Direct Client-Web Designer/Web Architect-Bay Area,CA
Hello, We have requirement for Web Designer/Web Architect in bay area CA. The person needs to have experience in building Commerce Site where Actual Shopping has been done. If your skills and experience matches with the same, send me your resume asap with contact # and rate to '[EMAIL PROTECTED]'. Title = Contract Information Architect/User Experience Designer 6 month contract Location: Redwood city Requirements: The person needs to have experience in building Commerce Site where Actual Shopping has been done Strong knowledge of site design; mastery in principles of Web design (HCI, HTML, CSS) Strong knowledge of user interface design processes and methodology Working knowledge of User Centered Design Principles and Practices Knowledge of architecture-related software (Illustrator, Visio, Photoshop, SQL Server, MS Office, Acrobat, Dreamweaver) Strong Preference given to those with:: Experience with digital media commerce sites Kan BTech Inc Recruiter 510-438-6834 [EMAIL PROTECTED] www.tbiinc.org --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: django foreignkey
Hi Nathan, I did manage.py syncdb with the table still not existing. I did manage.py sqlall myapps when saw that the foreign key was not created. here is my actual source code. from django.db import models from django.contrib.auth.models import User as AdminUser # Create your models here. DEPARTMENTS = ( ('HRD', 'HRD'), ('ACT', 'Accounting'), ('PUR', 'Purchasing'), ('LOG', 'Logistics'), ('PRO', 'Production'), ('MKG', 'Marketing'), ('EXP', 'Export'), ('ITD', 'IT'), ) LEVELS = ( ('SM', 'Senior Manager'), ('MR', 'Manager'), ('SP', 'Supervisor'), ('ST', 'Staff'), ) class User(models.Model): """KSK Employee accounts to use this application""" user = models.ForeignKey(AdminUser) department = models.CharField(maxlength=3, choices=DEPARTMENTS) level = models.CharField(maxlength=3, choices=LEVELS) Thanks james On Jul 19, 2:56 pm, Nathan Ostgard <[EMAIL PROTECTED]> wrote: > manage.py syncdb won't add new fields to the database if the table > already exists. You'll have to do this yourself. See manage.py sqlall > for some help. > > Otherwise, if you have: user = models.ForeignKey(User), then look for > a field named user_id in your table. > > > Nathan Ostgard > > On Jul 18, 9:57 pm, james_027 <[EMAIL PROTECTED]> wrote: > > > hi, > > > I have a model with a field models.ForeignKey(), with manage.py > > validate I check if my code are right, then run manage.py syncdb. When > > I was checking the tables generated I don't see any foreign key > > created? Is there something wrong? where should I check? > > > I am using django 0.96, mysql 5 on winxp > > > Thanks > > james --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Direct Client -Sr.Software Engineer Python-San Jose CA -Locals only
Hello, We have requirement for Sr.Software Engineer in San Jose CA with very strong experinece in PYTHON AND LINUX . If your skills and experience matches with the same, send me your resume asap with contact # and rate to '[EMAIL PROTECTED]'. Locals only pls apply TECHNICAL SKILLS REQUIREMENTS: * Knowledge of Internet protocols such as TCP/IP, HTTP, FTP, POP3, IMAP, SMTP, SNMP, etc. is a huge plus *Very Strong Knowledge of Python, Java, C++ or other object-oriented language is a plus Kan BTech Inc Recruiter 510-438-6834 [EMAIL PROTECTED] www.tbiinc.org --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
login() method conflict
hi, i've been trying to get started with django and i am stock in this problem and found out that there's a conflict in login() method. here is my view code from django.http import HttpResponse, HttpResponseRedirect from django.shortcuts import render_to_response from django.contrib.auth import authenticate, login def index(request): if not request.user.is_authenticated(): return render_to_response('login.htm', {'from':request.path}) return render_to_response('index.htm') def login(request): if request.method == 'POST': user = authenticate(username=request.POST['username'], password=request.POST['password']) if user is not None: if user.is_active: #return HttpResponse('user authenticated') fixlogin(request, user) return HttpResponseRedirect('/main/') else: return HttpResponse('user not active') else: return HttpResponse('authenticate fail') return render_to_response('login.htm') The problem is an error saying login() method accept only one parameter, where I follow this documentation (http:// www.djangoproject.com/documentation/0.96/authentication/#how-to-log-a-user-in). After many times of trail and error I thought of changing this import from django.contrib.auth import authenticate, login to from django.contrib.auth import authenticate, login as fixlogin() and use fixlogin(request, user) Is this already fix? I am just using 0.96. Thanks james --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: login() method conflict
On Thu, 2007-07-19 at 08:02 +, james_027 wrote: > hi, > > i've been trying to get started with django and i am stock in this > problem and found out that there's a conflict in login() method. here > is my view code > > from django.http import HttpResponse, HttpResponseRedirect > from django.shortcuts import render_to_response > from django.contrib.auth import authenticate, login > > > def index(request): > if not request.user.is_authenticated(): > return render_to_response('login.htm', {'from':request.path}) > return render_to_response('index.htm') > > def login(request): > if request.method == 'POST': > user = authenticate(username=request.POST['username'], > password=request.POST['password']) > if user is not None: > if user.is_active: > #return HttpResponse('user authenticated') > fixlogin(request, user) > return HttpResponseRedirect('/main/') > else: > return HttpResponse('user not active') > else: > return HttpResponse('authenticate fail') > return render_to_response('login.htm') > > The problem is an error saying login() method accept only one > parameter, where I follow this documentation (http:// > www.djangoproject.com/documentation/0.96/authentication/#how-to-log-a-user-in). > After many times of trail and error I thought of changing this import > from django.contrib.auth import authenticate, login to from > django.contrib.auth import authenticate, login as fixlogin() and use > fixlogin(request, user) > > Is this already fix? I am just using 0.96. There's no bug in Django here. The problem is that you import django.contrib.auth.login into the local namespace *and* decide to define another method called login also in the local namespace. Since you can only have one thing of each name in the namespace, confusion arises and the last thing trying to use that name (your method) wins. You'll notice in the documentation you refer to that the method defined in the local file is not called login(), for example. This is just normal Python practice -- one thing per name. The standard solution is to do from django.contrib import auth and then refer to auth.login() in your login() method. That explicitly avoids the name clash. Alternatives include picking a name other than "login" for your method or import auth.login under some other name, as you did. Regards, Malcolm -- Success always occurs in private and failure in full view. http://www.pointy-stick.com/blog/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Django advocacy in a commercial environment
Hello, Having just finished a couple of large projects in PHP4, our department (of 5 programmers) is looking to move to PHP5 - but me and another on the team have been pushing towards using Python/Django in future. While everyone sees the benefits of moving to Python (namespaces! enforced syntax! and more!), it would help us immensely if we could find some resources to wow the other programmers here. I was fortunate enough to attend Simon Willison's excellent talk at LUGRadio Live 2006, which really inspired me to start using Django, but short of inviting him here (and probably paying him), I'm not sure I could recreate that kind of convincing argument myself. Which leaves us with online resources, presentations, screencasts and suchlike. If anyone has any good resources which show off the power of Django (and by association, the benefits of PHP), then please share them with us. Thanks, --Jon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django advocacy in a commercial environment
Oops, a quick edit - that last sentence should of course read: ...'benefits *over* PHP'... --Jon On 7/19/07, Jon Atkinson <[EMAIL PROTECTED]> wrote: > Hello, > > Having just finished a couple of large projects in PHP4, our > department (of 5 programmers) is looking to move to PHP5 - but me and > another on the team have been pushing towards using Python/Django in > future. > > While everyone sees the benefits of moving to Python (namespaces! > enforced syntax! and more!), it would help us immensely if we could > find some resources to wow the other programmers here. > > I was fortunate enough to attend Simon Willison's excellent talk at > LUGRadio Live 2006, which really inspired me to start using Django, > but short of inviting him here (and probably paying him), I'm not sure > I could recreate that kind of convincing argument myself. Which leaves > us with online resources, presentations, screencasts and suchlike. > > If anyone has any good resources which show off the power of Django > (and by association, the benefits of PHP), then please share them with > us. > > Thanks, > > --Jon > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: login() method conflict
You may find it easier to avoid these conflicts by doing: from django.contrib import auth Then use: user = auth.authenticate(username='foo', password='bar') auth.login(request, user) On Jul 19, 1:02 am, james_027 <[EMAIL PROTECTED]> wrote: > hi, > > i've been trying to get started with django and i am stock in this > problem and found out that there's a conflict in login() method. here > is my view code > > from django.http import HttpResponse, HttpResponseRedirect > from django.shortcuts import render_to_response > from django.contrib.auth import authenticate, login > > def index(request): > if not request.user.is_authenticated(): > return render_to_response('login.htm', {'from':request.path}) > return render_to_response('index.htm') > > def login(request): > if request.method == 'POST': > user = authenticate(username=request.POST['username'], > password=request.POST['password']) > if user is not None: > if user.is_active: > #return HttpResponse('user authenticated') > fixlogin(request, user) > return HttpResponseRedirect('/main/') > else: > return HttpResponse('user not active') > else: > return HttpResponse('authenticate fail') > return render_to_response('login.htm') > > The problem is an error saying login() method accept only one > parameter, where I follow this documentation > (http://www.djangoproject.com/documentation/0.96/authentication/#how-to-log-a...). > After many times of trail and error I thought of changing this import > from django.contrib.auth import authenticate, login to from > django.contrib.auth import authenticate, login as fixlogin() and use > fixlogin(request, user) > > Is this already fix? I am just using 0.96. > > Thanks > james --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: login() method conflict
Thanks everyone, that was a foolish mistake... I am not only new to django but also new to python cheers, james On Jul 19, 4:09 pm, Nathan Ostgard <[EMAIL PROTECTED]> wrote: > You may find it easier to avoid these conflicts by doing: > from django.contrib import auth > > Then use: > user = auth.authenticate(username='foo', password='bar') > auth.login(request, user) > > On Jul 19, 1:02 am, james_027 <[EMAIL PROTECTED]> wrote: > > > hi, > > > i've been trying to get started with django and i am stock in this > > problem and found out that there's a conflict in login() method. here > > is my view code > > > from django.http import HttpResponse, HttpResponseRedirect > > from django.shortcuts import render_to_response > > from django.contrib.auth import authenticate, login > > > def index(request): > > if not request.user.is_authenticated(): > > return render_to_response('login.htm', {'from':request.path}) > > return render_to_response('index.htm') > > > def login(request): > > if request.method == 'POST': > > user = authenticate(username=request.POST['username'], > > password=request.POST['password']) > > if user is not None: > > if user.is_active: > > #return HttpResponse('user authenticated') > > fixlogin(request, user) > > return HttpResponseRedirect('/main/') > > else: > > return HttpResponse('user not active') > > else: > > return HttpResponse('authenticate fail') > > return render_to_response('login.htm') > > > The problem is an error saying login() method accept only one > > parameter, where I follow this documentation > > (http://www.djangoproject.com/documentation/0.96/authentication/#how-t..). > > After many times of trail and error I thought of changing this import > > from django.contrib.auth import authenticate, login to from > > django.contrib.auth import authenticate, login as fixlogin() and use > > fixlogin(request, user) > > > Is this already fix? I am just using 0.96. > > > Thanks > > james --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: context processor question
Hello, Here it is the part of the documentation you are looking for: http://www.djangoproject.com/documentation/templates_python/#subclassing-context-requestcontext This is an extract of the part that you are looking: If you're using Django's render_to_response() shortcut to populate a template with the contents of a dictionary, your template will be passed a Context instance by default (not a RequestContext). To use a RequestContext in your template rendering, pass an optional third argument to render_to_response(): a RequestContext instance. Your code might look like this: def some_view(request): # ... return render_to_response('my_template.html', my_data_dictionary, context_instance=RequestContext(request)) I hope that help. On Jul 19, 6:45 am, james_027 <[EMAIL PROTECTED]> wrote: > Hi Jeremy, > > I am a bit lost ... where do I apply that? Isn't that I just call the > variable name/dict key in the template? > > Thanks > james > > On Jul 19, 11:18 am, "Jeremy Dunck" <[EMAIL PROTECTED]> wrote: > > > On 7/18/07, james_027 <[EMAIL PROTECTED]> wrote: > > ... > > > > the commonly use data will automatically available, do I get it right? > > > Yes. Just keep in mind that you need to use RequestContext rather > > than Context in order for context processors to be applied. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
meta path_info, yet again
hello everone, a while back I mailed about a problem with path_info. Basically I'm having the same problem and the previous fix we discussed no longer works. I'm getting this behavior: http://www.com/a/ => path_info = "/a" http://www.com/a/b/ => path_info = "/b" http://www.com/a/b/c/ => path_info = "/b/c/" Apache 2.2.4 mod_python 3.3.1 The previous time I had this error we were able to fix it by removing DocumentRoot from the apache config, but this time that's not really working. This is the virtual-host section with some small obfuscations: ( settings.py is in /opt/splice/pysplice/settings.py ) ServerName xx.splicemusic.com ServerAlias beard AcceptPathInfo On AuthName "x" AuthUserFile /x AuthType Basic require valid-user Order allow,deny Allow from All PythonInputFilter tramline.core::inputfilter TRAMLINE_INPUT PythonOutputFilter tramline.core::outputfilter TRAMLINE_OUTPUT SetInputFilter TRAMLINE_INPUT SetOutputFilter TRAMLINE_OUTPUT PythonOption tramline_path /tmp/tramline/ SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE pysplice.settings SetEnv LD_LIBRARY_PATH /usr/local/lib:/usr/local/pgsql/lib PythonDebug On PythonPath "['/opt/splice/'] + sys.path" Satisfy Any Allow from All Satisfy Any Allow from All Satisfy Any Allow from All Alias /media /opt/splice/pysplice/media # for some things we need media served by apache! SetHandler None Satisfy Any Allow from All I'm becoming pretty desperate for a fix as we're slowly but surely converting this server to our "live" server. thanks a lot, - bram PS: http://www.splicemusic.com is moving to django. Yippy :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Bulk data upload
This approach does sound really interesting, and is pretty close to what I've been planning. I wonder if I might have a look at that ExcelImport class :) Toby Dylan Hocking escribió: >> What about CSV? You can export from Excel as CSV pretty easily and it's a >> fairly easy format to parse in python... > > Either that or tab-delimited text. I have a django app that does bulk data > upload from the admin interface according to the following protocol. > > 1. Users make their bulk upload data tables in excel. > > 2. They log onto the Django admin site, where I have a special ExcelImport > model set up --- it just has a TextField where the data goes. > > 3. They copy the entire table from excel and paste it in the TextField, > then click Save. > > 4. I have a custom save() method for the ExcelImport class that processes > the data and creates the related objects. > >> Thanks, >> >> Dave >> >> -- >> David Reynolds >> [EMAIL PROTECTED] >> >> > > --~--~-~--~~~---~--~~ > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-users@googlegroups.com > To unsubscribe from this group, send email to [EMAIL PROTECTED] > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en > -~--~~~~--~~--~--~--- > signature.asc Description: OpenPGP digital signature
Request Context and Generic Views
Hi there! How does it exactly work when I want a RequestContext to be used in a generic view. There's the context_processors key in the dict you gotta pass it, but "A list of template-context processors to apply to the view’s template" doesn't really mean much to me, and even less after giving it a "list" and seeing python complain about callables ;) Might anyone give me an example of a dict I might pass a generic view? Thanks guys! signature.asc Description: OpenPGP digital signature
Re: Problem with multiple django versions on mod_python
Thanks for your help, Russ. I updated mod_python (which was probably overdue anyway), but that didn't fix the problem. I've been looking for other signs but nothing has surfaced yet. If anybody else can recall a similar experience, please let me know! -rob On Jul 18, 9:07 pm, "Russell Keith-Magee" <[EMAIL PROTECTED]> wrote: > On 7/19/07, oggie rob <[EMAIL PROTECTED]> wrote: > > > > > Please, if you've seen the same issue or have any helpful ideas to try > > to stop the error, let me know. > > I think I've seen the same problem (or, at least, an analogous one). > Unfortunately, I can't provide much by way of helpful debug or > solution - the sysadmin that identified the problem for us isn't > around for me to ask him for more details. > > As I recall, the problem was mod_python. Older versions of mod_python > had some sort of issue with caching python instances. As a result, if > you deployed two different versions of Django, the version of Django > that was provided to a given request was determined by the thread that > served the request. If the first request served by a thread used the > old version of Django, that was the version that was used for all > subsequent requests on that thread, regardless of the version that was > required to satisfy the request. > > I believe we fixed the problem by updating mod_python, but I'm not > completely certain on that. > > I know that this is all vague and ambiguous help - sorry I can't be > more specific. > > Yours, > Russ Magee %-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Random IndexError
Hi there! I'm getting random IndexErrors. This has risen when loading templatetags, or just when applying a filter to a var in a template. The traceback doesn't mean much to me, and I'm pretty unsure what may have been the reason for this error. Any help? Mod_python error: "PythonHandler django.core.handlers.modpython" Traceback (most recent call last): File "/usr/lib/python2.5/site-packages/mod_python/apache.py", line 299, in HandlerDispatch result = object(req) File "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", line 178, in handler return ModPythonHandler()(req) File "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", line 151, in __call__ response = self.get_response(request) File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py", line 111, in get_response return debug.technical_500_response(request, *sys.exc_info()) File "/usr/lib/python2.5/site-packages/django/views/debug.py", line 104, in technical_500_response pre_context_lineno, pre_context, context_line, post_context = _get_lines_from_file(filename, lineno, 7, loader, module_name) File "/usr/lib/python2.5/site-packages/django/views/debug.py", line 209, in _get_lines_from_file context_line = source[lineno].strip('\n') IndexError: list index out of range signature.asc Description: OpenPGP digital signature
Re: Problem with multiple django versions on mod_python
In case the problem lies in manipulating the python path inside a section, perhaps you could play another trick to load the different versions of django. I am doing as follows, though, not with Location tags but in VirtualHost sections, and it works for me: Somewhere on the python path, there is a subdirectory, django_versions. In there, several django trees exist. On the same level as django_versions subdirectory i have wrapper modules, one for each django version i need, named django_trunk.py, django_096.py, and so on. The wrapper code reads: ## import imp, os django = imp.load_module( "django", *imp.find_module("django", [os.path.join( os.path.dirname(__file__), "django_versions", "django- trunk" )] ) ) del imp, os all together, the layout is: /python-path/django_trunk.py /python-path/django_someversion.py /python-path/django_vresions/ /python-path/django_versions/django-trunk/django /python-path/django_vresions/django-someversion/django Note, there is no need to have an __init__.py inside django_versions, since the path munging is done in the wrapper module, where the required django module is loaded from a temporary fixed path set up dynamically. To use this, a second wrapper file is needed for the mod_python handler. This one is named django_trunk_handler.py and should be put somewhere on your python path as well: import django_trunk as django from django.core.handlers.modpython import handler And analogous to that, you can have django_someversion_handler.py: import django_someversion as django from django.core.handlers.modpython import handler Now, in httpd.conf, this comes together: ... PythonHandler django_trunk_handler PythonInterpreter version1 ... PythonHandler django_someversion_handler PythonInterpreter version2 Finally, you might want to have different manage.py stubs with an extra first line importing the right django module as django into the namespace to get going. Best regards... Niels On Jul 19, 12:46 pm, oggie rob <[EMAIL PROTECTED]> wrote: > Thanks for your help, Russ. I updated mod_python (which was probably > overdue anyway), but that didn't fix the problem. I've been looking > for other signs but nothing has surfaced yet. > If anybody else can recall a similar experience, please let me know! > > -rob > > On Jul 18, 9:07 pm, "Russell Keith-Magee" <[EMAIL PROTECTED]> > wrote: > > > > > On 7/19/07, oggie rob <[EMAIL PROTECTED]> wrote: > > > > Please, if you've seen the same issue or have any helpful ideas to try > > > to stop the error, let me know. > > > I think I've seen the same problem (or, at least, an analogous one). > > Unfortunately, I can't provide much by way of helpful debug or > > solution - the sysadmin that identified the problem for us isn't > > around for me to ask him for more details. > > > As I recall, the problem was mod_python. Older versions of mod_python > > had some sort of issue with caching python instances. As a result, if > > you deployed two different versions of Django, the version of Django > > that was provided to a given request was determined by the thread that > > served the request. If the first request served by a thread used the > > old version of Django, that was the version that was used for all > > subsequent requests on that thread, regardless of the version that was > > required to satisfy the request. > > > I believe we fixed the problem by updating mod_python, but I'm not > > completely certain on that. > > > I know that this is all vague and ambiguous help - sorry I can't be > > more specific. > > > Yours, > > Russ Magee %-)- Hide quoted text - > > - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: newforms and models unique=True validation
+1 it works, perfect (I just change the self.cleaned_data into self.clean_data). Now when you showed me the trick I was able to track it in docs as well, unfortunately I'm using 0.96 and http://www.djangoproject.com/documentation/0.96/newforms/ is much different to http://www.djangoproject.com/documentation/newforms/ Is there anything coming into django that would provide validation of unique=True out of the box? Anyway thank you very much On Jul 18, 8:42 pm, Nathan Ostgard <[EMAIL PROTECTED]> wrote: > You want to create a BaseForm to specify in your form_for_model call. > You could do something like: > > from django import newforms as forms > > class MyBaseForm(forms.BaseForm): > def clean_myfield(self): > if > MyModel.objects.filter(myfield=self.cleaned_data['myfield']).count(): > raise forms.ValidationError('some error message') > > MyForm = forms.form_for_model(MyModel, form=MyBaseForm) > > > Nathan Ostgard > > On Jul 18, 7:06 am, stereoit <[EMAIL PROTECTED]> wrote: > > > Hi, > > I have model with field that has attribute unique set to True. I know > > newforms are not able to handle such a validation as this is DB > > related. However I read at newforms doc page that it is possible to > > provide method called clean_() that can do custom validation. > > My problem is that method is supposed to access the data via > > self.cleaned_date and I create form by using form_for_model hence I do > > not know how to write such a method. > > > Can anyone point me to right direction or best practice? Handling this > > at form.save() seem not right to me. > > > My idea was to create custom validation method that would try tu pull > > object from DB with set to same as in > > cleaned_data['fieldname'] and if it exists it would raise > > ValidationError. But I have no clue how to do that at the moment. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Random IndexError
This might mean your sourcefile uses '\r' for newlines which isn't handled correctly by django. If that's the case, this might be worth filing a ticket, i think. On Jul 19, 1:20 pm, Chris Hoeppner <[EMAIL PROTECTED]> wrote: > Hi there! > > I'm getting random IndexErrors. This has risen when loading > templatetags, or just when applying a filter to a var in a template. The > traceback doesn't mean much to me, and I'm pretty unsure what may have > been the reason for this error. > > Any help? > > Mod_python error: "PythonHandler django.core.handlers.modpython" > > Traceback (most recent call last): > > File "/usr/lib/python2.5/site-packages/mod_python/apache.py", line > 299, in HandlerDispatch > result = object(req) > > File > "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", > line 178, in handler > return ModPythonHandler()(req) > > File > "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", > line 151, in __call__ > response = self.get_response(request) > > File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py", > line 111, in get_response > return debug.technical_500_response(request, *sys.exc_info()) > > File "/usr/lib/python2.5/site-packages/django/views/debug.py", line > 104, in technical_500_response > pre_context_lineno, pre_context, context_line, post_context = > _get_lines_from_file(filename, lineno, 7, loader, module_name) > > File "/usr/lib/python2.5/site-packages/django/views/debug.py", line > 209, in _get_lines_from_file > context_line = source[lineno].strip('\n') > > IndexError: list index out of range > > signature.asc > 1KDownload --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Random IndexError
You're right, they was ending with '\r'. Should I file a ticket? How's that done? Never done it before. Niels escribió: > This might mean your sourcefile uses '\r' for newlines which isn't > handled correctly by django. If that's the case, this might be worth > filing a ticket, i think. > > On Jul 19, 1:20 pm, Chris Hoeppner <[EMAIL PROTECTED]> wrote: >> Hi there! >> >> I'm getting random IndexErrors. This has risen when loading >> templatetags, or just when applying a filter to a var in a template. The >> traceback doesn't mean much to me, and I'm pretty unsure what may have >> been the reason for this error. >> >> Any help? >> >> Mod_python error: "PythonHandler django.core.handlers.modpython" >> >> Traceback (most recent call last): >> >> File "/usr/lib/python2.5/site-packages/mod_python/apache.py", line >> 299, in HandlerDispatch >> result = object(req) >> >> File >> "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", >> line 178, in handler >> return ModPythonHandler()(req) >> >> File >> "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", >> line 151, in __call__ >> response = self.get_response(request) >> >> File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py", >> line 111, in get_response >> return debug.technical_500_response(request, *sys.exc_info()) >> >> File "/usr/lib/python2.5/site-packages/django/views/debug.py", line >> 104, in technical_500_response >> pre_context_lineno, pre_context, context_line, post_context = >> _get_lines_from_file(filename, lineno, 7, loader, module_name) >> >> File "/usr/lib/python2.5/site-packages/django/views/debug.py", line >> 209, in _get_lines_from_file >> context_line = source[lineno].strip('\n') >> >> IndexError: list index out of range >> >> signature.asc >> 1KDownload > > > --~--~-~--~~~---~--~~ > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-users@googlegroups.com > To unsubscribe from this group, send email to [EMAIL PROTECTED] > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en > -~--~~~~--~~--~--~--- > signature.asc Description: OpenPGP digital signature
Re: Random IndexError
Well, that should be explained in http://www.djangoproject.com/documentation/contributing/#reporting-bugs And after following the do's and avoiding the don'ts, you would proceed at http://code.djangoproject.com/newticket Best, Niels On Jul 19, 2:33 pm, Chris Hoeppner <[EMAIL PROTECTED]> wrote: > You're right, they was ending with '\r'. Should I file a ticket? How's > that done? Never done it before. > > Niels escribió: > > > > > This might mean your sourcefile uses '\r' for newlines which isn't > > handled correctly by django. If that's the case, this might be worth > > filing a ticket, i think. > > > On Jul 19, 1:20 pm, Chris Hoeppner <[EMAIL PROTECTED]> wrote: > >> Hi there! > > >> I'm getting random IndexErrors. This has risen when loading > >> templatetags, or just when applying a filter to a var in a template. The > >> traceback doesn't mean much to me, and I'm pretty unsure what may have > >> been the reason for this error. > > >> Any help? > > >> Mod_python error: "PythonHandler django.core.handlers.modpython" > > >> Traceback (most recent call last): > > >> File "/usr/lib/python2.5/site-packages/mod_python/apache.py", line > >> 299, in HandlerDispatch > >> result = object(req) > > >> File > >> "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", > >> line 178, in handler > >> return ModPythonHandler()(req) > > >> File > >> "/usr/lib/python2.5/site-packages/django/core/handlers/modpython.py", > >> line 151, in __call__ > >> response = self.get_response(request) > > >> File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py", > >> line 111, in get_response > >> return debug.technical_500_response(request, *sys.exc_info()) > > >> File "/usr/lib/python2.5/site-packages/django/views/debug.py", line > >> 104, in technical_500_response > >> pre_context_lineno, pre_context, context_line, post_context = > >> _get_lines_from_file(filename, lineno, 7, loader, module_name) > > >> File "/usr/lib/python2.5/site-packages/django/views/debug.py", line > >> 209, in _get_lines_from_file > >> context_line = source[lineno].strip('\n') > > >> IndexError: list index out of range > > >> signature.asc > >> 1KDownload > > > > > > > signature.asc > 1KDownload- Hide quoted text - > > - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Unicode chars in CharField
Hi there! I'm getting this whenever I try to use some non-ascii character in a CharField. I know this has something to do with the unicode() function, but my python knowledge doesn't get me that far. Thanks everyone! Traceback (most recent call last): File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py" in get_response 77. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.5/site-packages/django/contrib/admin/views/decorators.py" in _checklogin 55. return view_func(request, *args, **kwargs) File "/usr/lib/python2.5/site-packages/django/views/decorators/cache.py" in _wrapped_view_func 39. response = view_func(request, *args, **kwargs) File "/usr/lib/python2.5/site-packages/django/contrib/admin/views/main.py" in add_stage 263. LogEntry.objects.log_action(request.user.id, ContentType.objects.get_for_model(model).id, pk_value, force_unicode(new_object), ADDITION) File "/usr/lib/python2.5/site-packages/django/utils/encoding.py" in force_unicode 40. s = unicode(str(s), encoding, errors) UnicodeEncodeError at /admin/anuncios/entry/add/ 'ascii' codec can't encode character u'\xc1' in position 0: ordinal not in range(128) signature.asc Description: OpenPGP digital signature
4 beginner's questions
Hi, Coming from a Java background, I introduced Django in my company for a new web application. So far, we made great progress and web development suddenly was fun again. Unfortunately, it feels like all time I save because of Django, is spent on searching for an IDE (I still haven't found something really usable), reading the doc and solving trivial Python problems. I hope this will get better once I have more experience with Python. I've a few questions regarding Django I'd like to ask in this and future mails. 1) It is important for me to recreate my environment from scratch (that is, from the VCS). I'd like to have a working application after calling "syncdb". For my own application, I've create an initial_data fixture. But I'd like to recreate users and permissions, too. Is this possible? I looked into django/core/management.py and it seems that "load_data" simple enumerates the installed application so if I want to create a fixture for "auth", the initial_data file must be located inside the django installation. This isn't an option. Furthermore, it seems that "syncdb" always asks for an admin account on the console. Can I somehow suppress that question? Instead, I'd like to load some saved fixture. 2) I'd like to run batch application against our database (periodically using cron). Of course, I'd like to use the same database abstraction as Django uses, so I tried to find a way to initialize the system. What's the recommended way to access models from outside of views? I came up with these lines (conveniently located inside the project folder): #!/usr/bin/env python ... if __name__ == '__main__': from django.core.management import setup_environ import settings PROJECT_DIRECTORY = setup_environ(settings) from demo.models import Demo d = Demo.objects.get(...) ... d.save() 3) I need to create an object with a unique random id - and I would prefer not to use the database specific SQL layer. What's the best way to do it? My naive approach is to declare the id field unique and simply try to insert objects until I get no error. The documentation says [unique] "is enforced at the database level" but it unfortunately does not describe what happens if the constraint is violated. Will this always raise an IntegrityError? 4) I'd like to specify the file name of an uploaded file. Right now, the original filename is kept and I think, this could cause problems if two people upload a file with the same name at the same time. I tried to understand the file upload process in the Django source but there was too much meta magic for my brain. However, it seems that the current documentation doesn't tell the whole story. It seems, that there is a save_FOO_file() in addition to the documentation tree get_FOO_xxx methods... My guess is that manipulators.py is responsible for saving the uploaded file. ... Wait, I think, _save_FIELD_file() will eventually save the file and yes, that while loop is obviously not threadsafe! So I need to set the filename myself. But how? -- Stefan Matthias Aust --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Debugging file uploads
Is this something I should file an issue for? The Django debug HTML page is great for finding bugs in templates and view functions. However, if you have an error in a view function with a request object that contains a - say - 200MB file object, well, then your browser dies a slow and painful death. At least my trusted Firefox does. Is there something I can configure? Let's say an upper limit for the number bytes printed for a byte array? Perhaps adding a cut filter to the pprint filter in django\views\debug.py? And I wish it would be possible to edit the shown code just in place :) What I know about Python so far, this should be possible, shouldn't it? If you can load and display the source code, you must be able to save a modified version to the same location... And, well, syntax coloring would be nice... no just kidding... -- Stefan Matthias Aust --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: 4 beginner's questions
Stefan Matthias Aust wrote: > Hi, > > Coming from a Java background, I introduced Django in my company for a > new web application. So far, we made great progress and web > development suddenly was fun again. Unfortunately, it feels like all > time I save because of Django, is spent on searching for an IDE (I > still haven't found something really usable), reading the doc and > solving trivial Python problems. I hope this will get better once I > have more experience with Python. > > I've a few questions regarding Django I'd like to ask in this and future > mails. > > 1) It is important for me to recreate my environment from scratch > (that is, from the VCS). I'd like to have a working application after > calling "syncdb". For my own application, I've create an initial_data > fixture. But I'd like to recreate users and permissions, too. > > Is this possible? > > I looked into django/core/management.py and it seems that "load_data" > simple enumerates the installed application so if I want to create a > fixture for "auth", the initial_data file must be located inside the > django installation. This isn't an option. Furthermore, it seems that > "syncdb" always asks for an admin account on the console. Can I > somehow suppress that question? Instead, I'd like to load some saved > fixture. > > 2) I'd like to run batch application against our database > (periodically using cron). Of course, I'd like to use the same > database abstraction as Django uses, so I tried to find a way to > initialize the system. > > What's the recommended way to access models from outside of views? > > I came up with these lines (conveniently located inside the project folder): > > #!/usr/bin/env python > ... > if __name__ == '__main__': >from django.core.management import setup_environ >import settings >PROJECT_DIRECTORY = setup_environ(settings) > >from demo.models import Demo >d = Demo.objects.get(...) >... >d.save() > I just made this. it should answer most of 1 and 2. http://code.djangoproject.com/wiki/DatabaseReset > 3) I need to create an object with a unique random id - and I would > prefer not to use the database specific SQL layer. What's the best way > to do it? My naive approach is to declare the id field unique and > simply try to insert objects until I get no error. The documentation > says [unique] "is enforced at the database level" but it unfortunately > does not describe what happens if the constraint is violated. Will > this always raise an IntegrityError? > Why a unique _random_ id. seems odd. knowing the use case might help. > 4) I'd like to specify the file name of an uploaded file. Right now, > the original filename is kept and I think, this could cause problems > if two people upload a file with the same name at the same time. > > I tried to understand the file upload process in the Django source but > there was too much meta magic for my brain. However, it seems that the > current documentation doesn't tell the whole story. It seems, that > there is a save_FOO_file() in addition to the documentation tree > get_FOO_xxx methods... My guess is that manipulators.py is responsible > for saving the uploaded file. ... Wait, I think, _save_FIELD_file() > will eventually save the file and yes, that while loop is obviously > not threadsafe! So I need to set the filename myself. But how? > good Q hopfully someone can answer it. :) Carl K --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem when inserting into a table with a MySQL auto_increment primary key
On Jul 18, 6:14 pm, Nis Jørgensen <[EMAIL PROTECTED]> wrote: > AnaReis skrev:> Hi all, > > I have a problem when inserting a register into this table that I'm > > working with. > > This table belongs to a MySQL database and the storage engine is > > MyISAM. The database that I'm using is a legacy database and I can't > > change it in any way. > > When I insert a register into the table it's MySQL who generates the > > primary key for me. Which means that I fill all the required table > > fields and leave the primary key field empty for MySQL to fill when I > > insert the record. The problem is, since the ".save()" method doesn't > > return any value there is no way for me to give any confirmation for > > the user if the register was inserted or not. > > Have you added the primary key to the model, like this: > > my_legacy_id = AutoField() > > If you do, I believe you will be able to read the value of the field > after calling .save(). > At least you can with the standard id field when using postgresql. > > Nis Hi Thanks for your help! I had put the AutoField() part but forgot to add the "_id" in the end of the field, that's why it wasn't working. Thanks again! :) Ana --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: 4 beginner's questions
On 7/19/07, Stefan Matthias Aust <[EMAIL PROTECTED]> wrote: > 1) It is important for me to recreate my environment from scratch > (that is, from the VCS). I'd like to have a working application after > calling "syncdb". For my own application, I've create an initial_data > fixture. But I'd like to recreate users and permissions, too. If you don't mind calling manage.py loaddata a few more times, yes. The parameter there is the name of the fixture, *not* the name of an app. http://www.djangoproject.com/documentation/django-admin/#loaddata-fixture-fixture Fixtures in other dirs: http://www.djangoproject.com/documentation/settings/#fixture-dirs ... > it seems that > "syncdb" always asks for an admin account on the console. Can I > somehow suppress that question? Instead, I'd like to load some saved > fixture. --noinput http://www.djangoproject.com/documentation/django-admin/#noinput > What's the recommended way to access models from outside of views? > What you have is pretty good, but do this, too, in order to make sure all models are loaded (so that descriptors for relationships are contributed to reverse models: from django.db.models import get_models get_models() > 3) I need to create an object with a unique random id - http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/163604 > "is enforced at the database level" but it unfortunately > does not describe what happens if the constraint is violated. Will > this always raise an IntegrityError? Yes. It just doesn't let you insert dupes; there is no id-generation fallback (unless it's an autofield). ... Leaving #4 unanswered; your understanding seems correct. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Using Sessions to display the contents of a shopping cart
I have the following view: def showcart(request, style_id, choice_id): s = Style.objects.get(id=style_id) c = Choice.objects.get(id=choice_id) x = request.session ?? # I want to add s and c to my session? return render_to_response('show_test.html', {'mychoice': x}) // Everytime the user adds something to their shopping cart then this view will be accessed. I want the view to store the two parameters (s and c) into my request.session so that the data in the session can be showed when the website visitor checks out. However, I'm not sure how to add these parameters to my session variable. I'm also not sure how to display all the session data. Thanks for any help --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Using Sessions to display the contents of a shopping cart
On 7/19/07, Greg <[EMAIL PROTECTED]> wrote: > x = request.session ?? # I want to add s and c to my session? cart = request.session.get('cart', []) cart.append({'style':s,'choice'c}) request.session['cart']=cart But, fundamentally, putting cart info in session is a bad idea; people switch computers (and thus cookies; sessions) fairly often. Also, people delete cookies for good reasons. I'd be severely pissed if my amazon wishlist went away when I deleted cookies. > I'm also not sure how > to display all the session data. http://www.djangoproject.com/documentation/authentication/#authentication-data-in-templates http://www.djangoproject.com/documentation/templates_python/#subclassing-context-requestcontext http://www.djangoproject.com/weblog/2005/sep/24/newshortcuts/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Blog engine
If it is so easy to create a blogging application with Django, then this should be an argument for a standard application, not against it IMHO. At minimum, it could become a nice example application, either as part of the django distribution or as a separate download. And if it is still easy enough, make it a Wordpress killer. Make it as easy to install and to use as Wordpress, being an example for the power of elegance of Django (and Python) - something like Typo or Mephisto for Rails. Another important argument for one de-facto standard are plug-ins and templates. There are zillions of templates (even nice ones) for Wordpress. And you can add dozens if not hundreds of plugins to further customize or extend the software. If everybody is creating his or her own solution, there will not be no synergy, no community, no attention. Rails became so popular, because people *saw* how easy it was to create something. Just telling them isn't enough :) Stefan --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django advocacy in a commercial environment
On Jul 19, 1:19 am, "Jon Atkinson" <[EMAIL PROTECTED]> wrote: > If anyone has any good resources which show off the power of Django > (and by association, the benefits of PHP), then please share them with > us. Where I work we migrated away from PHP to Django with great success but it depends on your environment. For us the Django admin was a huge factor since we have teams entering content and the default Django admin was way better than anything we had going so far. There are some performance articles and blog posts, for example: http://wiki.rubyonrails.org/rails/pages/Framework+Performance We benefitted from the Django workflow with its built-in web server. There's also the fact that Django is improving everyday which translates into free new features or things that were hard to do are easy now. For example, databrowse or djangosnippets. And we love Python and also love our jobs more because of the switch. :) Those aren't really resources for you but depending on your in-house requirements it's not hard to find resources online to help guide the decision. When I had to convince my superiors of the choice, I wrote a PDF document looking at the best choices in each language (Ruby, PHP, Python) and Django won out for our particular needs. -Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Blog engine
Why not start a Google code repository and see how many people want to chip in and help. This comes up often enough that it sounds like there's enough interest. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Blog engine
Stefan Matthias Aust escribió: > If it is so easy to create a blogging application with Django, then > this should be an argument for a standard application, not against it > IMHO. > > At minimum, it could become a nice example application, either as part > of the django distribution or as a separate download. And if it is > still easy enough, make it a Wordpress killer. Make it as easy to > install and to use as Wordpress, being an example for the power of > elegance of Django (and Python) - something like Typo or Mephisto for > Rails. > > Another important argument for one de-facto standard are plug-ins and > templates. There are zillions of templates (even nice ones) for > Wordpress. And you can add dozens if not hundreds of plugins to > further customize or extend the software. > > If everybody is creating his or her own solution, there will not be no > synergy, no community, no attention. Rails became so popular, > because people *saw* how easy it was to create something. Just telling > them isn't enough :) > > Stefan > > --~--~-~--~~~---~--~~ > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-users@googlegroups.com > To unsubscribe from this group, send email to [EMAIL PROTECTED] > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en > -~--~~~~--~~--~--~--- > Actually... It took me 30 minutes to get my blog engine running, without the design. And, there's no need to "make" for plugins. A Django app *is* a plugin to the django framework itself, if you'd like to see it that way. I have a common repository on the python path with things I tend to use often, like typogrify, markdown, and feedparser. You can just load them from any other app. There would still be the problem of people wanting to "one-click-install" plugins and themes. But why would such a person even think about using a framework instead of wordpress? And I still think that there's absolutely no need to make a de-facto standard blog app in django. You gotta use what works best for you, man. signature.asc Description: OpenPGP digital signature
Re: 4 beginner's questions
Carl, Jeremy, Thanks for your answers. Carl wrote: > I just made this. it should answer most of 1 and 2. > http://code.djangoproject.com/wiki/DatabaseReset Somehow, it seems to me that there should be a standard utility function to initialize the system for command line tools. I saw your "nifty trick" twice and I used a similar approach. Your migrate.py script seems to be very specific to your mysql-specific use case. Jeremy wrote: > > What's the recommended way to access models from outside of views? > What you have is pretty good, but do this, too, in order to make sure > all models are loaded (so that descriptors for relationships are > contributed to reverse models: [...] Thanks, I changed my code. > > 3) I need to create an object with a unique random id - > > http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/163604 Oh, it's not creating the ID, my question was whether I can safely assume that I will always get an IntegrityError (and nothing else) and whether just inserting stuff and catching errors is the recommended Pythonic way. -- Stefan Matthias Aust // Truth until paradox --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Blog engine
Chris, 2007/7/19, Chris Hoeppner <[EMAIL PROTECTED]>: > There would still be the problem of people wanting to > "one-click-install" plugins and themes. But why would such a person even > think about using a framework instead of wordpress? My point was that - assuming the Django community wants to spread the word that Django is the best answer to whatever question - that you have to target people who just want to use an application and demonstrate the greatness. This requires a momentum, a community. If you just not want to bother those people and do not want to be bothered, then, well, let them use Wordpress :) All I tried to say is perhaps that people who are looking for a simple to use blogging solution might want to get there with the least amount of work. Installing Wordpress is damn easy. Everybody with "computer knowledge" therefore typically recommends Wordpress (let's not dive into the discussion here that PHP is nearly always preinstalled and Python not). Would you recommend your non-technical friends to go and install Python and Django, then to compile a common repository of stuff grabbed from all over the web and then to write their own custom blogging solution because it's so easy? I guess not :) -- Stefan Matthias Aust --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Blog engine
Stefan Matthias Aust escribió: > Chris, > > 2007/7/19, Chris Hoeppner <[EMAIL PROTECTED]>: > >> There would still be the problem of people wanting to >> "one-click-install" plugins and themes. But why would such a person even >> think about using a framework instead of wordpress? > > My point was that - assuming the Django community wants to spread the > word that Django is the best answer to whatever question - that you > have to target people who just want to use an application and > demonstrate the greatness. This requires a momentum, a community. > > If you just not want to bother those people and do not want to be > bothered, then, well, let them use Wordpress :) > > All I tried to say is perhaps that people who are looking for a simple > to use blogging solution might want to get there with the least amount > of work. Installing Wordpress is damn easy. Everybody with "computer > knowledge" therefore typically recommends Wordpress (let's not dive > into the discussion here that PHP is nearly always preinstalled and > Python not). > > Would you recommend your non-technical friends to go and install > Python and Django, then to compile a common repository of stuff > grabbed from all over the web and then to write their own custom > blogging solution because it's so easy? I guess not :) > Depends. If they're non-technical but willing to learn, yes. And I'd assist them. If they're just stupid and want it to "just plain work" then I'd tell them to go and buy a book about "windows for dummies". And I don't mean that I *would*, but more that I *have done many times*. Some of them come back after a while, knowing a bit more, and wanting to learn. Others just don't bother me ever again. I like both of them :-) signature.asc Description: OpenPGP digital signature
Re: Using Sessions to display the contents of a shopping cart
Hi Jeremy, On Thu, 19 Jul 2007 10:45:46 -0500 "Jeremy Dunck" <[EMAIL PROTECTED]> wrote: > > On 7/19/07, Greg <[EMAIL PROTECTED]> wrote: > > x = request.session ?? # I want to add s and c to my session? > > cart = request.session.get('cart', []) > cart.append({'style':s,'choice'c}) > > request.session['cart']=cart > > But, fundamentally, putting cart info in session is a bad idea; people > switch computers (and thus cookies; sessions) fairly often. Also, > people delete cookies for good reasons. I'd be severely pissed if my > amazon wishlist went away when I deleted cookies. but was is the solution if the user is not logged in ? At this point your only chance is a session bound cookie or I'm wrong ? Kindly regards Lutz Steinborn --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Colleen Robledo is out of the office
I will be out of the office starting Thu 07/19/2007 and will not return until Mon 07/23/2007. I will return emails as soon as possible Monday 7/23. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: 4 beginner's questions
Stefan Matthias Aust wrote: > Carl, Jeremy, > > Thanks for your answers. > > Carl wrote: > >> I just made this. it should answer most of 1 and 2. >> http://code.djangoproject.com/wiki/DatabaseReset > > Somehow, it seems to me that there should be a standard utility > function to initialize the system for command line tools. I saw your > "nifty trick" twice and I used a similar approach. I vote for ./manage.py -runscript myscript.py which apparently has been shot down in the past. > > Your migrate.py script seems to be very specific to your > mysql-specific use case. yes, but only for reading. The writes into django db are all via the django db api. The page is boarder line wiki worthy, but I got tired of pasting the same 3 files into dpaste.com :) Carl K --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Bulk data upload
>> I dislike CSV because it takes extra overhead to >> synchronize the flavors of them (how are quotes quoted? are >> values quoted? etc). > > Psst! Check out Python's built-in ``csv`` module > (http://docs.python.org/lib/module-csv.html); it handles all that > nastiness for you. I've used it before, and it is great...if the person on the receiving end also has the benefits of Python's CSV module ;) In the OP's case, this works because they're receiving the file and they've got Python. So yes, use python's built-in csv module and relax. However, if you're on the sending end, and your recipient *doesn't* have the benefit of Python's csv module, you need to expend brain cycles to explain the csv-flavor to the recipient. With tab-delimited, it's far less problematic (unless some bozo wants to transmit actual tabs in their data...then try pipe-delimited as alluded to in some early sample code in this thread...unless there are tabs *and* pipes in the data, in which case, you need to smack the pathological twit and then expend the brain cycles) -tim --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Question about comment_utils
Hi all, I'm using Django 0.96 and trying to use James Bennett's comment_utils with my blog application. When I add the CommentModerator subclass and 'moderator.register' statements to models.py, the ManyToManyField class attributes in the moderated class stop working. I keep getting the following error File "/home/web/python-2.4.4/lib/python2.4/site-packages/django/db/ models/query.py" in lookup_inner 938. raise TypeError, "Cannot resolve keyword '%s' into field" % name However, when I comment out the subclass and moderator.register statements, everything works again. Is anyone else seeing the same behavior? Should I be running the latest SVN version of Django to take advantage of comment_utils? Thanks, Shankar --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Does a pre/post_save signal know who is the user currently logged in?
I'm implementing a model modification history and the only thing it is lacking is saving the user who did the modification. A view knows the logged in user through request.user but i could not find if a signal has this information somewhere. Thanks in advance! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
forloop variables without for
Hi! In a project I get a set of images from a model, and then I display it on the template. In same template (but in another place), I just want to display first element of set, and number of objects given. Can I do it without adding those fields to views.py? I've found a way for doing first, but it isn't very efficient: In views: images = tImage.objects.filter(product=product_id) In template: {% for image in images %} {% if forloop.first %} {{ image.image }} {% endif %} {% endfor %} Thanks a lot! Marc --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Newforms, MultiSelect, "Hold Down Control" message.
Thanks for your reply, sorry I didn't get back to this sooner. > The string you're referring to is appended to the help_text of a > ManyToManyField in django.db.models.fields.related. It's not being > set by newforms, merely inherited. You also wouldn't be seeing it if > you were using CheckboxSelectMultiple, only if the normal HTML select > widget were being used. I'm definitely seeing this string generated by my descendant of CheckboxSelectMultiple, and I'm pretty sure I saw it when I was using a straight CheckboxSelectMultiple widget as well. It's not immediately clear why user-interface oriented instructions would be stored with the database model -- it seems to me that the user interface code (newforms or widgets) ought to handle this itself. I'm not comfortable subclassing Form, but I do understand using the help_text attribute. Since I wasn't aware it existed, I don't have any other information in there. -- Larry --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: forloop variables without for
Try {{ images.0.image }} Sean On Jul 19, 7:43 pm, Marc Garcia <[EMAIL PROTECTED]> wrote: > Hi! > > In a project I get a set of images from a model, and then I display it > on the template. In same template (but in another place), I just want > to display first element of set, and number of objects given. Can I do > it without adding those fields to views.py? > > I've found a way for doing first, but it isn't very efficient: > > In views: > images = tImage.objects.filter(product=product_id) > > In template: > {% for image in images %} > {% if forloop.first %} >{{ image.image }} > {% endif %} > {% endfor %} > > Thanks a lot! > Marc --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Simple Left Join in Django question???
I've tried to search for a solution to this problem for the last 2 hours and I can't seem to figure it out. I basically want to return a joined table from a queryset - formatted for my template. I can't seem to figure out how to do this with the Django database API. With SQL a join query works out to: ''' select project_portfolio.*, client.* from project_portfolio left join client on project_portfolio.id = client.id ''' with the following simplified models: class project_portfolio(models.Model): project_name_char = models.CharField() project_client = models.ForeignKey(client) class client(models.Model): client_name_char = models.CharField The challenge here seems to be that I have to return MULTIPLE project_portfolio objects and THEN get the "client" data - because NOT all "clients" have "project_portfolio(s)" Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How do I know if fastcgi is installed correctly? (using dreamhost)
As I said, I tried to follow the tutorial: In this directory /home/walterbyrd/django.niche-software.com I have these two files: 1. dispatch.fcgi sys.path += ['/home/walterbyrd/django.niche-software/django/ django_src'] sys.path += ['/home/walterbyrd/django.niche-software/django/ django_projects'] from fcgi import WSGIServer from django.core.handlers.wsgi import WSGIHandler import os os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' WSGIServer(WSGIHandler()).run() --- 2. dispatch.fcgi #!/usr/bin/env python import sys sys.path += ['/home/walterbyrd/django.niche-software/django/ django_src'] sys.path += ['/home/walterbyrd/django.niche-software/django/ django_projects'] from fcgi import WSGIServer from django.core.handlers.wsgi import WSGIHandler import os os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' WSGIServer(WSGIHandler()).run() [niagara]$ ls -a . .. .htaccess dispatch.fcgi django fcgi.py fcgi.pyc [niagara]$ cat .htaccess RewriteEngine On RewriteBase / RewriteRule ^(media/.*)$ - [L] RewriteRule ^(admin_media/.*)$ - [L] RewriteRule ^(dispatch\.fcgi/.*)$ - [L] RewriteRule ^(.*)$ dispatch.fcgi/$1 [L] --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Unicode chars in CharField
Chris Hoeppner escribió: > Hi there! > > I'm getting this whenever I try to use some non-ascii character in a > CharField. I know this has something to do with the unicode() function, > but my python knowledge doesn't get me that far. > > Thanks everyone! > > Traceback (most recent call last): > File "/usr/lib/python2.5/site-packages/django/core/handlers/base.py" in > get_response > 77. response = callback(request, *callback_args, **callback_kwargs) > File > "/usr/lib/python2.5/site-packages/django/contrib/admin/views/decorators.py" > in _checklogin > 55. return view_func(request, *args, **kwargs) > File "/usr/lib/python2.5/site-packages/django/views/decorators/cache.py" > in _wrapped_view_func > 39. response = view_func(request, *args, **kwargs) > File > "/usr/lib/python2.5/site-packages/django/contrib/admin/views/main.py" in > add_stage > 263. LogEntry.objects.log_action(request.user.id, > ContentType.objects.get_for_model(model).id, pk_value, > force_unicode(new_object), ADDITION) > File "/usr/lib/python2.5/site-packages/django/utils/encoding.py" in > force_unicode > 40. s = unicode(str(s), encoding, errors) > > UnicodeEncodeError at /admin/anuncios/entry/add/ > 'ascii' codec can't encode character u'\xc1' in position 0: ordinal > not in range(128) > This is being annoying. If I add to any model, and any of the fields contains some special char, it will save the object, but throw an error like the quoted one. If I want to edit the object in the admin, same thing. But it shows up fine in my views. Might this be some kind of bug? signature.asc Description: OpenPGP digital signature
Re: Question about comment_utils
On 7/19/07, Shankar <[EMAIL PROTECTED]> wrote: > Is anyone else seeing the same behavior? Should I be running the latest > SVN version of Django to take advantage of comment_utils? You should go here http://code.google.com/p/django-comment-utils/issues/list and paste in the code -- including your model and your Moderator subclass -- into an issue report; I use Google Code specifically because it gives me a free bug tracking application. -- "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Does a pre/post_save signal know who is the user currently logged in?
On 7/19/07, Xanthus <[EMAIL PROTECTED]> wrote: > A view knows the logged in user through request.user but i could not > find if a signal has this information somewhere. No, this information is not available in the default signals. This is because Django can be used completely independently of its authentication system and completely indepdendently of its HTTP request/response system (e.g., you can set up cron jobs, use Django as a backend to a non-web application, etc.); if the request object and auth system were that tightly coupled to the model layer, a lot of uses wouldn't be possible. -- "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How do I know if fastcgi is installed correctly? (using dreamhost)
A couple of things to check - what are the permissions on dispatch.fcgi? It needs to be executable, e.g. -rwxr-xr-x Also, make sure it does not have DOS mode CR-LF And, do you have debug set in your settings.py? On Jul 19, 2:04 pm, walterbyrd <[EMAIL PROTECTED]> wrote: > As I said, I tried to follow the tutorial: > > In this directory > > /home/walterbyrd/django.niche-software.com > > I have these two files: > > 1. dispatch.fcgi > sys.path += ['/home/walterbyrd/django.niche-software/django/ > django_src'] > sys.path += ['/home/walterbyrd/django.niche-software/django/ > django_projects'] > > from fcgi import WSGIServer > from django.core.handlers.wsgi import WSGIHandler > import os > > os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' > WSGIServer(WSGIHandler()).run() > > --- > > 2. dispatch.fcgi > #!/usr/bin/env python > > import sys > > sys.path += ['/home/walterbyrd/django.niche-software/django/ > django_src'] > sys.path += ['/home/walterbyrd/django.niche-software/django/ > django_projects'] > > from fcgi import WSGIServer > from django.core.handlers.wsgi import WSGIHandler > import os > > os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' > WSGIServer(WSGIHandler()).run() > [niagara]$ ls -a > . .. .htaccess dispatch.fcgi django fcgi.py fcgi.pyc > [niagara]$ cat .htaccess > RewriteEngine On > RewriteBase / > RewriteRule ^(media/.*)$ - [L] > RewriteRule ^(admin_media/.*)$ - [L] > RewriteRule ^(dispatch\.fcgi/.*)$ - [L] > RewriteRule ^(.*)$ dispatch.fcgi/$1 [L] --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Does a pre/post_save signal know who is the user currently logged in?
take a look at: http://code.djangoproject.com/wiki/CookBookThreadlocalsAndUser On 7/19/07, James Bennett <[EMAIL PROTECTED]> wrote: > > > On 7/19/07, Xanthus <[EMAIL PROTECTED]> wrote: > > A view knows the logged in user through request.user but i could not > > find if a signal has this information somewhere. > > No, this information is not available in the default signals. This is > because Django can be used completely independently of its > authentication system and completely indepdendently of its HTTP > request/response system (e.g., you can set up cron jobs, use Django as > a backend to a non-web application, etc.); if the request object and > auth system were that tightly coupled to the model layer, a lot of > uses wouldn't be possible. > > -- > "Bureaucrat Conrad, you are technically correct -- the best kind of > correct." > > > > -- Lic. José M. Rodriguez Bacallao Cupet - Todos somos muy ignorantes, lo que ocurre es que no todos ignoramos lo mismo. Recuerda: El arca de Noe fue construida por aficionados, el titanic por profesionales - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Question about comment_utils
Hi James, Thanks. Keep up the great work! Meanwhile, I'll submit an issue report. Shankar On Thu, 19 Jul 2007 13:12:04 -0500, James Bennett wrote: > On 7/19/07, Shankar <[EMAIL PROTECTED]> wrote: >> Is anyone else seeing the same behavior? Should I be running the latest >> SVN version of Django to take advantage of comment_utils? > > You should go here > > http://code.google.com/p/django-comment-utils/issues/list > > and paste in the code -- including your model and your Moderator > subclass -- into an issue report; I use Google Code specifically because > it gives me a free bug tracking application. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Simple Left Join in Django question???
I believe in your template you should be able to do something like: {% for p in project_portfolio_list %} {{ p.project_name_char }} {{ p.project_client.client_name_char }} {% endfor %} If you had a view with: context['project_portfolio_list'] = project_portfolio.objects.all() You'll also want to be familiar with this portion of the docs: http://www.djangoproject.com/documentation/db-api/#related-objects Hope that helps, Grant On Jul 19, 11:02 am, Joshua <[EMAIL PROTECTED]> wrote: > I've tried to search for a solution to this problem for the last 2 > hours and I can't seem to figure it out. > > I basically want to return a joined table from a queryset - formatted > for my template. > > I can't seem to figure out how to do this with the Django database > API. > > With SQL a join query works out to: > > ''' > select project_portfolio.*, client.* > from project_portfolio left join client > on project_portfolio.id = client.id > ''' > with the following simplified models: > > class project_portfolio(models.Model): > project_name_char = models.CharField() > project_client = models.ForeignKey(client) > > class client(models.Model): > client_name_char = models.CharField > > The challenge here seems to be that I have to return MULTIPLE > project_portfolio objects and THEN get the "client" data - because NOT > all "clients" have "project_portfolio(s)" > > Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Using Sessions to display the contents of a shopping cart
Lutz, Yea I don't plan on having the user login to purchase a product from me. So I guess Session's will work if that is the case. It looks like I will have to place a cookie on the visitor's computer using set_test_cookie() and test_cookie_worked() method's so that I'm able to tell the difference between two users that are adding products to the cart at the same time. Does anybody know of any problems with this solution? On Jul 19, 11:40 am, Lutz Steinborn <[EMAIL PROTECTED]> wrote: > Hi Jeremy, > > On Thu, 19 Jul 2007 10:45:46 -0500 > > "Jeremy Dunck" <[EMAIL PROTECTED]> wrote: > > > On 7/19/07, Greg <[EMAIL PROTECTED]> wrote: > > > x = request.session ?? # I want to add s and c to my session? > > > cart = request.session.get('cart', []) > > cart.append({'style':s,'choice'c}) > > > request.session['cart']=cart > > > But, fundamentally, putting cart info in session is a bad idea; people > > switch computers (and thus cookies; sessions) fairly often. Also, > > people delete cookies for good reasons. I'd be severely pissed if my > > amazon wishlist went away when I deleted cookies. > > but was is the solution if the user is not logged in ? > At this point your only chance is a session bound cookie or I'm wrong ? > > Kindly regards > Lutz Steinborn --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Multiple User profiles
Hi there! I just wanted to share opinions on this. I'm in the process of building a rather large site, that's going to expect quite some hits a day. So I want to to keep things as clean as possible. One never knows when I'll be getting my hands dirty again. The User(tm), can have a variable amount of profiles, depending on the sections in the site the user... uses. Just to picture it out: User1: * Base profile * Music profile * Food profile * Chat profile User2: * Base profile * Chat profile User3: * Base profile * Music profile And the list might go on... As you see, every user has a Base profile assigned, and any number of the other profiles. I have the AUTH_PROFILE_MODULE setting pointing to the Base profile, and then I'll load the other profile(s) as needed. I'd like everyone to share his/her insight about this kind of situation. Should I better throw all the data together into the base profile, or keep it separately? Is there a way to define multiple profile settings? signature.asc Description: OpenPGP digital signature
Re: Simple Left Join in Django question???
Thank you for your response I'm not familiar with the context object - I'll have to do some research. I have this working portfolioPage = client.objects.filter(project_portfolio__project_display_bit = True) It's returning the clients data - just not the data for the project_portfolio (it's not joining)? On Jul 19, 2:08 pm, gkelly <[EMAIL PROTECTED]> wrote: > I believe in your template you should be able to do something like: > > {% for p in project_portfolio_list %} > {{ p.project_name_char }} {{ p.project_client.client_name_char }} > {% endfor %} > > If you had a view with: > > context['project_portfolio_list'] = project_portfolio.objects.all() > > You'll also want to be familiar with this portion of the > docs:http://www.djangoproject.com/documentation/db-api/#related-objects > > Hope that helps, > Grant > > On Jul 19, 11:02 am, Joshua <[EMAIL PROTECTED]> wrote: > > > I've tried to search for a solution to this problem for the last 2 > > hours and I can't seem to figure it out. > > > I basically want to return a joined table from a queryset - formatted > > for my template. > > > I can't seem to figure out how to do this with the Django database > > API. > > > With SQL a join query works out to: > > > ''' > > select project_portfolio.*, client.* > > from project_portfolio left join client > > on project_portfolio.id = client.id > > ''' > > with the following simplified models: > > > class project_portfolio(models.Model): > > project_name_char = models.CharField() > > project_client = models.ForeignKey(client) > > > class client(models.Model): > > client_name_char = models.CharField > > > The challenge here seems to be that I have to return MULTIPLE > > project_portfolio objects and THEN get the "client" data - because NOT > > all "clients" have "project_portfolio(s)" > > > Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Authentication for application with subdomains
I know this topis has been discussed already but I stiil havent find solution. We would like to build up the application that will be used by many customers. After registration the customer will access application via its subdomain name: eg. cust1 = http://cust1.application.com cust2 = http://cust2.application.com etc. This approach requires that authentication should use subdomain name, username and password . How can be this scenario accomplished with django? I think its very common approach when one application is used by many customers and things must work dynamicly ... so using django 'sites' approach is not suitable. Thanks for any advice and hits. David --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
newbie question: generating javascript, avoiding trailing comma
DU: I am a newbie, and I'm working on a simple tutorial for other newbies. I am trying to generate some javascript, and I have the following code in my template: var crimes = [ {% for crime in crime_list %} [ {{crime.longitude}}, {{ crime.latitude }},'{{ crime.address }}','{{ crime.type }}','{{ crime.date }}'], {% endfor %} ]; When this template is rendered to a webpage, I can get something like the following: var crimes = [ [-78.817828,42.904851,'17 Rapin Place','homicide','2006-01-05'], [-78.889458,42.897707,'155 Pennsylvania Street','homicide','2006-04-17'], [-78.884766,42.915257,'446 West Ferry','homicide','2006-01-10'], ]; This is fine, but I think the trailing comma in the final array item is causing a javascript error in IE. Is there a way to rewrite my template code to avoid the trailing comma? Thanks in advance, cjl --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Authentication for application with subdomains
It's very simple to implement that application structure. For authentication you must set proper SESSION_COOKIE_DOMAIN variable in settings: http://www.djangoproject.com/documentation/settings/#session-cookie-domain For manage subdomains you can write you own middleware to parse request.META[ 'SERVER_NAME' ] value and setting some needed attributes to request then handle it in your views late. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: newbie question: generating javascript, avoiding trailing comma
There's a forloop.last variable that you could test. Eg: var crimes = [ {% for crime in crime_list %} [ {{crime.longitude}}, {{ crime.latitude }},'{{ crime.address }}','{{ crime.type }}','{{ crime.date }}'] {% if not forloop.last %},{% endif %} {% endfor %} ]; On Jul 19, 12:35 pm, cjl <[EMAIL PROTECTED]> wrote: > DU: > > I am a newbie, and I'm working on a simple tutorial for other > newbies. I am trying to generate some javascript, and I have the > following code in my template: > > var crimes = [ > {% for crime in crime_list %} > [ {{crime.longitude}}, > {{ crime.latitude }},'{{ crime.address }}','{{ crime.type }}','{{ crime.date > }}'], > {% endfor %} > ]; > > When this template is rendered to a webpage, I can get something like > the following: > > var crimes = [ > [-78.817828,42.904851,'17 Rapin > Place','homicide','2006-01-05'], > [-78.889458,42.897707,'155 Pennsylvania > Street','homicide','2006-04-17'], > [-78.884766,42.915257,'446 West > Ferry','homicide','2006-01-10'], > ]; > > This is fine, but I think the trailing comma in the final array item > is causing a javascript error in IE. Is there a way to rewrite my > template code to avoid the trailing comma? > > Thanks in advance, > cjl --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: newbie question: generating javascript, avoiding trailing comma
It would probably be easier if you processed crime_list in your view and generated a 'crimes' variable for use in your template. cjl wrote: > DU: > > I am a newbie, and I'm working on a simple tutorial for other > newbies. I am trying to generate some javascript, and I have the > following code in my template: > > var crimes = [ > {% for crime in crime_list %} > [ {{crime.longitude}}, > {{ crime.latitude }},'{{ crime.address }}','{{ crime.type }}','{{ crime.date > }}'], > {% endfor %} > ]; > > When this template is rendered to a webpage, I can get something like > the following: > > var crimes = [ > [-78.817828,42.904851,'17 Rapin > Place','homicide','2006-01-05'], > [-78.889458,42.897707,'155 Pennsylvania > Street','homicide','2006-04-17'], > [-78.884766,42.915257,'446 West > Ferry','homicide','2006-01-10'], > ]; > > This is fine, but I think the trailing comma in the final array item > is causing a javascript error in IE. Is there a way to rewrite my > template code to avoid the trailing comma? > > Thanks in advance, > cjl > > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Request Context and Generic Views
They all use RequestContext already. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: 4 beginner's questions
> Oh, it's not creating the ID, my question was whether I can safely > assume that I will always get an IntegrityError (and nothing else) and > whether just inserting stuff and catching errors is the recommended > Pythonic way. IntegrityError is what you will get on a unique conflict, yes. However, it seems like a poor solution to spam INSERTS until you get a valid ID. Why exactly do you need a random ID? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Date Widget (or date format) in newforms
Has anyone written a date widget with separate fields for day, month, and year (and, ideally, a calendar) for the newforms package? Failing that, is there any way to change the format in which the text widget used for dates displays and decodes the date. -MM-DD may be better in every way, but it doesn't work for this particular application's users. -- Larry --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django's User authentication
Jason F. McBrayer wrote: > james_027 <[EMAIL PROTECTED]> writes: > > > what if I need additional fields or methods for my apps? Do i inherit > > it or edit the user class? > > The standard approach is here: > http://www.b-list.org/weblog/2006/06/06/django-tips-extending-user-model I'm glad this came up, I've been struggling with it myself. I'd like to be able to edit the additional fields that I associated with the User (via my UserProfile class) from the admin interface, right inline with the rest of the User fields. So I took the advice in one of the comments in that thread. I won't pretend to comprehend it all, but it says: | class UserProfile(models.Model): | user = models.ForeignKey(User, edit_inline=models.TABULAR, num_in_admin=1,min_num_in_admin=1, max_num_in_admin=1,num_extra_on_change=0) | # ... my additional fields This produces an error when validating models, | Validating models... | keyapp.userprofile: At least one field in UserProfile should have core=True, because it's being edited inline by user.User. | 1 error found. Okay, so who am I to argue with an error message? I slap a "core=True," in there with it (on ALL the fields in UserProfile; anything less causes other problems), and it SEEMS to work! That is, there's another box in the admin interface for editing a User object, with my additional fields available to edit. Too good to be true, right? Right. :-( I can neither add a UserProfile nor edit the values of the UserProfile from the User-edit admin page. I know, I know, it was unreasonable to expect it to be THAT easy. But the fact that it DISPLAYS the fields from another table (and *pretends* to let me edit them even though it discards my changes) with so little work on my part makes me think it might work if I wasn't doing something wrong or dumb. /myproj/mainweb/settings.py: | INSTALLED_APPS = ( |'django.contrib.auth', |'django.contrib.contenttypes', |'django.contrib.sessions', |'django.contrib.sites', |'myproj.mainweb.myweb.myapp', # my stuff |'django.contrib.admin',# user-account administration interface (provided by Django) | ) | AUTH_PROFILE_MODULE = 'myapp.UserProfile' /myproj/mainweb/myweb/myapp/models.py: | from django.db import models | from django.contrib.auth.models import User | class UserProfile(models.Model): |user = models.ForeignKey(User, edit_inline=models.TABULAR, num_in_admin=1,min_num_in_admin=1, max_num_in_admin=1,num_extra_on_change=0, core=True) |ftv = models.CharField('Favorite TV Station', maxlength=4, core=True) |phone = models.CharField('Telephone Number', maxlength=24, core=True) | class Admin: |pass The UserProfile fields DO show up in the User-editing admin page, as input fields... but any input or changes to them are ignored/discarded. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: newbie question: generating javascript, avoiding trailing comma
Duc & Kevin: Thank you for your quick and accurate replies. It looks like I need to spend more time with the documentation. Kevin's solution fixed my problem. -CJL --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Request Context and Generic Views
As has been mentioned, they all use a RequestContext to begin with, but if you need additional custom variables to be exposed to your template, then you can pass them as a dict for the extra_context variable. On Jul 19, 5:08 am, Chris Hoeppner <[EMAIL PROTECTED]> wrote: > Hi there! > > How does it exactly work when I want a RequestContext to be used in a > generic view. There's the context_processors key in the dict you gotta > pass it, but "A list of template-context processors to apply to the > view's template" doesn't really mean much to me, and even less after > giving it a "list" and seeing python complain about callables ;) > > Might anyone give me an example of a dict I might pass a generic view? > > Thanks guys! > > signature.asc > 1KDownload --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Authentication for application with subdomains
Hi David, I'm just starting on an app with the same structure. I think the main problem here is that the username field has to be unique. One possible solution would be to append the domain name to the username before authentication. The user types in 'bob', then the system munges it to 'bob.sub.domain.com' before doing the validation. Anyone know of a less hackish answer? I know we can create custom authentication backends, but I don't see another way to let users have the same username across different subdomains. SH --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with multiple django versions on mod_python
Thanks for the tip, Niels. I tried that and it didn't work either. I got to thinking about how likely it would be that mod_python & interpreters were causing problems. I've used multiple interpreters for some time and haven't noticed any other strange behaviour. A little test by printing out the apache.interpreter showed that it always correctly used the specified interpreter. I started looking more at unicode. I thought it odd that it always propagated as a unicode translation error. After a bit of poking around, I found this line in the trunk version and I wondered if this might be causing some issues: django/db/backends/postgresql/base.py: cursor.execute("SET client_encoding to 'UNICODE'") Well I can't see why the encoding would be used in both installations, but I think that postgres interactions were causing the problem, rather than mod_python. To make a long story short, I switched to 0.91- bugfix, worked through the conflicts (which is why I hadn't upgraded earlier), and because it contains a UnicodeDatabaseWrapper, it now appears to work without problems. That was a doozy. Thanks all for your help! -rob On Jul 19, 4:27 am, Niels <[EMAIL PROTECTED]> wrote: > In case the problem lies in manipulating the python path inside a > section, perhaps you could play another trick to load the > different versions of django. I am doing as follows, though, not with > Location tags but in VirtualHost sections, and it works for me: > > Somewhere on the python path, there is a subdirectory, > django_versions. In there, several django trees exist. On the same > level as django_versions subdirectory i have wrapper modules, one for > each django version i need, named django_trunk.py, django_096.py, and > so on. The wrapper code reads: > > ## > import imp, os > django = imp.load_module( > "django", > *imp.find_module("django", [os.path.join( > os.path.dirname(__file__), "django_versions", "django- > trunk" > )] ) > ) > del imp, os > > all together, the layout is: > /python-path/django_trunk.py > /python-path/django_someversion.py > /python-path/django_vresions/ > /python-path/django_versions/django-trunk/django > /python-path/django_vresions/django-someversion/django > > Note, there is no need to have an __init__.py inside django_versions, > since the path munging is done in the wrapper module, where the > required django module is loaded from a temporary fixed path set up > dynamically. > > To use this, a second wrapper file is needed for the mod_python > handler. This one is named django_trunk_handler.py and should be put > somewhere on your python path as well: > > import django_trunk as django > from django.core.handlers.modpython import handler > > And analogous to that, you can have django_someversion_handler.py: > > import django_someversion as django > from django.core.handlers.modpython import handler > > Now, in httpd.conf, this comes together: > > ... > PythonHandler django_trunk_handler > PythonInterpreter version1 > > > ... > PythonHandler django_someversion_handler > PythonInterpreter version2 > > > Finally, you might want to have different manage.py stubs with an > extra first line importing the right django module as django into the > namespace to get going. > > Best regards... > > Niels > > On Jul 19, 12:46 pm, oggie rob <[EMAIL PROTECTED]> wrote: > > > Thanks for your help, Russ. I updated mod_python (which was probably > > overdue anyway), but that didn't fix the problem. I've been looking > > for other signs but nothing has surfaced yet. > > If anybody else can recall a similar experience, please let me know! > > > -rob > > > On Jul 18, 9:07 pm, "Russell Keith-Magee" <[EMAIL PROTECTED]> > > wrote: > > > > On 7/19/07, oggie rob <[EMAIL PROTECTED]> wrote: > > > > > Please, if you've seen the same issue or have any helpful ideas to try > > > > to stop the error, let me know. > > > > I think I've seen the same problem (or, at least, an analogous one). > > > Unfortunately, I can't provide much by way of helpful debug or > > > solution - the sysadmin that identified the problem for us isn't > > > around for me to ask him for more details. > > > > As I recall, the problem was mod_python. Older versions of mod_python > > > had some sort of issue with caching python instances. As a result, if > > > you deployed two different versions of Django, the version of Django > > > that was provided to a given request was determined by the thread that > > > served the request. If the first request served by a thread used the > > > old version of Django, that was the version that was used for all > > > subsequent requests on that thread, regardless of the version that was > > > required to satisfy the request. > > > > I believe we fixed the problem by updating mod_python, but I'm not > > > completely certain on that. > > > > I know that this is all vague and ambiguous help - sorry I can't be > > > more specific. > > > > Yours, > > > Russ Magee %-)- Hid
Re: Does a pre/post_save signal know who is the user currently logged in?
take a look at: http://code.djangoproject.com/wiki/CookBookThreadlocalsAndUser On 7/19/07, James Bennett <[EMAIL PROTECTED]> wrote: > > > On 7/19/07, Xanthus <[EMAIL PROTECTED]> wrote: > > A view knows the logged in user through request.user but i could not > > find if a signal has this information somewhere. > > No, this information is not available in the default signals. This is > because Django can be used completely independently of its > authentication system and completely indepdendently of its HTTP > request/response system (e.g., you can set up cron jobs, use Django as > a backend to a non-web application, etc.); if the request object and > auth system were that tightly coupled to the model layer, a lot of > uses wouldn't be possible. > > -- > "Bureaucrat Conrad, you are technically correct -- the best kind of > correct." > > > > -- Lic. José M. Rodriguez Bacallao Cupet - Todos somos muy ignorantes, lo que ocurre es que no todos ignoramos lo mismo. Recuerda: El arca de Noe fue construida por aficionados, el titanic por profesionales - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How do I know if fastcgi is installed correctly? (using dreamhost)
On Jul 19, 12:24 pm, FrankW <[EMAIL PROTECTED]> wrote: > A couple of things to check - what are the permissions on > dispatch.fcgi? > It needs to be executable, e.g. -rwxr-xr-x Permissions are correct. > Also, make sure it does not have DOS mode CR-LF No DOS mode CR-LF. > And, do you have debug set in your settings.py? from settings.py DEBUG = True TEMPLATE_DEBUG = DEBUG My file structure: django.niche-software.com/ --- dispatch.fcgi --- hello.fcgi --- .htaccess --- django/ -- django_media/ -- django_projects/ - myproject/ settings.py - sqlite-3.4.0 -- django_src/ -- django_templates The hello.fcgi I got from the dreamhost wiki: http://www.skweezer.net/bloglines/s.aspx/2/wiki.dreamhost.com/Special_~_Search?search=django&go=Go The hello.fcgi looks like this: #!/usr/bin/python2.3 from flup.server.fcgi import WSGIServer def test_app(environ, start_response): start_response('200 OK', [('Content-Type', 'text/plain')]) yield 'Hello, world!\n' WSGIServer(test_app).run() I tried running that, and got the same 500 error. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Simple Left Join in Django question???
Maybe I should have titled this how do I create a left join in Django syntax or with the Django db-API All the examples in the documentation let you retrieve the related object ONLY if you have ONE related object retrieved. On Jul 19, 2:18 pm, Joshua <[EMAIL PROTECTED]> wrote: > Thank you for your response > > I'm not familiar with the context object - I'll have to do some > research. > > I have this working > > portfolioPage = > client.objects.filter(project_portfolio__project_display_bit = True) > > It's returning the clients data - just not the data for the > project_portfolio (it's not joining)? > > On Jul 19, 2:08 pm, gkelly <[EMAIL PROTECTED]> wrote: > > > I believe in your template you should be able to do something like: > > > {% for p in project_portfolio_list %} > > {{ p.project_name_char }} {{ p.project_client.client_name_char }} > > {% endfor %} > > > If you had a view with: > > > context['project_portfolio_list'] = project_portfolio.objects.all() > > > You'll also want to be familiar with this portion of the > > docs:http://www.djangoproject.com/documentation/db-api/#related-objects > > > Hope that helps, > > Grant > > > On Jul 19, 11:02 am, Joshua <[EMAIL PROTECTED]> wrote: > > > > I've tried to search for a solution to this problem for the last 2 > > > hours and I can't seem to figure it out. > > > > I basically want to return a joined table from a queryset - formatted > > > for my template. > > > > I can't seem to figure out how to do this with the Django database > > > API. > > > > With SQL a join query works out to: > > > > ''' > > > select project_portfolio.*, client.* > > > from project_portfolio left join client > > > on project_portfolio.id = client.id > > > ''' > > > with the following simplified models: > > > > class project_portfolio(models.Model): > > > project_name_char = models.CharField() > > > project_client = models.ForeignKey(client) > > > > class client(models.Model): > > > client_name_char = models.CharField > > > > The challenge here seems to be that I have to return MULTIPLE > > > project_portfolio objects and THEN get the "client" data - because NOT > > > all "clients" have "project_portfolio(s)" > > > > Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Unicode problem while changing from 0.95 to latest developer version
Hello, I have done upgrade from 0.95 to svn developer version. One of my django apps using unicode characters does not start anymore, I get the following: -- Traceback (most recent call last): File "C:\Python24\lib\site-packages\django\core\servers \basehttp.py", line 278, in run self.result = application(self.environ, self.start_response) File "C:\Python24\lib\site-packages\django\core\servers \basehttp.py", line 620, in __call__ return self.application(environ, start_response) File "C:\Python24\lib\site-packages\django\core\handlers\wsgi.py", line 190, in __call__ response = self.get_response(request) File "C:\Python24\lib\site-packages\django\core\handlers\base.py", line 111, in get_response return debug.technical_500_response(request, *sys.exc_info()) File "C:\Python24\lib\site-packages\django\views\debug.py", line 141, in technical_500_response return HttpResponseServerError(t.render(c), mimetype='text/html') File "C:\Python24\lib\site-packages\django\template\__init__.py", line 181, in render return self.nodelist.render(context) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 736, in render bits.append(self.render_node(node, context)) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 754, in render_node result = node.render(context) File "C:\Python24\lib\site-packages\django\template\defaulttags.py", line 134, in render nodelist.append(node.render(context)) File "C:\Python24\lib\site-packages\django\template\defaulttags.py", line 228, in render return self.nodelist_true.render(context) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 736, in render bits.append(self.render_node(node, context)) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 764, in render_node raise wrapped TemplateSyntaxError: Caught an exception while rendering: 'utf8' codec can't decode bytes in position 833-834: invalid data Original Traceback (most recent call last): File "C:\Python24\lib\site-packages\django\template\__init__.py", line 754, in render_node result = node.render(context) File "C:\Python24\lib\site-packages\django\template\defaulttags.py", line 134, in render nodelist.append(node.render(context)) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 790, in render return self.filter_expression.resolve(context) File "C:\Python24\lib\site-packages\django\template\__init__.py", line 603, in resolve obj = func(obj, *arg_vals) File "C:\Python24\lib\site-packages\django\template \defaultfilters.py", line 25, in _dec args[0] = force_unicode(args[0]) File "C:\Python24\lib\site-packages\django\utils\encoding.py", line 42, in force_unicode s = unicode(s, encoding, errors) UnicodeDecodeError: 'utf8' codec can't decode bytes in position 833-834: invalid data -- The admin site works, I can browse and update the data base without any problems. My development PC runs Windows. Any idea what can be wrong? Regards, Piotr --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
schema evolution
Hey all, I've ported my schema evolution work from my SoC project last summer to Django v0.96. To use it, download the patch below, and run the following: $ cd //site-packages/django/ $ patch -p1 < ~//django_schema_evolution-v096patch.txt It should output the following: patching file core/management.py patching file db/backends/mysql/base.py patching file db/backends/mysql/introspection.py patching file db/backends/postgresql/base.py patching file db/backends/postgresql/introspection.py patching file db/backends/sqlite3/base.py patching file db/backends/sqlite3/introspection.py patching file db/models/fields/__init__.py patching file db/models/options.py To use it: $ cd // $ ./manage.py sqlevolve It should output something like this: BEGIN; ALTER TABLE `main_query` CHANGE COLUMN `accuracy` `accuracynew` numeric(10, 6) NULL; ALTER TABLE `main_query` ADD COLUMN `price` varchar(256) NULL; COMMIT; Assuming you have a model such as this: class Query(models.Model): query = models.CharField(maxlength=256, blank=False) accuracynew = models.FloatField(max_digits=10, decimal_places=6, null=True, blank=True, aka='accuracy') price = models.CharField(maxlength=256, null=True, blank=True) # new column Note the aka field where I changed the name of "accuracy" to "accuracynew". Let me know if you find any bugs. http://kered.org/blog/2007-07-19/django-schema-evolution/ http://kered.org/blog/wp-content/uploads/2007/07/django_schema_evolution-v096patch.txt -- Derek --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Authentication for application with subdomains
On Jul 19, 2:19 pm, David Marko <[EMAIL PROTECTED]> wrote: > I know this topis has been discussed already but I stiil havent find > solution. We would like to build up the application that will be used > by many customers. After registration the customer will access > application via its subdomain name: > eg. cust1 =http://cust1.application.com > cust2 =http://cust2.application.com > etc. > > This approach requires that authentication should use subdomain name, > username and password . How can be this scenario accomplished with > django? > I think its very common approach when one application is used by many > customers and things must work dynamicly ... so using django 'sites' > approach is not suitable. > > Thanks for any advice and hits. > > David If the username is unique to the subdomain, you either have to hack around the existing User model (as per SH's suggestion) or you need your own User model for your application (outside of the Django standard). I'd probably hack up the django User model and associate a CustomerUser model to it with the 'real' login, unique to the Customer. Once your user is created and associated to a subdomain, you can pull the subdomain from the request (as daev said, request.META['SERVER_NAME'] in middleware and make it available on the session (e.g., use it to look up a Customer object and make it available on the request or session). doug. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Using Sessions to display the contents of a shopping cart
On 7/19/07, Greg <[EMAIL PROTECTED]> wrote: > So I guess Session's will work if that is the case. It looks > like I will have to place a cookie on the visitor's computer using > set_test_cookie() and test_cookie_worked() method's so that I'm able > to tell the difference between two users that are adding products to > the cart at the same time. Does anybody know of any problems with > this solution? No, don't do that. The session framework already does that for you. If you use request.session, and the browser accepts cookies, you'll magically have values in request.session as set on previous requests. http://www.djangoproject.com/documentation/sessions/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Simple Left Join in Django question???
The Django db-api handles JOINs for you. It abstracts them into "forward", "backward" and "many-to-many" relationships (as documented on the page I linked before). Spend some time on the command line playing with these relationships and you'll see how you can navigate around your models through foreign keys and such. Also, if you need quicker answers, join #django on irc.freenode.net and paste your models at dpaste.com. There's always really bright, helpful people hanging around on there. Grant On Jul 19, 1:49 pm, Joshua <[EMAIL PROTECTED]> wrote: > Maybe I should have titled this how do I create a left join in Django > syntax or with the Django db-API > > All the examples in the documentation let you retrieve the related > object ONLY if you have ONE related object retrieved. > > On Jul 19, 2:18 pm, Joshua <[EMAIL PROTECTED]> wrote: > > > Thank you for your response > > > I'm not familiar with the context object - I'll have to do some > > research. > > > I have this working > > > portfolioPage = > > client.objects.filter(project_portfolio__project_display_bit = True) > > > It's returning the clients data - just not the data for the > > project_portfolio (it's not joining)? > > > On Jul 19, 2:08 pm, gkelly <[EMAIL PROTECTED]> wrote: > > > > I believe in your template you should be able to do something like: > > > > {% for p in project_portfolio_list %} > > > {{ p.project_name_char }} {{ p.project_client.client_name_char }} > > > {% endfor %} > > > > If you had a view with: > > > > context['project_portfolio_list'] = project_portfolio.objects.all() > > > > You'll also want to be familiar with this portion of the > > > docs:http://www.djangoproject.com/documentation/db-api/#related-objects > > > > Hope that helps, > > > Grant > > > > On Jul 19, 11:02 am, Joshua <[EMAIL PROTECTED]> wrote: > > > > > I've tried to search for a solution to this problem for the last 2 > > > > hours and I can't seem to figure it out. > > > > > I basically want to return a joined table from a queryset - formatted > > > > for my template. > > > > > I can't seem to figure out how to do this with the Django database > > > > API. > > > > > With SQL a join query works out to: > > > > > ''' > > > > select project_portfolio.*, client.* > > > > from project_portfolio left join client > > > > on project_portfolio.id = client.id > > > > ''' > > > > with the following simplified models: > > > > > class project_portfolio(models.Model): > > > > project_name_char = models.CharField() > > > > project_client = models.ForeignKey(client) > > > > > class client(models.Model): > > > > client_name_char = models.CharField > > > > > The challenge here seems to be that I have to return MULTIPLE > > > > project_portfolio objects and THEN get the "client" data - because NOT > > > > all "clients" have "project_portfolio(s)" > > > > > Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Does a pre/post_save signal know who is the user currently logged in?
On 19 jul, 17:33, "Lic. José M. Rodriguez Bacallao" <[EMAIL PROTECTED]> wrote: > take a look at:http://code.djangoproject.com/wiki/CookBookThreadlocalsAndUser Great! It worked like a charm! Thanks very much José. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
How to loop through a Dict to add values?
Hello, I have the following view def showcart(request, style_id, choice_id): s = Style.objects.get(id=style_id) c = Choice.objects.get(id=choice_id) cart = request.session.get('cart', []) cart.append({'style': s, 'choice': c}) request.session['cart'] = cart pr = 0 for a in cart: pr = pr + a['choice'] return render_to_response('show_test.html', {'mychoice': cart, 'p': pr}) / Whenever i try this I get the error: TypeError at /rugs/cart/1/4/ unsupported operand type(s) for +: 'int' and 'Choice' // Anybody know how I pull a value out of a dict and add it to a existing number? Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Simple Left Join in Django question???
Thanks for your help, again On Jul 19, 4:10 pm, gkelly <[EMAIL PROTECTED]> wrote: > The Django db-api handles JOINs for you. It abstracts them into > "forward", "backward" and "many-to-many" relationships (as documented > on the page I linked before). > > Spend some time on the command line playing with these relationships > and you'll see how you can navigate around your models through foreign > keys and such. > > Also, if you need quicker answers, join #django on irc.freenode.net > and paste your models at dpaste.com. There's always really bright, > helpful people hanging around on there. > > Grant > > On Jul 19, 1:49 pm, Joshua <[EMAIL PROTECTED]> wrote: > > > Maybe I should have titled this how do I create a left join in Django > > syntax or with the Django db-API > > > All the examples in the documentation let you retrieve the related > > object ONLY if you have ONE related object retrieved. > > > On Jul 19, 2:18 pm, Joshua <[EMAIL PROTECTED]> wrote: > > > > Thank you for your response > > > > I'm not familiar with the context object - I'll have to do some > > > research. > > > > I have this working > > > > portfolioPage = > > > client.objects.filter(project_portfolio__project_display_bit = True) > > > > It's returning the clients data - just not the data for the > > > project_portfolio (it's not joining)? > > > > On Jul 19, 2:08 pm, gkelly <[EMAIL PROTECTED]> wrote: > > > > > I believe in your template you should be able to do something like: > > > > > {% for p in project_portfolio_list %} > > > > {{ p.project_name_char }} {{ p.project_client.client_name_char }} > > > > {% endfor %} > > > > > If you had a view with: > > > > > context['project_portfolio_list'] = project_portfolio.objects.all() > > > > > You'll also want to be familiar with this portion of the > > > > docs:http://www.djangoproject.com/documentation/db-api/#related-objects > > > > > Hope that helps, > > > > Grant > > > > > On Jul 19, 11:02 am, Joshua <[EMAIL PROTECTED]> wrote: > > > > > > I've tried to search for a solution to this problem for the last 2 > > > > > hours and I can't seem to figure it out. > > > > > > I basically want to return a joined table from a queryset - formatted > > > > > for my template. > > > > > > I can't seem to figure out how to do this with the Django database > > > > > API. > > > > > > With SQL a join query works out to: > > > > > > ''' > > > > > select project_portfolio.*, client.* > > > > > from project_portfolio left join client > > > > > on project_portfolio.id = client.id > > > > > ''' > > > > > with the following simplified models: > > > > > > class project_portfolio(models.Model): > > > > > project_name_char = models.CharField() > > > > > project_client = models.ForeignKey(client) > > > > > > class client(models.Model): > > > > > client_name_char = models.CharField > > > > > > The challenge here seems to be that I have to return MULTIPLE > > > > > project_portfolio objects and THEN get the "client" data - because NOT > > > > > all "clients" have "project_portfolio(s)" > > > > > > Thank you in advance for any help - Josh --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to loop through a Dict to add values?
you're not adding two ints, you're adding an int to an instance of your Choice class. make your line: pr = pr + a['choice'].value or whatever you called it. Greg wrote: > Hello, > I have the following view > > def showcart(request, style_id, choice_id): > s = Style.objects.get(id=style_id) > c = Choice.objects.get(id=choice_id) > cart = request.session.get('cart', []) > cart.append({'style': s, 'choice': c}) > request.session['cart'] = cart > pr = 0 > for a in cart: > pr = pr + a['choice'] > return render_to_response('show_test.html', {'mychoice': cart, > 'p': pr}) > > > / > > Whenever i try this I get the error: > > TypeError at /rugs/cart/1/4/ > unsupported operand type(s) for +: 'int' and 'Choice' > > // > > Anybody know how I pull a value out of a dict and add it to a existing > number? > > Thanks > > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to loop through a Dict to add values?
Derek, I tried that and now I get the following error: AttributeError at /rugs/cart/1/4/ 'Choice' object has no attribute 'value' / Here is my view def showcart(request, style_id, choice_id): s = Style.objects.get(id=style_id) c = Choice.objects.get(id=choice_id) #x = c.size, " ", c.price cart = request.session.get('cart', []) cart.append({'style': s, 'choice': c}) request.session['cart'] = cart pr = 0 for a in cart: pr = pr + a['choice'].value return render_to_response('show_test.html', {'mychoice': cart, 'p': pr}) / On Jul 19, 4:22 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: > you're not adding two ints, you're adding an int to an instance of your > Choice class. make your line: > > pr = pr + a['choice'].value > > or whatever you called it. > > Greg wrote: > > Hello, > > I have the following view > > > def showcart(request, style_id, choice_id): > >s = Style.objects.get(id=style_id) > >c = Choice.objects.get(id=choice_id) > >cart = request.session.get('cart', []) > >cart.append({'style': s, 'choice': c}) > >request.session['cart'] = cart > > pr = 0 > >for a in cart: > > pr = pr + a['choice'] > > return render_to_response('show_test.html', {'mychoice': cart, > > 'p': pr}) > > > / > > > Whenever i try this I get the error: > > > TypeError at /rugs/cart/1/4/ > > unsupported operand type(s) for +: 'int' and 'Choice' > > > // > > > Anybody know how I pull a value out of a dict and add it to a existing > > number? > > > Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to loop through a Dict to add values?
you were supposed to substitute "value" with whatever column you have defined. (you didn't post your model def) Greg wrote: > Derek, > I tried that and now I get the following error: > > AttributeError at /rugs/cart/1/4/ > 'Choice' object has no attribute 'value' > > / > > Here is my view > > def showcart(request, style_id, choice_id): > s = Style.objects.get(id=style_id) > c = Choice.objects.get(id=choice_id) > #x = c.size, " ", c.price > cart = request.session.get('cart', []) > cart.append({'style': s, 'choice': c}) > request.session['cart'] = cart > pr = 0 > for a in cart: > pr = pr + a['choice'].value > return render_to_response('show_test.html', {'mychoice': cart, 'p': > pr}) > > / > > > > > > On Jul 19, 4:22 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: >> you're not adding two ints, you're adding an int to an instance of your >> Choice class. make your line: >> >> pr = pr + a['choice'].value >> >> or whatever you called it. >> >> Greg wrote: >>> Hello, >>> I have the following view >>> def showcart(request, style_id, choice_id): >>>s = Style.objects.get(id=style_id) >>>c = Choice.objects.get(id=choice_id) >>>cart = request.session.get('cart', []) >>>cart.append({'style': s, 'choice': c}) >>>request.session['cart'] = cart >>> pr = 0 >>>for a in cart: >>> pr = pr + a['choice'] >>> return render_to_response('show_test.html', {'mychoice': cart, >>> 'p': pr}) >>> / >>> Whenever i try this I get the error: >>> TypeError at /rugs/cart/1/4/ >>> unsupported operand type(s) for +: 'int' and 'Choice' >>> // >>> Anybody know how I pull a value out of a dict and add it to a existing >>> number? >>> Thanks > > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: schema evolution
It's great! I have my own schema evolution solution here http://code.google.com/p/django-schemaevolution/. But yours seems to be more powerful. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Using Sessions to display the contents of a shopping cart
The way we handle it with Satchmo is to have a cart object and store that id in the session. It's pretty simple and does not require a user to be logged in. -Chris --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to loop through a Dict to add values?
Derek, Ok...I made the change and I'm now getting the error: TypeError at /rugs/cart/1/4/ unsupported operand type(s) for +: 'int' and 'Price' Is 'a['choice'].price' not an Int? It says it is in my model file. Here is my view def showcart(request, style_id, choice_id): s = Style.objects.get(id=style_id) c = Choice.objects.get(id=choice_id) #x = c.size, " ", c.price cart = request.session.get('cart', []) cart.append({'style': s, 'choice': c}) request.session['cart'] = cart pr = 0 for a in cart: pr = pr + a['choice'].price return render_to_response('show_test.html', {'mychoice': cart, 'p': pr}) / Here is my template file: {% extends "rug_leftnav.html" %} {% block body %} {% for a in mychoice %} {{ a.style.manufacturer }} - {{ a.style.collection }} - {{ a.style }} - {{ a.choice.size }} - ${{ a.choice.price }}.00 {% endfor %} {{ p }} {% endblock %} // Here are some of my model classes: class Size(models.Model): name = models.CharField(maxlength=100) def __str__(self,): return self.name class Admin: pass class Price(models.Model): name = models.IntegerField() def __str__(self,): return str(self.name) class Admin: pass class Choice(models.Model): choice = models.ForeignKey(Collection, edit_inline=models.TABULAR, num_in_admin=5) size = models.ForeignKey(Size, core=True) price = models.ForeignKey(Price, core=True) def __str__(self,): return str((self.size, self.price)) class Style(models.Model): name = models.CharField(maxlength=200) color = models.CharField(maxlength=100) image = models.ImageField(upload_to='site_media/') theslug = models.SlugField(prepopulate_from=('name',)) manufacturer = models.ForeignKey(Manufacturer) collection = models.ForeignKey(Collection) sandp = models.ManyToManyField(Choice) class Admin: search_fields = ['name'] list_filter = ('collection',) list_display = ('name', 'theslug','collection', 'rmanu') js = ( '/site_media/ajax_yahoo.js', ) def __str__(self,): return self.name def rmanu(self): return self.collection.manufacturer // Thanks for your help Derek On Jul 19, 4:46 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: > you were supposed to substitute "value" with whatever column you have > defined. (you didn't post your model def) > > Greg wrote: > > Derek, > > I tried that and now I get the following error: > > > AttributeError at /rugs/cart/1/4/ > > 'Choice' object has no attribute 'value' > > > / > > > Here is my view > > > def showcart(request, style_id, choice_id): > >s = Style.objects.get(id=style_id) > >c = Choice.objects.get(id=choice_id) > >#x = c.size, " ", c.price > >cart = request.session.get('cart', []) > >cart.append({'style': s, 'choice': c}) > >request.session['cart'] = cart > >pr = 0 > >for a in cart: > >pr = pr + a['choice'].value > >return render_to_response('show_test.html', {'mychoice': cart, 'p': > > pr}) > > > / > > > On Jul 19, 4:22 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: > >> you're not adding two ints, you're adding an int to an instance of your > >> Choice class. make your line: > > >> pr = pr + a['choice'].value > > >> or whatever you called it. > > >> Greg wrote: > >>> Hello, > >>> I have the following view > >>> def showcart(request, style_id, choice_id): > >>>s = Style.objects.get(id=style_id) > >>>c = Choice.objects.get(id=choice_id) > >>>cart = request.session.get('cart', []) > >>>cart.append({'style': s, 'choice': c}) > >>>request.session['cart'] = cart > >>> pr = 0 > >>>for a in cart: > >>> pr = pr + a['choice'] > >>> return render_to_response('show_test.html', {'mychoice': cart, > >>> 'p': pr}) > >>> / > >>> Whenever i try this I get the error: > >>> TypeError at /rugs/cart/1/4/ > >>> unsupported operand type(s) for +: 'int' and 'Choice' > >>> // > >>> Anybody know how I pull a value out of a dict and add it to a existing > >>> number? > >>> Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How do I know if fastcgi is installed correctly? (using dreamhost)
in your shell, if you cd into /home/walterbyrd/django.niche-software/ django and type ./dispatch.fcgi, what do you get? in the dreamhost control panel do you have the domain set up with FastCGI support? what about Extra Web Security? On Jul 19, 4:36 pm, walterbyrd <[EMAIL PROTECTED]> wrote: > On Jul 19, 12:24 pm, FrankW <[EMAIL PROTECTED]> wrote: > > > A couple of things to check - what are the permissions on > > dispatch.fcgi? > > It needs to be executable, e.g. -rwxr-xr-x > > Permissions are correct. > > > Also, make sure it does not have DOS mode CR-LF > > No DOS mode CR-LF. > > > And, do you have debug set in your settings.py? > > from settings.py > > DEBUG = True > TEMPLATE_DEBUG = DEBUG > > My file structure: > > django.niche-software.com/ > --- dispatch.fcgi > --- hello.fcgi > --- .htaccess > --- django/ > -- django_media/ > -- django_projects/ > - myproject/ > settings.py > - sqlite-3.4.0 > -- django_src/ > -- django_templates > > The hello.fcgi I got from the dreamhost wiki: > > http://www.skweezer.net/bloglines/s.aspx/2/wiki.dreamhost.com/Special... > > The hello.fcgi looks like this: > > #!/usr/bin/python2.3 > from flup.server.fcgi import WSGIServer > def test_app(environ, start_response): start_response('200 OK', > [('Content-Type', 'text/plain')]) yield 'Hello, world!\n' > WSGIServer(test_app).run() > > I tried running that, and got the same 500 error. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: schema evolution
yeah, i did a poor/non-existent job advocating inclusion of my SoC work into django-proper. (combination of frustration with my original mentor and busy prepping for starting my phd right after it ended - i just handed it off and didn't follow through afterwards) but i use django quite a bit now and am surprised some sort of this hasn't been merged yet, so i figured i'd bring it up to date and re-release. daev wrote: > It's great! I have my own schema evolution solution here > http://code.google.com/p/django-schemaevolution/. But yours seems to > be more powerful. > > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to loop through a Dict to add values?
well, you're dealing in $$$, so you prob. want floats...but where is your FloatField? an attribute of your class Price? or can you cast your Price class to a float? pr = 0.0 for a in cart: pr = pr + float(a['choice'].price) do you understand how classes in object oriented languages work? you can only add numbers together, not your own custom classes. (without some extra work i expect - i don't know how operator overloading in python works, or even if it exists) this is what your error statement is telling you...that you're trying to add a number to a non-number class. you have to pull the actual number out of whatever class structure you've put it in. Greg wrote: > Derek, > Ok...I made the change and I'm now getting the error: > > TypeError at /rugs/cart/1/4/ > unsupported operand type(s) for +: 'int' and 'Price' > > Is 'a['choice'].price' not an Int? It says it is in my model file. > > > > Here is my view > > def showcart(request, style_id, choice_id): > s = Style.objects.get(id=style_id) > c = Choice.objects.get(id=choice_id) > #x = c.size, " ", c.price > cart = request.session.get('cart', []) > cart.append({'style': s, 'choice': c}) > request.session['cart'] = cart > pr = 0 > for a in cart: > pr = pr + a['choice'].price > return render_to_response('show_test.html', {'mychoice': cart, 'p': > pr}) > > > / > > Here is my template file: > > {% extends "rug_leftnav.html" %} > {% block body %} > {% for a in mychoice %} > {{ a.style.manufacturer }} - {{ a.style.collection }} - {{ a.style }} > - {{ a.choice.size }} - ${{ a.choice.price }}.00 > > {% endfor %} > {{ p }} > {% endblock %} > > // > > Here are some of my model classes: > > class Size(models.Model): > name = models.CharField(maxlength=100) > > def __str__(self,): > return self.name > > class Admin: > pass > > class Price(models.Model): > name = models.IntegerField() > > def __str__(self,): > return str(self.name) > > class Admin: > pass > > > class Choice(models.Model): > choice = models.ForeignKey(Collection, edit_inline=models.TABULAR, > num_in_admin=5) > size = models.ForeignKey(Size, core=True) > price = models.ForeignKey(Price, core=True) > def __str__(self,): > return str((self.size, self.price)) > > class Style(models.Model): > name = models.CharField(maxlength=200) > color = models.CharField(maxlength=100) > image = models.ImageField(upload_to='site_media/') > theslug = models.SlugField(prepopulate_from=('name',)) > manufacturer = models.ForeignKey(Manufacturer) > collection = models.ForeignKey(Collection) > sandp = models.ManyToManyField(Choice) > > class Admin: > search_fields = ['name'] > list_filter = ('collection',) > list_display = ('name', 'theslug','collection', 'rmanu') > > js = ( > '/site_media/ajax_yahoo.js', > ) > > def __str__(self,): > return self.name > > def rmanu(self): > return self.collection.manufacturer > > > // > > > Thanks for your help Derek > > > On Jul 19, 4:46 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: >> you were supposed to substitute "value" with whatever column you have >> defined. (you didn't post your model def) >> >> Greg wrote: >>> Derek, >>> I tried that and now I get the following error: >>> AttributeError at /rugs/cart/1/4/ >>> 'Choice' object has no attribute 'value' >>> / >>> Here is my view >>> def showcart(request, style_id, choice_id): >>>s = Style.objects.get(id=style_id) >>>c = Choice.objects.get(id=choice_id) >>>#x = c.size, " ", c.price >>>cart = request.session.get('cart', []) >>>cart.append({'style': s, 'choice': c}) >>>request.session['cart'] = cart >>>pr = 0 >>>for a in cart: >>>pr = pr + a['choice'].value >>>return render_to_response('show_test.html', {'mychoice': cart, 'p': >>> pr}) >>> / >>> On Jul 19, 4:22 pm, Derek Anderson <[EMAIL PROTECTED]> wrote: you're not adding two ints, you're adding an int to an instance of your Choice class. make your line: pr = pr + a['choice'].value or whatever you called it. Greg wrote: > Hello, > I have the following view > def showcart(request, style_id, choice_id): >s = Style.objects.get(id=style_id) >c = Choice.objects.get(id=choice_id) >cart = request.session.get('cart', []) >cart.append({'style': s, 'choice': c}) >request.session['cart'] = cart > pr = 0 >for a in cart: > pr = pr + a['choice'] > return render_to_response('show_test.html', {'mychoice': cart, > 'p': pr}) > / > When
Re: forloop variables without for
Thanks mate, it works great. Anybody could tell me if there is something like that for counting items on that? Don't want to do: {% for image in images %} {% if forloop.last %} {{ forloop.counter }} {% endif %} {% endfor %} On Jul 19, 7:51 pm, sean <[EMAIL PROTECTED]> wrote: > Try {{ images.0.image }} > > Sean > > On Jul 19, 7:43 pm, Marc Garcia <[EMAIL PROTECTED]> wrote: > > > Hi! > > > In a project I get a set of images from a model, and then I display it > > on the template. In same template (but in another place), I just want > > to display first element of set, and number of objects given. Can I do > > it without adding those fields to views.py? > > > I've found a way for doing first, but it isn't very efficient: > > > In views: > > images = tImage.objects.filter(product=product_id) > > > In template: > > {% for image in images %} > > {% if forloop.first %} > >{{ image.image }} > > {% endif %} > > {% endfor %} > > > Thanks a lot! > > Marc --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with multiple django versions on mod_python
On Jul 19, 2:07 pm, "Russell Keith-Magee" <[EMAIL PROTECTED]> wrote: > On 7/19/07, oggie rob <[EMAIL PROTECTED]> wrote: > > > Please, if you've seen the same issue or have any helpful ideas to try > > to stop the error, let me know. > > I think I've seen the same problem (or, at least, an analogous one). > Unfortunately, I can't provide much by way of helpful debug or > solution - the sysadmin that identified the problem for us isn't > around for me to ask him for more details. > > As I recall, the problem was mod_python. Older versions of mod_python > had some sort of issue with caching python instances. As a result, if > you deployed two different versions of Django, the version of Django > that was provided to a given request was determined by the thread that > served the request. If the first request served by a thread used the > old version of Django, that was the version that was used for all > subsequent requests on that thread, regardless of the version that was > required to satisfy the request. For the record, the description which was given to you whereby "if the first request served by a thread used the old version of Django, that was the version that was used for all subsequent requests on that thread" is nonsense. There has never been a problem with mod_python which would have caused that sort of behaviour. > I believe we fixed the problem by updating mod_python, but I'm not > completely certain on that. Always a good idea regardless. Using mod_python 3.3.1 is high recommended. Where problems can come up with hosting multiple Django instances is not with mod_python or Django, but with third party C extension modules which haven't been written correctly so as to be used concurrently from multiple Python sub interpreters. One concrete example which was identified recently was Decimal support in pyscopg module. http://www.initd.org/tracker/psycopg/ticket/192 In short, a C extension module may cache data from one sub interpreter and then use it in the context of a different sub interpreter causing incorrect or errornous behaviour. The problem with Decimal support in pyscopg falls into this category. It is entirely possible that the OP may have been hitting a similar obscure problem in the database adapter being used. The only real way to ensure that such a problem isn't encountered is to use mod_fastcgi or mod_wsgi daemon mode. In both these hosting solutions for Apache the Django instance can be run in a distinct process and thus one doesn't encounter issues with C extension modules that aren't written to work with multiple sub interpreters properly. Graham --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Mapping models to CRUD urls?
Loving django still, and now I'm at the point where I'm running into a limit on my understanding on how to map the Model CRUD functions (non- admin style) to a URL pattern. For example: Model1: fielda fieldb Model2: key=Foreignkey(model1) fielda fieldb Model3: key=foriengkey(model2) fielda fieldb So, i'm looking for some help to allow me to CRUD each of these models, and I've come up with a few: http://.../model1/add - calls a view to add a new model1 object to the DB. http://.../model1/edit/#- calls a view to update the model1 ID = # http://.../model2/add/#- calls a view to add a new model2, with a foreign key model1 of # http://.../model2/edit/#- calls a view to edit a model2 of ID #. I guess I continue the same pattern for all sub-models? so model3 would be: http://.../model3/add/#- calls a view to add a new model3, with foreign key model2 of # http://.../model3/edit/#- calls a view to edit a model3 of ID# It seems simple enough, but wanted to get everyones feedback on anything I'm missing, or is it just this simple? Thanks John --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with multiple django versions on mod_python
On 7/20/07, Graham Dumpleton <[EMAIL PROTECTED]> wrote: > > For the record, the description which was given to you whereby "if the > first request served by a thread used the old version of Django, that > was the version that was used for all subsequent requests on that > thread" is nonsense. There has never been a problem with mod_python > which would have caused that sort of behaviour. I'll take your word for it. Like I said, I wasn't able to get hold of the sysadmin that sorted out the problem, so it's entirely possible I have the details completely mixed up. Yours, Russ Magee %-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with multiple django versions on mod_python
> In short, a C extension module may cache data from one sub interpreter > and then use it in the context of a different sub interpreter causing > incorrect or errornous behaviour. The problem with Decimal support in > pyscopg falls into this category. It is entirely possible that the OP > may have been hitting a similar obscure problem in the database > adapter being used. > > The only real way to ensure that such a problem isn't encountered is > to use mod_fastcgi or mod_wsgi daemon mode. In both these hosting > solutions for Apache the Django instance can be run in a distinct > process and thus one doesn't encounter issues with C extension modules > that aren't written to work with multiple sub interpreters properly. > > Graham Yep, that sounds like it! That raises some questions as to the recommended apache setup. At least I know a workaround, for now, but I will be watching the psycopg wiki closely. Thank you very much for pointing this out - I was a bit lost there and only knew something was fishy. -rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Multiple URLconfs per app?
Thanks, guys. On Jul 19, 12:52 am, Nathan Ostgard <[EMAIL PROTECTED]> wrote: > If you just want to specify the urls as listed, you could always > create a urls folder in myapp, put an __init__.py in there, and create > myapp/urls/feature1.py and myapp/urls/feature2.py. > > > Nathan Ostgard > > On Jul 18, 7:37 pm, Collin Grady <[EMAIL PROTECTED]> wrote: > > > You'll need two files. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: forloop variables without for
Glad to help. {{ images.image_set.count }} or similar should work, depending on your models. cheers, Sean On Jul 20, 1:13 am, Marc Garcia <[EMAIL PROTECTED]> wrote: > Thanks mate, it works great. > > Anybody could tell me if there is something like that for counting > items on that? > > Don't want to do: > {% for image in images %} > {% if forloop.last %} >{{ forloop.counter }} > {% endif %} > {% endfor %} > > On Jul 19, 7:51 pm, sean <[EMAIL PROTECTED]> wrote: > > > Try {{ images.0.image }} > > > Sean > > > On Jul 19, 7:43 pm, Marc Garcia <[EMAIL PROTECTED]> wrote: > > > > Hi! > > > > In a project I get a set of images from a model, and then I display it > > > on the template. In same template (but in another place), I just want > > > to display first element of set, and number of objects given. Can I do > > > it without adding those fields to views.py? > > > > I've found a way for doing first, but it isn't very efficient: > > > > In views: > > > images = tImage.objects.filter(product=product_id) > > > > In template: > > > {% for image in images %} > > > {% if forloop.first %} > > >{{ image.image }} > > > {% endif %} > > > {% endfor %} > > > > Thanks a lot! > > > Marc --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Emergency - In Need Of Developer
I need a developer in the US (only) with at least 2 years experience with Django/Python to fix and optimize a Django site I had done a few weeks back. The original developer can no longer be contacted and the code is horribly inefficient, delaying the site from launch. Please email me for more details. Thanks, Peter -- View this message in context: http://www.nabble.com/Emergency---In-Need-Of-Developer-tf4114485.html#a11700313 Sent from the django-users mailing list archive at Nabble.com. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Unicode problem while changing from 0.95 to latest developer version
On 7/19/07, piotr <[EMAIL PROTECTED]> wrote: ... > TemplateSyntaxError: Caught an exception while rendering: 'utf8' codec > can't decode bytes in position 833-834: invalid data > ... > Any idea what can be wrong? I'm betting a string it's trying to decode isn't in utf-8. ;-) Go through this checklist: http://code.djangoproject.com/wiki/UnicodeBranch#PortingApplicationsTheQuickChecklist If still problems, check to see what string it's working with there, and adjust the unicode-related settings and/or file encoding declarations as needed. (DEFAULT_CHARSET, FILE_CHARSET, etc.) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: schema evolution
Hey all, Sorry for the double-post, but I've written up some examples / documentation: http://kered.org/blog/wp-content/uploads/2007/07/django_schema_evolution_documentation.html Also, I've ported the changes to SVN. I would like to solicit testers, for potential inclusion in django-proper. Thanks, Derek Derek Anderson wrote: > Hey all, > > I've ported my schema evolution work from my SoC project last summer to > Django v0.96. To use it, download the patch below, and run the following: > > $ cd //site-packages/django/ > $ patch -p1 < ~//django_schema_evolution-v096patch.txt > > It should output the following: > > patching file core/management.py > patching file db/backends/mysql/base.py > patching file db/backends/mysql/introspection.py > patching file db/backends/postgresql/base.py > patching file db/backends/postgresql/introspection.py > patching file db/backends/sqlite3/base.py > patching file db/backends/sqlite3/introspection.py > patching file db/models/fields/__init__.py > patching file db/models/options.py > > To use it: > > $ cd // > $ ./manage.py sqlevolve > > It should output something like this: > > BEGIN; > ALTER TABLE `main_query` CHANGE COLUMN `accuracy` `accuracynew` > numeric(10, 6) NULL; > ALTER TABLE `main_query` ADD COLUMN `price` varchar(256) NULL; > COMMIT; > > Assuming you have a model such as this: > > class Query(models.Model): > query = models.CharField(maxlength=256, blank=False) > accuracynew = models.FloatField(max_digits=10, decimal_places=6, > null=True, blank=True, aka='accuracy') > price = models.CharField(maxlength=256, null=True, blank=True) # > new column > > Note the aka field where I changed the name of "accuracy" to "accuracynew". > > Let me know if you find any bugs. > > http://kered.org/blog/2007-07-19/django-schema-evolution/ > http://kered.org/blog/wp-content/uploads/2007/07/django_schema_evolution-v096patch.txt > > -- Derek > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Mapping models to CRUD urls?
On 7/20/07, John M <[EMAIL PROTECTED]> wrote: > > http://.../model3/add/#- calls a view to add a new model3, with > foreign key model2 of # > http://.../model3/edit/#- calls a view to edit a model3 of ID# > > It seems simple enough, but wanted to get everyones feedback on > anything I'm missing, or is it just this simple? It's pretty much that simple, although there are a few details I would suggest: - You have add and edit views, but no 'view' view - i.e., just show me the object. The best place for this is probably http://.../model1/# for model1, ID # (repeated for other models). Alternatively, if there is no such thing as a non-editing view - if you want an object to be editable whenever it is viewed, just make the http://.../model1/# view the edit view. If you do this, make sure you do a HttpResponseRedirect when you POST to prevent the POST request ending up in the browser history. - You might want to have a think about your method of foreign key hinting using the URL. Each URL should be a unique, cachable resource - in this case, "add an instance of model3". Adding transient/suggested data to your URL would generally violate this principle. On top of that, what do you do to the URL space if you need to specify 2 foreign keys? A alternate approach would be to pass in the preferred foreign key as part of the GET dictionary i.e., your request would be: /model3/add/?model1=3. That way, there is only 1 URL resource (the add page at /model3/add/), and the view can still work if you have no or multiple specified foreign key references (just modify the handling of the GET dictionary to inspect 0, 1 or many keys). Yours, Russ Magee %-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---