the user has
access to the logout action :)

  $this-Auth-allow('logout');

Enjoy,
   John

On Mar 31, 3:13 pm, iFeghali igor.fegh...@gmail.com wrote:
 Hello All,

 Many thanks for the help so far. Let's try to be a bit more clear...
 that's my scenario:

 1) only authenticated users have access to the site (but the login
 form, of course)

 for a visitor (non auth user):
 2) example.com should redirect to example.com/users/login with no
 error message at all
 3) example.com/anything should redirect to example.com/users/login
 with no error message at all, and them redirect the user to /anything
 after logging in
 4) providing the wrong credentials should pop up an error message

 for an authenticated user:
 5) example.com should redirect to example.com/foo/index
 6) trying to access a resource denied to this user should get him the
 authError (but no login form, clear now burzum?)

 So far I have 1, 3, 4, 5 and 6 working fine. But I couldn't think of a
 way to implement (2) without breaking one of the others. Currently
 root (/) routes to /foo/index and I would prefer to keep it this
 way. Routing / to /users/login would bring (2) but break (5).
 Routing / to /users/login *and* finding a way to redirect the path
 to /foo/index inside the users controller sounds an ugly hack that i
 would like to avoid. Any more ideas left ?

 Thank you.
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Re: media view and files on the fly

2009-03-31 Thread Matt Curry


I had to do this with pdf/xls files returned by a webservice.  I took
the default media view (/cake/libs/views/media.php) and copied it to /
app/views/app_media.php.

Then I modified it so that it checked for a $content view var and
wrote that to a tmpfile.
Here's the diff:
http://bin.cakephp.org/view/1310700342

-Matt
http://www.pseudocoder.com

On Mar 30, 1:05 pm, Mark (Germany) dereurom...@googlemail.com
wrote:
 i tried to use the media view for files generated on the fly (some
 exported text inside a export.txt or whatever)
 but it seems like the media view can only handle downloads of
 existing files on the server

 trying to rewrite it did not turn out very well
 so, did anyone manage to create a txt file to download, that is filled
 with the echoed content

 echo 'blabla'
 or
 $content = 'blabla' transfered to the media view

 without creating locale (temp.) files on the server?
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Does anybody know how can I limit the join table fields when I user joins condition?

2009-03-31 Thread joshua

For example:
One task has many users.

$condition = array();
$condition['joins'] = array(
array(
'table' = 'users',
'alias' = 'User',
'type' = 'inner',
'foreignKey' = 'user_id',
'conditions'= array('User.id =
Task.user_id','User.deleted=0')
));

I just want to find the user name , not all the fields in User table. I try
to add the 'fields' property in this array, but it seems not.
-- 
Thanks
Joshua

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Re: Does anybody know how can I limit the join table fields when I user joins condition?

2009-03-31 Thread francky06l


Use the 'fields' options for your field and add 'User.name' in it
maybe ?

hth

On Mar 31, 3:28 pm, joshua josh...@gmail.com wrote:
 For example:
 One task has many users.
 
         $condition = array();
         $condition['joins'] = array(
             array(
                 'table' = 'users',
                 'alias' = 'User',
                 'type' = 'inner',
                 'foreignKey' = 'user_id',
                 'conditions'= array('User.id =
 Task.user_id','User.deleted=0')
         ));
 
 I just want to find the user name , not all the fields in User table. I try
 to add the 'fields' property in this array, but it seems not.
 --
 Thanks
 Joshua
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turning on/off query that shows at the end of each page?

2009-03-31 Thread Sajid.bd


Hello I am learning cake.Can anyone help me how to turn on/off the
query that shows at the end of each page?

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Re: Why is it so hard to find answers on cakephp trouble?

2009-03-31 Thread Steven


I think the documentation in the most part is OK, but in some areas it
lacks complete explanation. For me an example of this is the ACL
documentation, it actually starts off really well and explains in
enough detail, what ACL is all about ACOS/AROS, how to get it set up,
implement it into your models etc etc. But it does not spend enough
time explaining the best practices when it comes to actually blocking
people from getting to certain areas.

It caused me a lot of confusion because I ended up Googling for an
answer, and everywhere had differing ways of implementing it.

That has been my biggest gripe with the documentation so far.

One thing I would like to see, similar to the php documentation, is
where users can post examples of using the code in comments.

Just my 2 cents

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how to use other SQL expressions like where field_name in(x,y,z)

2009-03-31 Thread rwolverine


Thanks in advance for any help provided. Apologies for no code blocks.

I want to write my find such that it can construct a query like:

SELECT `ReviewerActivityStatus`.`id`,
`ReviewerActivityStatus`.`reviewer_id`,
`ReviewerActivityStatus`.`date`, `ReviewerActivityStatus`.`status`,
`ReviewerActivityStatus`.`comment`, `Reviewer`.`id`,
`Reviewer`.`briefing_id` FROM `reviewer_activity_statuses` AS
`ReviewerActivityStatus` LEFT JOIN `reviewers` AS `Reviewer` ON
(`ReviewerActivityStatus`.`reviewer_id` = `Reviewer`.`id`) WHERE
`reviewer_id` in (6,8) AND `status` = 1


Notice no single quotes in the parenthesis of the in clause...

But when I do:

$result = $this-ReviewerActivityStatus-find('all',array
('conditions'=array('reviewer_id IN (?)'=$keys,'status'='1')));

it constructs the following:

SELECT `ReviewerActivityStatus`.`id`,
`ReviewerActivityStatus`.`reviewer_id`,
`ReviewerActivityStatus`.`date`, `ReviewerActivityStatus`.`status`,
`ReviewerActivityStatus`.`comment`, `Reviewer`.`id`,
`Reviewer`.`briefing_id` FROM `reviewer_activity_statuses` AS
`ReviewerActivityStatus` LEFT JOIN `reviewers` AS `Reviewer` ON
(`ReviewerActivityStatus`.`reviewer_id` = `Reviewer`.`id`) WHERE
`reviewer_id` in ('6,8') AND `status` = 1

Notice the single quotes in the parenthesis of the in clause around
the value for $key which is just a string.

My whole code looks like:

function checkApprovalStatus($reviewerid = null) {
echo(!--);
//we can find out the briefing ID from the reviewer table, 
check it
first
$result = $this-Reviewers-find('all',array('conditions'=array
('id'=$reviewerid)));
//find the other reviewers with the same briefing id
$briefing_id = $result[0]['Reviewers']['briefing_id'];
$result = $this-Reviewers-find('all',array('conditions'=array
('briefing_id'=$briefing_id),'order'='id ASC'));
$reviwercount = count($result);
$keys = ;
foreach($result as $reviewers)
{
$keys .= $reviewers['Reviewers']['id']., ;
}
$keys = substr_replace($keys,,-2);
//now let's find these reviewers and if they have a
record with a status value of 1
$result = $this-ReviewerActivityStatus-find('all',array
('conditions'=array('reviewer_id IN (?)'=$keys,'status'='1')));

$approvalcount = count($result);
//if there were as many approvals as reviewers, update the 
briefing
status field
echo(reviwer and approval counts: $reviwercount == 
$approvalcount\r
\n);
if($reviwercount == $approvalcount)
{
echo('updating the briefing');
//find the briefing record
$data = 
$this-Briefing-find('all',array('conditions'=array('id'=
$briefing_id)));
var_dump($data);
   //TODO: modify the resulting array and save it.
}
echo(--);
}

Again thanks for any replies!

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safe_mode install impossible

2009-03-31 Thread almasty


I've installed cake_1.2.2.8120 on my server and am happily developing
with it. It's really is very neat.

However, can an install be done using the advanced pattern i.e. the
cake lib folder resides outside the root in a common area for any web
user on a shared server to use?

I tried but could not get it to work.

The files are in /usr/local/cake_1.2.2.8120/cake.

With safe_mode off and the correct entry in include_path and
open_basedir install is a snap. With safe_mode on it does not matter
what I try and use (safe_mode_include_dir included) I cannot access
the shared lib in /usr/local/cake_1.2.2.8120/cake without setting a
recursive chmod to the user AND group of a particular web site.

So if each site has it's own user for it's own web folder and root
e.g. web1, web2, web3 and they all belong to the group web_user then
to use cake's shared library for web2 it will only work with safe_mode
on if I set

chmod -R web1:web_user /usr/local/cake_1.2.2.8120

But of course web2, and web3 etc are out of luck. I have tried each
combination I can think of. Is there a template to get this done or
something obvious I am missing? Or perhaps you just cannot use CakePHP
effectively with safe_mode on?

Al

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Multiple hasMany relationships to one model?

2009-03-31 Thread Adam M


Hi All,

How can I PROPERLY set up my database so that several models have
multiple images?  Each image belongs to a particular model, so they
are definitely hasMany relationships.  Example:

Episode
-id
-name
-date

Movie
-id
-name
-date
-producer

Image
-id
-name
-caption
-path

Episode hasMany Image
Movie hasMany Image

Does the paradigm of adding a foreign key to the Image table still
apply if I have multiple hasMany relationships?  That is, would I add
multiple foreign keys to the table as follows?:
Image
-id
-movie_id
-episode_id
-name
-caption
-path

Thanks

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DebugKit's toolbar not working

2009-03-31 Thread Steven


I installed debug_kit version 1.0 into app\plugins\debug_kit, my debug
level is set to 2, and I have put:

var $components = array('DebugKit.Toolbar');

In the relevant controller. However DebugKit is displaying all its
output at the bottom of the page between my content, and the SQL
output.

I don't have scaffolding, so it can't be that, I have even updated to
the head revision from thechaw. Which made no difference.

This might make me sound stupid but I am out of ideas, I know this
primarily works through jquery, so does jquery to to be in my app
\webroot\js directory?


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Re: New Install - Where is the Dispatch

2009-03-31 Thread almasty


The set-up I had was to have the shared cake libraries in

/usr/local/cake_1.2.2.8120

I had my app folder in

/var/www/vhosts/mydomain.com/app

and my webroot in

/var/www/vhosts/mydomain.com/httpdocs

The user was mydomain:psacln

I found the `problem` was with the chmod permission in /usr/local/
cake_1.2.2.8120. If I ran

chmod -R mydomain:psacln /usr/local/cake_1.2.2.8120

The problem went away, or I found I could also just turn off
safe_mode.

However, what I want is to have safe_mode on and allow every site on
my server to have access to the shared cake lib. I cannot find the
correct combination
of permissions to do that. I've used ZEND and a few other frameworks
without trouble just by adding the shared paths to
safe_mode_include_dir but CakePHP just doesn't like that.

Help?



On Mar 28, 2:07 pm, almasty m...@shanemcgovern.com wrote:
 Hi

 I'm getting this error

 Fatal error: Class 'Dispatcher' not found in /var/www/vhosts/
 shakethembones.com/httpdocs/index.php on line 87

 I've done a search on google and can find a couple of post about
 getting this error but no solutions

 I have just installed

 I've used the instructions here

 http://book.cakephp.org/view/308/Installing-CakePHPunder `Advanced
 Setup: Alternative Installation Options`. I have the tmp dir with 777,
 and my include paths, openbase dir etc in a vhost file contain the
 cake lib, app and webroot just to take them off the radar in terms of
 permissions.

 Line 87 is a call to the Dispatcher class, which I guess is not
 included as expected.

 Can anyone point me in the right direction for an answer?

 Al

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Re: DebugKit's toolbar not working

2009-03-31 Thread Sam Sherlock

Try clearing the browsers cache - I think I to had this issue, just would
show top right

after clearing cache of ff it started.   My projects all have jquery in
them, but I believe that debugkit has contains everything it requires
(loading jquery via google api - not conclusive on that I expect I'll be
corrected soon)

But unles it was mere conincidence clear your browsers cache

- S


2009/3/31 Steven steven.beech...@gmail.com


 I installed debug_kit version 1.0 into app\plugins\debug_kit, my debug
 level is set to 2, and I have put:

 var $components = array('DebugKit.Toolbar');

 In the relevant controller. However DebugKit is displaying all its
 output at the bottom of the page between my content, and the SQL
 output.

 I don't have scaffolding, so it can't be that, I have even updated to
 the head revision from thechaw. Which made no difference.

 This might make me sound stupid but I am out of ideas, I know this
 primarily works through jquery, so does jquery to to be in my app
 \webroot\js directory?


 


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Is there an offline documentation for CakePHP?

2009-03-31 Thread Liebermann, Anja Carolin


Hello everybody,

my company will forbid access to the internet within the next days, even
for the IT department. To be able to develop with CakePHP in the future
I would like to know if there is an offline documentation for CakePHP
1.2 ( manual and/or API). Any hints to counter this madness are deeply
appreciated.

Anja

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Re: Is there an offline documentation for CakePHP?

2009-03-31 Thread Dinh Ba Thanh


You may want to save this link to your harddisk

http://book.cakephp.org/complete/3

Best Regards,
Dinh Ba Thanh, Jason
bath...@gmail.com




On Mar 31, 2009, at 10:24 PM, Liebermann, Anja Carolin wrote:


 Hello everybody,

 my company will forbid access to the internet within the next days,  
 even
 for the IT department. To be able to develop with CakePHP in the  
 future
 I would like to know if there is an offline documentation for CakePHP
 1.2 ( manual and/or API). Any hints to counter this madness are deeply
 appreciated.

 Anja

 


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Re: how to use other SQL expressions like where field_name in(x,y,z)


I believe the syntax should be:

$result = $this-ReviewerActivityStatus-find(
'all',
array(
'conditions'=array(
'reviewer_id = $keys,
'status'='1'
)
)
);

where $keys is an array.

On Tue, Mar 31, 2009 at 7:46 AM, rwolverine bwri...@abcgrp.com wrote:

 Thanks in advance for any help provided. Apologies for no code blocks.

 I want to write my find such that it can construct a query like:

 SELECT `ReviewerActivityStatus`.`id`,
 `ReviewerActivityStatus`.`reviewer_id`,
 `ReviewerActivityStatus`.`date`, `ReviewerActivityStatus`.`status`,
 `ReviewerActivityStatus`.`comment`, `Reviewer`.`id`,
 `Reviewer`.`briefing_id` FROM `reviewer_activity_statuses` AS
 `ReviewerActivityStatus` LEFT JOIN `reviewers` AS `Reviewer` ON
 (`ReviewerActivityStatus`.`reviewer_id` = `Reviewer`.`id`) WHERE
 `reviewer_id` in (6,8) AND `status` = 1


 Notice no single quotes in the parenthesis of the in clause...

 But when I do:

 $result = $this-ReviewerActivityStatus-find('all',array
 ('conditions'=array('reviewer_id IN (?)'=$keys,'status'='1')));

 it constructs the following:

 SELECT `ReviewerActivityStatus`.`id`,
 `ReviewerActivityStatus`.`reviewer_id`,
 `ReviewerActivityStatus`.`date`, `ReviewerActivityStatus`.`status`,
 `ReviewerActivityStatus`.`comment`, `Reviewer`.`id`,
 `Reviewer`.`briefing_id` FROM `reviewer_activity_statuses` AS
 `ReviewerActivityStatus` LEFT JOIN `reviewers` AS `Reviewer` ON
 (`ReviewerActivityStatus`.`reviewer_id` = `Reviewer`.`id`) WHERE
 `reviewer_id` in ('6,8') AND `status` = 1

 Notice the single quotes in the parenthesis of the in clause around
 the value for $key which is just a string.

 My whole code looks like:

        function checkApprovalStatus($reviewerid = null) {
                echo(!--);
                //we can find out the briefing ID from the reviewer table, 
 check it
 first
                $result = 
 $this-Reviewers-find('all',array('conditions'=array
 ('id'=$reviewerid)));
                //find the other reviewers with the same briefing id
                $briefing_id = $result[0]['Reviewers']['briefing_id'];
                $result = 
 $this-Reviewers-find('all',array('conditions'=array
 ('briefing_id'=$briefing_id),'order'='id ASC'));
                $reviwercount = count($result);
                $keys = ;
                foreach($result as $reviewers)
                {
                        $keys .= $reviewers['Reviewers']['id']., ;
                }
                $keys = substr_replace($keys,,-2);
                //now let's find these reviewers and if they have a
 record with a status value of 1
                $result = $this-ReviewerActivityStatus-find('all',array
 ('conditions'=array('reviewer_id IN (?)'=$keys,'status'='1')));

                $approvalcount = count($result);
                //if there were as many approvals as reviewers, update the 
 briefing
 status field
                echo(reviwer and approval counts: $reviwercount == 
 $approvalcount\r
 \n);
                if($reviwercount == $approvalcount)
                {
                        echo('updating the briefing');
                        //find the briefing record
                        $data = 
 $this-Briefing-find('all',array('conditions'=array('id'=
 $briefing_id)));
                        var_dump($data);
                       //TODO: modify the resulting array and save it.
                }
                echo(--);
        }

 Again thanks for any replies!

 


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Re: Multiple hasMany relationships to one model?


You have a couple options here. What's proper is really what works
best in your situation, so do some testing to see how the queries
perform. I had a similar situation so I'll explain what I did.

Video
- id

Episode
- video_id
- name
- date

Movie
- video_id
- name
- date
- producer

Image
- id
- name
- caption
- path
- video_id

Video hasMany Episode
Video hasMany Movie
Episode hasMany Image
Movie hasMany Image

In this design Video is the parent of Episode and Movie and generates
unique ids for them. These ids can then be added to any tables
associated to Episode or Movie. On top of that you can setup foreign
keys in MySQL so that when you delete a Video to cascades and deletes
all related data.

On Mar 31, 1:09 am, Adam M adam.mcnam...@gmail.com wrote:
 Hi All,

 How can I PROPERLY set up my database so that several models have
 multiple images?  Each image belongs to a particular model, so they
 are definitely hasMany relationships.  Example:

 Episode
 -id
 -name
 -date

 Movie
 -id
 -name
 -date
 -producer

 Image
 -id
 -name
 -caption
 -path

 Episode hasMany Image
 Movie hasMany Image

 Does the paradigm of adding a foreign key to the Image table still
 apply if I have multiple hasMany relationships?  That is, would I add
 multiple foreign keys to the table as follows?:
 Image
 -id
 -movie_id
 -episode_id
 -name
 -caption
 -path

 Thanks
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Re: Is there an offline documentation for CakePHP?


I cannot imagine trying to develop web apps without an internet
connection. There is just so much more than the Cake manual that's
required. I can deal with a brief outage, but there's no way I could
get much done without a connection *ever*.

btw, how is the IT dept. supposed to install updates, etc? Or even
know about them?

On Tue, Mar 31, 2009 at 10:24 AM, Liebermann, Anja Carolin
anja.lieberm...@alltours.de wrote:

 Hello everybody,

 my company will forbid access to the internet within the next days, even
 for the IT department. To be able to develop with CakePHP in the future
 I would like to know if there is an offline documentation for CakePHP
 1.2 ( manual and/or API). Any hints to counter this madness are deeply
 appreciated.

 Anja

 


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Re: Multiple hasMany relationships to one model?


I'd go HABTM for this, I think.

movies
videos
images
images_movies
images_videos

On Tue, Mar 31, 2009 at 2:09 AM, Adam M adam.mcnam...@gmail.com wrote:

 Hi All,

 How can I PROPERLY set up my database so that several models have
 multiple images?  Each image belongs to a particular model, so they
 are definitely hasMany relationships.  Example:

 Episode
 -id
 -name
 -date

 Movie
 -id
 -name
 -date
 -producer

 Image
 -id
 -name
 -caption
 -path

 Episode hasMany Image
 Movie hasMany Image

 Does the paradigm of adding a foreign key to the Image table still
 apply if I have multiple hasMany relationships?  That is, would I add
 multiple foreign keys to the table as follows?:
 Image
 -id
 -movie_id
 -episode_id
 -name
 -caption
 -path

 Thanks

 


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AW: Is there an offline documentation for CakePHP?

2009-03-31 Thread Liebermann, Anja Carolin


Hi Brian,

I cannot imagine it either. I just hope to survive until enough things go wrong 
and it is switched on again.

Anja

-Ursprüngliche Nachricht-
Von: cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] Im Auftrag 
von brian
Gesendet: Dienstag, 31. März 2009 16:35
An: cake-php@googlegroups.com
Betreff: Re: Is there an offline documentation for CakePHP?


I cannot imagine trying to develop web apps without an internet connection. 
There is just so much more than the Cake manual that's required. I can deal 
with a brief outage, but there's no way I could get much done without a 
connection *ever*.

btw, how is the IT dept. supposed to install updates, etc? Or even know about 
them?

On Tue, Mar 31, 2009 at 10:24 AM, Liebermann, Anja Carolin 
anja.lieberm...@alltours.de wrote:

 Hello everybody,

 my company will forbid access to the internet within the next days, 
 even for the IT department. To be able to develop with CakePHP in the 
 future I would like to know if there is an offline documentation for 
 CakePHP
 1.2 ( manual and/or API). Any hints to counter this madness are deeply 
 appreciated.

 Anja

 




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AW: Is there an offline documentation for CakePHP?

2009-03-31 Thread Liebermann, Anja Carolin


Thank you very much, that looks good!

Anja

-Ursprüngliche Nachricht-
Von: cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] Im Auftrag 
von Dinh Ba Thanh
Gesendet: Dienstag, 31. März 2009 16:26
An: cake-php@googlegroups.com
Betreff: Re: Is there an offline documentation for CakePHP?


You may want to save this link to your harddisk

http://book.cakephp.org/complete/3

Best Regards,
Dinh Ba Thanh, Jason
bath...@gmail.com




On Mar 31, 2009, at 10:24 PM, Liebermann, Anja Carolin wrote:


 Hello everybody,

 my company will forbid access to the internet within the next days, 
 even for the IT department. To be able to develop with CakePHP in the 
 future I would like to know if there is an offline documentation for 
 CakePHP
 1.2 ( manual and/or API). Any hints to counter this madness are deeply 
 appreciated.

 Anja

 




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Re: Why is it so hard to find answers on cakephp trouble?


On Tue, Mar 31, 2009 at 8:34 AM, Steven steven.beech...@gmail.com wrote:

 I think the documentation in the most part is OK, but in some areas it
 lacks complete explanation. For me an example of this is the ACL
 documentation, it actually starts off really well and explains in
 enough detail, what ACL is all about ACOS/AROS, how to get it set up,
 implement it into your models etc etc. But it does not spend enough
 time explaining the best practices when it comes to actually blocking
 people from getting to certain areas.

This is precisely the situation I'm in right now. While the setup has
been a real bear to figure out, I think I'm on the right track now.
But I'm still having some difficulty figuring out how to *use* ACL.

 It caused me a lot of confusion because I ended up Googling for an
 answer, and everywhere had differing ways of implementing it.

Ditto, again. I've seen a lot of implementations but much of it seems
incompatible. I think.

I'm thankful that so many people took the time to post their
code/instructions, though.

 That has been my biggest gripe with the documentation so far.

 One thing I would like to see, similar to the php documentation, is
 where users can post examples of using the code in comments.

I'll second that, too.

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Re: Is there an offline documentation for CakePHP?


Wir begrüßen Sie zurück, wenn wir von Ihnen noch einmal.

(I hope that's correct--been a long time since I spoke any German)

On Tue, Mar 31, 2009 at 10:40 AM, Liebermann, Anja Carolin
anja.lieberm...@alltours.de wrote:

 Hi Brian,

 I cannot imagine it either. I just hope to survive until enough things go 
 wrong and it is switched on again.

 Anja

 -Ursprüngliche Nachricht-
 Von: cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] Im Auftrag 
 von brian
 Gesendet: Dienstag, 31. März 2009 16:35
 An: cake-php@googlegroups.com
 Betreff: Re: Is there an offline documentation for CakePHP?


 I cannot imagine trying to develop web apps without an internet connection. 
 There is just so much more than the Cake manual that's required. I can deal 
 with a brief outage, but there's no way I could get much done without a 
 connection *ever*.

 btw, how is the IT dept. supposed to install updates, etc? Or even know about 
 them?

 On Tue, Mar 31, 2009 at 10:24 AM, Liebermann, Anja Carolin 
 anja.lieberm...@alltours.de wrote:

 Hello everybody,

 my company will forbid access to the internet within the next days,
 even for the IT department. To be able to develop with CakePHP in the
 future I would like to know if there is an offline documentation for
 CakePHP
 1.2 ( manual and/or API). Any hints to counter this madness are deeply
 appreciated.

 Anja

 




 


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Re: turning on/off query that shows at the end of each page?


If you set debug to 0 it will not be displayed. Look in
app/config/core.php

You can also remove the echo $cakeDebug; from your layout but I
wouldn't recommend that.

On Tue, Mar 31, 2009 at 8:11 AM, Sajid.bd sajid0405...@gmail.com wrote:

 Hello I am learning cake.Can anyone help me how to turn on/off the
 query that shows at the end of each page?

 


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Re: turning on/off query that shows at the end of each page?

2009-03-31 Thread mscdex


On Mar 31, 8:11 am, Sajid.bd sajid0405...@gmail.com wrote:
 Hello I am learning cake.Can anyone help me how to turn on/off the
 query that shows at the end of each page?

In your app\config\core.php, set the 'debug' configuration setting to
0 or 1.
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skype links with html helper

2009-03-31 Thread donnerbeil


Hi,

Does anyone know, if it is possible to generate a link like:

skype:username?call

with the html-link() method?


I tried this:
$html-link('username','skype:username?call);

output is:
http://www.mydomain.com/skype:username?call

Any ideas?


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Re: skype links with html helper

2009-03-31 Thread Sam Sherlock

I think that using the html helper is unnecessary it is more complicated
than simply

echo 'a href=skype:' . $username . '?call' . $username . '/a';



- S


2009/3/31 donnerbeil donnerb...@googlemail.com


 Hi,

 Does anyone know, if it is possible to generate a link like:

 skype:username?call

 with the html-link() method?


 I tried this:
 $html-link('username','skype:username?call);

 output is:
 http://www.mydomain.com/skype:username?call

 Any ideas?


 


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Router pass email

2009-03-31 Thread hasentopf


Hi.
I've got a problem with Route passing parameters to action.

routes.php:
Router::connect('/newsletter/unsubscribe/:email', array('controller'
= 'newsletterReceivers', 'action' = 'unsubscribe'), array('pass' =
array('email')));

NewsletterReceiversController:
function unsubscribe($email = null) {
  $email = $this-NewsletterReceiver-findByEmail($email);
  if ($this-NewsletterReceiver-del($email)) {
$this-flash(__('Entry deleted', true), '/', 3);
  } else {
$this-flash(__('Invalid Entry', true), '/', 3);
  }
}

Request URL:
http://website.local/newsletter/unsubscribe/t...@web.de

$email, which is passed as an URL Parameter is t...@web and not
t...@web.de

Can anyone tell me why it is cutted before the dot?

Best
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auto submit sitemap to Google

2009-03-31 Thread koala kid


Hi,

I am working on a site for a client using cakePHP. I found a great
article in the bakery that outputs the sitemap in the correct XML
format and is accessible via the browser.  I want to automate the
submission of this using a cron job. Does anyone have an example
script that would call the xml file and send it to the http address
that Google provides specifically for this?

Thanks in advance.
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Search by Selects

2009-03-31 Thread Dave


Can someone point me in the direction of a good place to start
building a Search Function?

I have a HABTM table with options related to the User that they can
select only (not allowed to add or edit), now I want to be able to
have Users search using the checkboxes?

In the table is Hip Hop, Country, Classical, Rock, Indie, Pop, so
on

Now I would like people to be able to search based on those options
using checkbox

Any ideas where to start would be very helpful as I have not found
anything thru my own searching.

Thanks,

Dave
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form select/javascript

2009-03-31 Thread kurious oranj


Hi,

I'm quite new to CakePHP and need to have a SELECT with options for
each year from 1983 to the current year. I can certainly write the
javascript to do the loop from 1983 to current year, but what's the
best way to call that javascript to populate the SELECT? I just need
the general mechanism.

Thanks

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Re: CakePHP on Hiawatha web server

2009-03-31 Thread Gwoo


Did you uncomment App.baseUrl in core.php?
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Re: DebugKit's toolbar not working

2009-03-31 Thread Brendon Kozlowski


If clearing your cache does not help, your CSS may be interfering with
DebugKit's own CSS.

On Mar 31, 10:23 am, Sam Sherlock sam.sherl...@gmail.com wrote:
 Try clearing the browsers cache - I think I to had this issue, just would
 show top right

 after clearing cache of ff it started.   My projects all have jquery in
 them, but I believe that debugkit has contains everything it requires
 (loading jquery via google api - not conclusive on that I expect I'll be
 corrected soon)

 But unles it was mere conincidence clear your browsers cache

 - S

 2009/3/31 Steven steven.beech...@gmail.com





  I installed debug_kit version 1.0 into app\plugins\debug_kit, my debug
  level is set to 2, and I have put:

  var $components = array('DebugKit.Toolbar');

  In the relevant controller. However DebugKit is displaying all its
  output at the bottom of the page between my content, and the SQL
  output.

  I don't have scaffolding, so it can't be that, I have even updated to
  the head revision from thechaw. Which made no difference.

  This might make me sound stupid but I am out of ideas, I know this
  primarily works through jquery, so does jquery to to be in my app
  \webroot\js directory?- Hide quoted text -

 - Show quoted text -
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Re: auto submit sitemap to Google

2009-03-31 Thread Kalt


I'm not 100% sure of that but if your robots.txt have the following
line :
Sitemap: sitemap_location
search engines will crawl your sitemap automatically.

On 31 mar, 17:54, koala kid alexhob...@gmail.com wrote:
 Hi,

 I am working on a site for a client using cakePHP. I found a great
 article in the bakery that outputs the sitemap in the correct XML
 format and is accessible via the browser.  I want to automate the
 submission of this using a cron job. Does anyone have an example
 script that would call the xml file and send it to the http address
 that Google provides specifically for this?

 Thanks in advance.
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Re: form select/javascript

2009-03-31 Thread Kalt


echo $form-dateTime(
'fieldname',
'DMY',
'NONE',
null,
array(
'minYear' = 1983,
'maxYear' = date('Y')
),
false
)

On 31 mar, 18:00, kurious oranj tim.alm...@gmail.com wrote:
 Hi,

 I'm quite new to CakePHP and need to have a SELECT with options for
 each year from 1983 to the current year. I can certainly write the
 javascript to do the loop from 1983 to current year, but what's the
 best way to call that javascript to populate the SELECT? I just need
 the general mechanism.

 Thanks
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Re: Save null or empty datetime fields

2009-03-31 Thread Stinkbug


I ran into the same problem.  I've been told this is a PHP problem,
not really a Cake problem.  The way we ended up handling it is by
creating a stored procedure and calling that procedure within our
model.  Basically, what the procedure does is take the data and makes
sure that all -00-00 fields are set to null.

On Mar 18, 3:00 pm, edwingt edwin.al...@gmail.com wrote:
 Hello,
 I want to save an empty date field, but I cant.
 There are some options to tell the date field that can be null?
 I already check that no rule is defined in the model, for the date
 field and the database date field accepts nulls.

 Any advice?
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Re: How to silently redirects to login page ?

2009-03-31 Thread logout


I woud set $this-Auth-loginRedirect to false and check in the login
() action if the user is logged or not. This way you can check a lot
more things (user role, etc.) and redirect the logged user wherever
you want. Oh, and one more thing, disable the browser cache for the
login form...

On Mar 31, 3:41 pm, John Andersen j.andersen...@gmail.com wrote:
 In your case I would change your route / as I specified earlier and
 in the app_controller-beforeFilter function, add:

       $this-Auth-loginRedirect = array('controller' = 'foo',
 'action' = 'index');

 Thus when a user provides a valid login, the user is automatically
 directed to /foo/index
 Enjoy,
    John

 On Mar 31, 3:13 pm, iFeghali igor.fegh...@gmail.com wrote:



  Hello All,

  Many thanks for the help so far. Let's try to be a bit more clear...
  that's my scenario:

  1) only authenticated users have access to the site (but the login
  form, of course)

  for a visitor (non auth user):
  2) example.com should redirect to example.com/users/login with no
  error message at all
  3) example.com/anything should redirect to example.com/users/login
  with no error message at all, and them redirect the user to /anything
  after logging in
  4) providing the wrong credentials should pop up an error message

  for an authenticated user:
  5) example.com should redirect to example.com/foo/index
  6) trying to access a resource denied to this user should get him the
  authError (but no login form, clear now burzum?)

  So far I have 1, 3, 4, 5 and 6 working fine. But I couldn't think of a
  way to implement (2) without breaking one of the others. Currently
  root (/) routes to /foo/index and I would prefer to keep it this
  way. Routing / to /users/login would bring (2) but break (5).
  Routing / to /users/login *and* finding a way to redirect the path
  to /foo/index inside the users controller sounds an ugly hack that i
  would like to avoid. Any more ideas left ?

  Thank you.- Hide quoted text -

 - Show quoted text -
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Re: simple cms w/ auth :: username password only to admin console page


Ok, I will give it a try with understanding what you are trying to
accomplish!

Correct me if my understand is wrong, but:

1) You have a standard CakePHP installation with the CakePHP directory
and an application app directory, correct?
2) You wish to use the application to provide content management of
the content in the application, correct?
3) You wish that each user of your application will have access only
to his/her own content in the application, correct?

With that I understand that you would like something like:
App
--- Controller
-- a contents controller
--- Models
-- a content model
-- a user model
--- Views
-- Contents
- Content views
-- etc.

Thus when a user has logged in, and has chosen the CMS (contents), the
contents controller gives him/her access to manage the content -
modelled by the content model.

Awaiting some comments from you, enjoy,
   John

On Mar 27, 9:02 am, programguru ja...@w3developing.com wrote:
 Hello,

 I've been hacking at this for several days, and have modified and toyed with 
 about 7 different tutorials with Auth, only to find none of them provide the 
 actual answer I am looking for - or maybe I don't know what the correct 
 answer is.

 Anyhow.

 All I have been trying to do is create:

 1) A view that is user/pass protected which allows control of content for the 
 site. I was able to get several login systems working with Auth, but not able 
 to edit any content because the permissions are outside of the login scope or 
 something of that nature.

 I am certainly missing a link somewhere in all of this.

 2) All controllers should be accessible from this view so the content can be 
 modified.

 I cannot figure out how (although I have done this a million times with 
 straight php/mysql) how to make this work with CakePHP.

 The problem I keep running into is the /users dir only allows access to that 
 dir, but I cannot create a sub directory in there for example called: CMS, 
 because then the controller classes cannot be accessed by the default core.

 Anyhow, Id be glad to hear any insight in how to get a stupid simple CMS page 
 setup with access to all of the sites editable content.

 I don't need anyone to explain how to build a db, a controller, a model, or 
 Bake... That's not what I am asking.

 Just a bit lost and need some direction.

 Thanks.
 --
 View this message in 
 context:http://n2.nabble.com/simple-cms-w--auth-%3A%3A-username---password-on...
 Sent from the CakePHP mailing list archive at Nabble.com.
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Re: DebugKit's toolbar not working

2009-03-31 Thread mark_story


DebugKit does not use any jQuery.  If you are not getting the toolbar
to display, you should check the following.

1. Your HTML output, is the toolbar source there.
2. Your Html output, is the CSS/JS for the toolbar there?
3. If you set $this-view in action or beforeRender you will not see
the toolbar.

Other than that if you have a reproducible ( as in I can get it to
happen for me) issue please file a ticket and I'll be happy to fix
it :)

-Mark

On Mar 31, 8:18 am, Steven steven.beech...@gmail.com wrote:
 I installed debug_kit version 1.0 into app\plugins\debug_kit, my debug
 level is set to 2, and I have put:

 var $components = array('DebugKit.Toolbar');

 In the relevant controller. However DebugKit is displaying all its
 output at the bottom of the page between my content, and the SQL
 output.

 I don't have scaffolding, so it can't be that, I have even updated to
 the head revision from thechaw. Which made no difference.

 This might make me sound stupid but I am out of ideas, I know this
 primarily works through jquery, so does jquery to to be in my app
 \webroot\js directory?
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Re: How to silently redirects to login page ?


Yes, Logout, but first I would like the original poster to make it
work as wished for, then any further checking can be implemented on a
need basis.
Enjoy,
   John

On Mar 31, 8:05 pm, logout stefano...@gmail.com wrote:
 I woud set $this-Auth-loginRedirect to false and check in the login
 () action if the user is logged or not. This way you can check a lot
 more things (user role, etc.) and redirect the logged user wherever
 you want. Oh, and one more thing, disable the browser cache for the
 login form...

[snip]
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Re: Router pass email

2009-03-31 Thread hasentopf


Hi again.

In my routes.php I also got:   Router::parseExtensions('rss');

This entry is necessary for creating a RSS feed with the RssHelper.

When the Router::parseExtensions('rss'); comes before Router::connect
('/newsletter/unsubscribe/:email', array('controller'
= 'newsletterReceivers', 'action' = 'unsubscribe'), array('pass' =
array('email')));  the email parameter is passed correctly.

Can anyone explain this?

Best
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Re: variable from one action view to another


Use urlencode for the name before placing it in the url and then
urldecode it when processing the reply!
Enjoy,
   John

On Mar 25, 3:33 am, kai k3ho...@gmail.com wrote:
 I have a foreach loop that runs through an array and for each object
 there's a report link that lets users report something wrong with that
 object. the report link draws a modal box that displays the report
 actions view and in that view i'm hoping to have the name of the
 object. I tried passing the name in the url but some names use symbols
 that won't work, does anyone have any suggestions?
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Re: Multiple hasMany relationships to one model?


Brian - that'd be a good option if an image can belong to many movies
and many episodes.

Adam - is that the case? Or can an image only belong to either 1 movie
or 1 episode? From the description you put up it sounds like hasMany
is the right association, it's just making a good db design underneath
it.

On Mar 31, 9:39 am, brian bally.z...@gmail.com wrote:
 I'd go HABTM for this, I think.

 movies
 videos
 images
 images_movies
 images_videos



 On Tue, Mar 31, 2009 at 2:09 AM, Adam M adam.mcnam...@gmail.com wrote:

  Hi All,

  How can I PROPERLY set up my database so that several models have
  multiple images?  Each image belongs to a particular model, so they
  are definitely hasMany relationships.  Example:

  Episode
  -id
  -name
  -date

  Movie
  -id
  -name
  -date
  -producer

  Image
  -id
  -name
  -caption
  -path

  Episode hasMany Image
  Movie hasMany Image

  Does the paradigm of adding a foreign key to the Image table still
  apply if I have multiple hasMany relationships?  That is, would I add
  multiple foreign keys to the table as follows?:
  Image
  -id
  -movie_id
  -episode_id
  -name
  -caption
  -path

  Thanks
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Re: Double left join?


Take a look at the Containable behavior. You should able to something
as simple as:

http://book.cakephp.org/view/474/Containable

$this-Model-contain('Company', 'Category');
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Re: Does anybody know how can I limit the join table fields when I user joins condition?


I highly recommend checking out the Containable behavior:

http://book.cakephp.org/view/474/Containable

It will simplify this code and let you easily add fields.

On Mar 31, 8:28 am, joshua josh...@gmail.com wrote:
 For example:
 One task has many users.
 
         $condition = array();
         $condition['joins'] = array(
             array(
                 'table' = 'users',
                 'alias' = 'User',
                 'type' = 'inner',
                 'foreignKey' = 'user_id',
                 'conditions'= array('User.id =
 Task.user_id','User.deleted=0')
         ));
 
 I just want to find the user name , not all the fields in User table. I try
 to add the 'fields' property in this array, but it seems not.
 --
 Thanks
 Joshua
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Re: looking for a method to record 'page views'

2009-03-31 Thread Smelly Eddie

Have you considered using an existing solution with metrics and
reporting surrounding it? You can give read only access to clients as
well.

http://edwardawebb.com/programming/php-programming/cakephp/piwik-analyze-visits-cakephp-site

On Mar 30, 1:39 pm, JamesF usaexportexpe...@gmail.com wrote:
i did see that article but i think im goign to go with a different
approach...

i'm making a table called visits with four fields

id -auto increment
listing_id -related listing id
timestamp -now()
ip_address -users ip

basically whenever a listing is view i will execute an insert on the
database logging the information. when i display the stats i will run
queries off the table.
i have a feeling this isn't going to be very MVC compliant but bottom
line is i need to get it working. i have a few concerns about database
performance but i think it will be better to do it this way than a log
file/cron job method.

On Mar 30, 12:21 pm, brian bally.z...@gmail.com wrote:

Have a look at this
HitCountBehaviorhttp://dsi.vozibrale.com/articles/view/simple-hitcount-behavior-for-c...

I haven't used this, though it's been on my list of things to investigate.

On Mon, Mar 30, 2009 at 11:14 AM, JamesF usaexportexpe...@gmail.com wrote:

Hi all,

I am looking for a simple way of keeping track of page views. The
application is a rental properties website and I would like
advertisers who list their properties to know how many times they have
been viewed.

Anyone have a tried and true method for this ?
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Re: looking for a method to record 'page views'

2009-03-31 Thread Matt Curry


Another thing to consider (especially if it's a busy site) is to not
track the views in real time.  Instead scan your webserver logs hourly/
daily and update the counts that way.  This allows you to cache the
pages and still keep track of visits.

-Matt
http://www.pseudocoder.com

On Mar 30, 11:14 am, JamesF usaexportexpe...@gmail.com wrote:
 Hi all,

 I am looking for a simple way of keeping track of page views. The
 application is a rental properties website and I would like
 advertisers who list their properties to know how many times they have
 been viewed.

 Anyone have a tried and true method for this ?
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Re: Setting Layout for Scaffolding?

2009-03-31 Thread bbf


Thanks Amit but unfortunately that walkthrough helps for modifying the
HTML that the scaffolding functionality uses -- but it does not
address the layout. The layout remains default.

 I also tried setting  [ $this-layout =  ] in those view / .ctp
files and no change.

I also tried [ $this-layout =  ] in _beforeScaffold() -- no
change.

What I find bizarre is that it seems that not many others need this
functionality?
public frontend = layout1
private backend = layout2

Does everyone use the same layout for the scaffolding?

On Mar 30, 6:11 pm, Amit a...@amitvaria.com wrote:
 Here's a good 
 walkthrough:http://teknoid.wordpress.com/2009/01/31/take-control-over-your-bake-a...

 On Mar 30, 5:05 pm, Amit a...@amitvaria.com wrote:

  I think you're referring to cake/libs/views/scaffold/(add|edit|
  view.ctp). These will let you alter the way scaffolding looks

  On Mar 30, 2:42 am, bbf builtbyf...@gmail.com wrote:

   I've searched the groups and Google and can't find an answer for this.

   How do I set a different layout for the scaffolding?

   Thanks for your help!
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Re: form select/javascript

2009-03-31 Thread mscdex


On Mar 31, 12:18 pm, Kalt pierre.fring...@gmail.com wrote:
 echo $form-dateTime(
         'fieldname',
         'DMY',
         'NONE',
         null,
         array(
                 'minYear' = 1983,
                 'maxYear' = date('Y')
         ),
         false
 )

You can also do:

echo $form-year('Model.fieldname', 1983, date(Y), null, array(),
false);
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Re: media view and files on the fly

2009-03-31 Thread Mark (Germany)


nice :)
thx

On 31 Mrz., 15:17, Matt Curry m...@mcurry.net wrote:
 I had to do this with pdf/xls files returned by a webservice.  I took
 the default media view (/cake/libs/views/media.php) and copied it to /
 app/views/app_media.php.

 Then I modified it so that it checked for a $content view var and
 wrote that to a tmpfile.
 Here's the diff:http://bin.cakephp.org/view/1310700342

 -Matthttp://www.pseudocoder.com

 On Mar 30, 1:05 pm, Mark (Germany) dereurom...@googlemail.com
 wrote:

  i tried to use the media view for files generated on the fly (some
  exported text inside a export.txt or whatever)
  but it seems like the media view can only handle downloads of
  existing files on the server

  trying to rewrite it did not turn out very well
  so, did anyone manage to create a txt file to download, that is filled
  with the echoed content

  echo 'blabla'
  or
  $content = 'blabla' transfered to the media view

  without creating locale (temp.) files on the server?
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Re: DebugKit's toolbar not working

2009-03-31 Thread Steven


After reading your posts I could see that the css and toolbar were
loading. I tried installing a it on a fresh cakephp app, to ensure it
wasnt a CSS clash, and notices that cakephp had no styling...

Then I realised that this issue boiled down to mod_rewrite not being
on!

Thanks for the replies, and thanks for an awesome plugin Mark.

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Re: Why is validation called twice?

2009-03-31 Thread Miles J


Thats my last resort type of deal. Just wondering why its called twice?
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Re: media view and files on the fly

2009-03-31 Thread Mark (Germany)


are you sure it is app_media.php then?
i only got it to work by leaving it the same name media.php in /app/
views/

mark



On 31 Mrz., 21:45, Mark (Germany) dereurom...@googlemail.com
wrote:
 nice :)
 thx

 On 31 Mrz., 15:17, Matt Curry m...@mcurry.net wrote:

  I had to do this with pdf/xls files returned by a webservice.  I took
  the default media view (/cake/libs/views/media.php) and copied it to /
  app/views/app_media.php.

  Then I modified it so that it checked for a $content view var and
  wrote that to a tmpfile.
  Here's the diff:http://bin.cakephp.org/view/1310700342

  -Matthttp://www.pseudocoder.com

  On Mar 30, 1:05 pm, Mark (Germany) dereurom...@googlemail.com
  wrote:

   i tried to use the media view for files generated on thefly(some
   exported text inside a export.txt or whatever)
   but it seems like the media view can only handle downloads of
   existing files on the server

   trying to rewrite it did not turn out very well
   so, did anyone manage to create a txt file to download, that is filled
   with the echoed content

   echo 'blabla'
   or
   $content = 'blabla' transfered to the media view

   without creating locale (temp.) files on the server?
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Re: Why is validation called twice?

2009-03-31 Thread logout


Well, you have too many 'recaptcha'-s:

'recaptcha' = array(
'recaptcha' = array(
'rule' = array('recaptcha'),
'message' = 'captchaFailed'
)
)

Just try to name those differently and try again, for example:

'myrecaptcha' = array(
'recaptcha2' = array(
'rule' = array('recaptcha'),
'message' = 'captchaFailed'
)
)

Hope this helps.

On Mar 31, 11:43 pm, Miles J mileswjohn...@gmail.com wrote:
 Thats my last resort type of deal. Just wondering why its called twice?
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Re: Why is validation called twice?

2009-03-31 Thread Miles J


Well thats not the problem, I simply had more rules and in the example
I am only showing one.
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Re: Why is validation called twice?

2009-03-31 Thread Miles J


For now I had to manipulate the sessions to make sure the first value
is used and not over written.

/**
 * Validate recaptcha
 * @param array $data
 * @return boolean
 */
function recaptcha($data) {
App::import('Vendor', 'recaptcha', array('file' = 'recaptcha.php'));
App::import('Component', 'Session');

$Session = new SessionComponent();
$private = Configure::read('Settings.captcha_private');
$public = Configure::read('Settings.captcha_public');

$verify = recaptcha_check_answer($private, env('REMOTE_ADDR'), $this-
data[$this-name]['recaptcha_challenge'], $this-data[$this-name]
['recaptcha']);

if ($Session-read('Recaptcha.time') == time()) {
$response = $Session-read('Recaptcha.response');
} else {
$response = ($verify-is_valid) ? 'pass' : 'fail';
$Session-write('Recaptcha.response', $response);
$Session-write('Recaptcha.time', time());
}

return ($response == 'pass') ? true : false;
}

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Re: auto submit sitemap to Google


Google provides for creating and sending them a sitemap:

http://www.google.com/support/webmasters/bin/answer.py?answer=40318hl=en

On Tue, Mar 31, 2009 at 12:13 PM, Kalt pierre.fring...@gmail.com wrote:

 I'm not 100% sure of that but if your robots.txt have the following
 line :
 Sitemap: sitemap_location
 search engines will crawl your sitemap automatically.

 On 31 mar, 17:54, koala kid alexhob...@gmail.com wrote:
 Hi,

 I am working on a site for a client using cakePHP. I found a great
 article in the bakery that outputs the sitemap in the correct XML
 format and is accessible via the browser.  I want to automate the
 submission of this using a cron job. Does anyone have an example
 script that would call the xml file and send it to the http address
 that Google provides specifically for this?

 Thanks in advance.
 


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Re: Router pass email


I guess the .de looks like an extension. Why it would strip it from
your route is another question.

You could avoid this altogether (depending on your situation) by
POSTing the email address to your action. If this link is
auto-generated and included in a newsletter email, I guess that'd be
out of the question. Unless you provided a generic link and had the
user submit their email from a form.

On Tue, Mar 31, 2009 at 1:28 PM, hasentopf
mathias.koell...@googlemail.com wrote:

 Hi again.

 In my routes.php I also got:       Router::parseExtensions('rss');

 This entry is necessary for creating a RSS feed with the RssHelper.

 When the Router::parseExtensions('rss'); comes before Router::connect
 ('/newsletter/unsubscribe/:email', array('controller'
 = 'newsletterReceivers', 'action' = 'unsubscribe'), array('pass' =
 array('email')));  the email parameter is passed correctly.

 Can anyone explain this?

 Best
 


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Re: form select/javascript

2009-03-31 Thread Juan Carlos Michaca

 echo $form-input('Model.field', array('onclick'='someAction()',
'label'='', 'minYear' = '1910', 'maxYear' = '2010'));

2009/3/31 mscdex msc...@gmail.com


 On Mar 31, 12:18 pm, Kalt pierre.fring...@gmail.com wrote:
  echo $form-dateTime(
  'fieldname',
  'DMY',
  'NONE',
  null,
  array(
  'minYear' = 1983,
  'maxYear' = date('Y')
  ),
  false
  )

 You can also do:

 echo $form-year('Model.fieldname', 1983, date(Y), null, array(),
 false);
 



-- 
Juan Carlos Michaca Lucero
PAASEL
Consultoría en Matemáticas Aplicadas
Insurgentes Sur 1700 Despacho 102
Col. Florida C.P, 01030
Deleg. Alvaro Obregón, México D.F.
Tel. + 52 (55) 5663 4175
http://www.paasel.com
juan.mich...@paasel.com

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Re: form select/javascript

2009-03-31 Thread jc_mich



You can do this:

 echo $form-input('Model.year', array('onclick'='someAction();',
'label'='','style'=width: 60px, 'minYear' = '1983', 'maxYear' =
date('Y'))); 



kurious oranj wrote:
 
 
 Hi,
 
 I'm quite new to CakePHP and need to have a SELECT with options for
 each year from 1983 to the current year. I can certainly write the
 javascript to do the loop from 1983 to current year, but what's the
 best way to call that javascript to populate the SELECT? I just need
 the general mechanism.
 
 Thanks
 
  
 
 

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Sent from the CakePHP mailing list archive at Nabble.com.


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Re: Notice (8): Undefined index: id?

2009-03-31 Thread Aurelius


It happens when Saving a Model!

I've no beforeX-Filters, I also had debug($this-data) right before
saving,
but each Model (Accept the hasAndbelongToMany) have an id!

thx
Aurelius

On 31 Mrz., 02:32, mscdex msc...@gmail.com wrote:
 On Mar 30, 6:11 pm, Marcelo Andrade mfandr...@gmail.com wrote:



  On Mon, Mar 30, 2009 at 6:44 PM, Aurelius aurel...@temporaryinbox.com 
  wrote:

   What does that mean, and where is the problem?
   Notice (8): Undefined index: id [CORE/cake/libs/model/model.php, line
   1281...on line 77

   That's line 77:
   if ($this-User-save ( $this-data, true , array ( 'firstname',
   'lastname', '' ))) {
   ... }

   What's wrong?

  It's hard to say.  Maybe you're in an edit action and
  your $this-data doesn't contain the desired record id.

  Please, tell us more about your scenario.

  Best regards.

  --
  MARCELO DE F. ANDRADE
  Belem, PA, Amazonia, Brazil
  Linux User #221105

 http://mfandrade.wordpress.com

 Also, do you have any beforeValidate or beforeSave callbacks that are
 changing the data?
 Sounds like the data for your primary key for your User model is being
 unset somewhere possibly.
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login problem


The problem is simply that I can't log in. I've done this before but
I'm trying to build an ACL-controlled site and following along with
the manual's example app. WHen I try loggin in I get You are not
authorized to access that location. I suspect the problem might be
with the redirect, and not my credentials, as I'm not seeing Auth's
loginError.

AppController:

function beforeFilter()
{
$this-Auth-fields = array('username' = 'email', 'password' = 
'password');
$this-Auth-userScope = array( 'User.enabled' = 1);
$this-Auth-loginError = 'No matching user found.';
$this-Auth-loginAction = array('controller' = 'users', 'action' = 
'login');
$this-Auth-loginRedirect = array('controller' = 'pages', 'action'
= 'display', 'home');
$this-Auth-logoutRedirect = array('controller' = 'users', 'action'
= 'login');
$this-Auth-authorize = 'actions';
$this-Auth-actionPath = 'ROOT/';
}

UsersController:

function beforeFilter()
{
parent::beforeFilter();
if ($this-action == 'login') $this-layout = 'login';
$this-Auth-allowedActions = array('reset_password');
}

public function login() {}

public function logout()
{
$this-Session-setFlash('Good-Bye');
$this-redirect($this-Auth-logout());
}

As you can see, it's not much different than the manual. The
beforeFilter layout switch is there because none of the pages for this
site should be public (it's an extranet).

The password is good, and my user is enabled.

I have nothing in my acos table yet, so I think that shouldn't be the
cause of this. AFAICT, if PagesController::display() is not in acos,
there shouldn't be any problem. Correct me if I'm wrong, please.

Can anyone see something missing? Or think of something else I can check?

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Re: login problem


Sorry for the noise. It was indeed this line:

$this-Auth-authorize = 'actions';

I thought that because there is no ACO for PagesController there
wouldn't be a problem. In any case, this isn't what I want to do,
after all.

Back to the drawing board ...

On Tue, Mar 31, 2009 at 10:14 PM, brian bally.z...@gmail.com wrote:
 The problem is simply that I can't log in. I've done this before but
 I'm trying to build an ACL-controlled site and following along with
 the manual's example app. WHen I try loggin in I get You are not
 authorized to access that location. I suspect the problem might be
 with the redirect, and not my credentials, as I'm not seeing Auth's
 loginError.

 AppController:

 function beforeFilter()
 {
        $this-Auth-fields = array('username' = 'email', 'password' = 
 'password');
        $this-Auth-userScope = array( 'User.enabled' = 1);
        $this-Auth-loginError = 'No matching user found.';
        $this-Auth-loginAction = array('controller' = 'users', 'action' = 
 'login');
        $this-Auth-loginRedirect = array('controller' = 'pages', 'action'
 = 'display', 'home');
        $this-Auth-logoutRedirect = array('controller' = 'users', 'action'
 = 'login');
        $this-Auth-authorize = 'actions';
        $this-Auth-actionPath = 'ROOT/';
 }

 UsersController:

 function beforeFilter()
 {
        parent::beforeFilter();
        if ($this-action == 'login') $this-layout = 'login';
        $this-Auth-allowedActions = array('reset_password');
 }

 public function login() {}

 public function logout()
 {
        $this-Session-setFlash('Good-Bye');
        $this-redirect($this-Auth-logout());
 }

 As you can see, it's not much different than the manual. The
 beforeFilter layout switch is there because none of the pages for this
 site should be public (it's an extranet).

 The password is good, and my user is enabled.

 I have nothing in my acos table yet, so I think that shouldn't be the
 cause of this. AFAICT, if PagesController::display() is not in acos,
 there shouldn't be any problem. Correct me if I'm wrong, please.

 Can anyone see something missing? Or think of something else I can check?


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HELP, Controller displaying multiple duplicate rows

2009-03-31 Thread Louie Miranda

Hello,

I think there is a problem on my parameter on the controller. Because once
my other tables has multiple entries, the data on the row is duplicated for
my main controller.

See my code and parameter and the SQL query cakephp produces.
http://bin.cakephp.org/saved/5

The default for cakephp

   1. *$this-set('pdffiles', $this-paginate());*
   2.
   3. ON (`Pdffile`.`statuses_id` = `Statuses`.`id`) LEFT
JOINhttp://www.php.net/join`users`
   AS `User`
   4. --- ON (`Pdffile`.`user_id` = `User`.`id`) LEFT
JOINhttp://www.php.net/join`comments`
   AS `Comment`
   5. ON (`Comment`.`pdffile_id` = `Pdffile`.`id`) LEFT
JOINhttp://www.php.net/join`statuses`
   AS `Status`
   6. *ON (`Status`.`pdffile_id` = `Pdffile`.`id`) WHERE 1 = 1 LIMIT 20*

The modified, under controller

   1. $this-Pdffile-recursive = 0;
   2. *$parsedConditions['Pdffile.user_id'] = $this-Auth-User('id');*
   3. $this-paginate['Pdffile'] = array http://www.php.net/array(
   'conditions' = $parsedConditions, 'limit' = '50', 'order' =
arrayhttp://www.php.net/array
   ('Pdffile.timestamp' = 'desc'));
   4. $this-set('pdffiles', $this-paginate());
   5.
   6. ON (`Pdffile`.`statuses_id` = `Statuses`.`id`) LEFT
JOINhttp://www.php.net/join`users`
   AS `User`
   7. --- ON (`Pdffile`.`user_id` = `User`.`id`) LEFT
JOINhttp://www.php.net/join`comments`
   AS `Comment`
   8. ON (`Comment`.`pdffile_id` = `Pdffile`.`id`) LEFT
JOINhttp://www.php.net/join`statuses`
   AS `Status`
   9. ON (`Status`.`pdffile_id` = `Pdffile`.`id`) WHERE `Pdffile`.`user_id`
   = 17
   10. ORDER BY `Pdffile`.`timestamp` desc LIMIT 50

Missing where 1 = 1?

How could this be fixed?
--
Louie Miranda (lmira...@gmail.com)
http://www.louiemiranda.net

Quality Web Hosting - www.axishift.com
Pinoy Web Hosting, Web Hosting Philippines

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RewriteEngine not allowed here - 500 Internal Server Error

2009-03-31 Thread djXternal


/htdocs/cake/.htaccess: RewriteEngine not allowed here

this is resulting in a 500 Internal Server error, I have checked for
the existence the proper content of all .htaccess files, and have
setup the 'AllowOverride All' and the Load Module for mod_rewrite are
all setup properly, and I even tried adding 'RewriteBase /' to
the .htaccess files

What else could be wrong?

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Re: HELP, Controller displaying multiple duplicate rows