Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
I've attached a fix for this issue.
SY, Alexey
2006/7/21, Victor A Martynov [EMAIL PROTECTED]:
Hello Geir,
I created new JIRA:
HARMONY-946
on this issue.
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Geir Magnusson Jr [EMAIL PROTECTED] wrote:
We have a bug. 0.0.0.0 should be all adapters, and is legit.
Can you file a JIRA?
Victor A Martynov wrote:
Hello Mikhail,
Here are the results of running the modified test:
---
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099, 0,
InetAddress.getByName(0.0.0.0));
System.out.println(ss.getInetAddress());
Socket s = new Socket(0.0.0.0, 1099);
}
}
---
c:\testjava Test
/0.0.0.0
c:\testC:/Harmony/bin/ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310,
debug
c:\testC:/Harmony/bin/ij Test
/0.0.0.0
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:10)
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mikhail Fursov [EMAIL PROTECTED] wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP
must be
specified manually.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--
Mikhail Fursov
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
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--
Alexey A. Petrenko
Intel Middleware Products Division
-
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Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hello Geir,
I created new JIRA:
HARMONY-946
on this issue.
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Geir Magnusson Jr [EMAIL PROTECTED] wrote:
We have a bug. 0.0.0.0 should be all adapters, and is legit.
Can you file a JIRA?
Victor A Martynov wrote:
Hello Mikhail,
Here are the results of running the modified test:
---
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099, 0,
InetAddress.getByName(0.0.0.0));
System.out.println(ss.getInetAddress());
Socket s = new Socket(0.0.0.0, 1099);
}
}
---
c:\testjava Test
/0.0.0.0
c:\testC:/Harmony/bin/ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310,
debug
c:\testC:/Harmony/bin/ij Test
/0.0.0.0
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:10)
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mikhail Fursov [EMAIL PROTECTED] wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP
must be
specified manually.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--
Mikhail Fursov
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
[classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP must be
specified manually.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--
Mikhail Fursov
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hello Mark,
I run the example on MS Windows XP, Harmony classlib+DRLVM dated 11 july
2006.
c:\testc:\Harmony\bin\ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
The documentation of java.net.Socket says nothing about 0.0.0.0 address,
but documentation on java.net.DatagramSocket has a reference to it:
http://java.sun.com/j2se/1.4.2/docs/api/java/net/DatagramSocket.html
If the IP address is 0.0.0.0, the socket will be bound to the wildcard
address, an IP address chosen by the kernel.
So it's normal to use 0.0.0.0 and we have a bug.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello Mark,
I run the example on MS Windows XP, Harmony classlib+DRLVM dated 11 july
2006.
c:\testc:\Harmony\bin\ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Mikhail Fursov
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hello Mikhail,
Here are the results of running the modified test:
---
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099, 0,
InetAddress.getByName(0.0.0.0));
System.out.println(ss.getInetAddress());
Socket s = new Socket(0.0.0.0, 1099);
}
}
---
c:\testjava Test
/0.0.0.0
c:\testC:/Harmony/bin/ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
c:\testC:/Harmony/bin/ij Test
/0.0.0.0
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:10)
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mikhail Fursov [EMAIL PROTECTED] wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP must be
specified manually.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--
Mikhail Fursov
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Mikhail Fursov wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP must be
specified manually.
I don't think so. 0.0.0.0 should mean all of them, right?
geir
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hello Mark,
I checked the behavior of the test on Linux. It seems that the problem
exists on MS Windows only:
--
[EMAIL PROTECTED]:~ uname -a
Linux server 2.6.5-7.145lxset1-smp #1 SMP Thu Jan 27 09:19:29 UTC 2005 i686
i686 i386 GNU/Linux
[EMAIL PROTECTED]:~ Harmony/bin/ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Linux/ia32/gcc 3.3.4, debug
[EMAIL PROTECTED]:~ Harmony/bin/ij Test
/0.0.0.0
[EMAIL PROTECTED]:~ java Test
/0.0.0.0
[EMAIL PROTECTED]:~
--
The fact that Windows and Linux version behavior is different makes me think
that it is a bug in LUNI rather than the bug in RI.
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
On 7/20/06, Mikhail Fursov [EMAIL PROTECTED] wrote:
The documentation of java.net.Socket says nothing about 0.0.0.0 address,
but documentation on java.net.DatagramSocket has a reference to it:
http://java.sun.com/j2se/1.4.2/docs/api/java/net/DatagramSocket.html
If the IP address is 0.0.0.0, the socket will be bound to the wildcard
address, an IP address chosen by the kernel.
Hello Mikhail, they are different. New DatagramSocket(0.0.0.0,port) means
the datagram socket will be bound to 0.0.0.0, but new Socket(0.0.0.0,port)
means new a socket bound with a system free port and then connect to (
0.0.0.0, port).
I didn't investigate Harmony implementation code, but I guess it's caused by
difference of system call. On windows, 0.0.0.0 is regarded as a invalid
address, while on Linux, it's valid.
I'll take a deep look at the code later on.
So it's normal to use 0.0.0.0 and we have a bug.
Agree. I think we should follow RI this time.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello Mark,
I run the example on MS Windows XP, Harmony classlib+DRLVM dated 11 july
2006.
c:\testc:\Harmony\bin\ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310,
debug
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov
[EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable
{
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Mikhail Fursov
--
Andrew Zhang
China Software Development Lab, IBM
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
We have a bug. 0.0.0.0 should be all adapters, and is legit.
Can you file a JIRA?
Victor A Martynov wrote:
Hello Mikhail,
Here are the results of running the modified test:
---
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099, 0,
InetAddress.getByName(0.0.0.0));
System.out.println(ss.getInetAddress());
Socket s = new Socket(0.0.0.0, 1099);
}
}
---
c:\testjava Test
/0.0.0.0
c:\testC:/Harmony/bin/ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
c:\testC:/Harmony/bin/ij Test
/0.0.0.0
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:10)
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mikhail Fursov [EMAIL PROTECTED] wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP
must be
specified manually.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--
Mikhail Fursov
-
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Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
2006/7/20, Alexey Petrenko [EMAIL PROTECTED]:
That's a different types of sockets. You specify address to BIND for
DatagramSocket and address to CONNECT for Socket.
Address to bind can be chosen by underlying system.
But how do you suggest to choose address to connect? :)
I'll check the IP protocol spec for the meaning of 0.0.0.0 address. If
there is any...
I could not find anything in the IP spec. But C headers defines
0.0.0.0 as a value for INADDR_ANY constant... Ant it is used to bind a
socket to all the local addresses.
So I think that exception is OK here.
SY, Alexey
2006/7/20, Mikhail Fursov [EMAIL PROTECTED]:
The documentation of java.net.Socket says nothing about 0.0.0.0 address,
but documentation on java.net.DatagramSocket has a reference to it:
http://java.sun.com/j2se/1.4.2/docs/api/java/net/DatagramSocket.html
If the IP address is 0.0.0.0, the socket will be bound to the wildcard
address, an IP address chosen by the kernel.
So it's normal to use 0.0.0.0 and we have a bug.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello Mark,
I run the example on MS Windows XP, Harmony classlib+DRLVM dated 11 july
2006.
c:\testc:\Harmony\bin\ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
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Terms of use : http://incubator.apache.org/harmony/mailing.html
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--
Mikhail Fursov
--
Alexey A. Petrenko
Intel Middleware Products Division
--
Alexey A. Petrenko
Intel Middleware Products Division
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Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
On 7/20/06, Geir Magnusson Jr [EMAIL PROTECTED] wrote:
Mikhail Fursov wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP must
be
specified manually.
I don't think so. 0.0.0.0 should mean all of them, right?
Yes. a socket listens on 0.0.0.0 means on it listens on all of network
interfaces on this machine. It's often used for binding function.
But the behaviour of connecting to 0.0.0.0 is unspeicified. At least,
windows treats it as invalid target address, while linux allows it.
geir
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Andrew Zhang
China Software Development Lab, IBM
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Yes, you're right - any of them.
BTW I tried to build debug version of classlib to have HYSOCKDEBUG enabled
and have a problem with build (lack of experience)
I tried to add -DDEBUG flag to classlib\trunk\depends\build\defines.mak and
rerun ant build but nothing was rebuilded.
What is the right way to rebuild classlib to enable logging like
HYSOCKDEBUG?
On 7/20/06, Geir Magnusson Jr [EMAIL PROTECTED] wrote:
Mikhail Fursov wrote:
Add this line to the test to clarify the situation:
System.out.println(ss.getInetAddress());
I think that for PC with multiple network adapters serversocket IP must
be
specified manually.
I don't think so. 0.0.0.0 should mean all of them, right?
geir
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello,
I'm having trouble with an application. This problem concerns creating
java.net.Socket on host 0.0.0.0.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Mikhail Fursov
Re: [classlib] Uncertain behavior of new Socket(0.0.0.0, 1099);
Hi Mikhail,
I don't think this description of DatagramSocket constructor is
somehow applicable to the Victor's example. In this description we
deal with *local* address to bind DatagramSocket to (to receive
DatagramPackets). But in the example above 0.0.0.0 is used as a
*destination* address for plain Socket to establish a connection to.
This is the completely different case IMHO. BTW, I'm not sure it is
possible to establish a connection to a wildcard address.
Regards,
2006/7/20, Mikhail Fursov [EMAIL PROTECTED]:
The documentation of java.net.Socket says nothing about 0.0.0.0 address,
but documentation on java.net.DatagramSocket has a reference to it:
http://java.sun.com/j2se/1.4.2/docs/api/java/net/DatagramSocket.html
If the IP address is 0.0.0.0, the socket will be bound to the wildcard
address, an IP address chosen by the kernel.
So it's normal to use 0.0.0.0 and we have a bug.
On 7/20/06, Victor A Martynov [EMAIL PROTECTED] wrote:
Hello Mark,
I run the example on MS Windows XP, Harmony classlib+DRLVM dated 11 july
2006.
c:\testc:\Harmony\bin\ij -version
Apache Harmony DRLVM HEAD-4807 (2006-05-02), Windows/ia32/msvc 1310, debug
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
On 7/20/06, Mark Hindess [EMAIL PROTECTED] wrote:
On 20 July 2006 at 15:34, Victor A Martynov [EMAIL PROTECTED]
wrote:
Hello,
I'm having trouble with an application. This problem concerns
creating
java.net.Socket on host 0.0.0.0.
What platform? Works for me on Linux (debian testing).
-Mark.
The test below illustrates this problem:
import java.net.*;
public class Test {
public static void main(String args[]) throws Throwable {
ServerSocket ss = new ServerSocket(1099);
Socket s = new Socket(0.0.0.0, 1099);
}
}
The output on RI and on Harmony differs:
c:\testjava Test
c:\testC:/Harmony/bin/ij Test
java.net.ConnectException: 0.0.0.0/0.0.0.0:1099 - The address is not
available
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:238)
at org.apache.harmony.luni.net.PlainSocketImpl.connect(
PlainSocketImpl.java:200)
at java.net.Socket.startupSocket(Socket.java:715)
at java.net.Socket.init(Socket.java:139)
at Test.main(Test.java:7)
I wonder whether it is a bug in RI or a bug in LUNI of Harmony?
=
Warm Regards,
Victor Martynov,
Intel Middleware Product Division
--=_Part_57416_17500570.1153395298489--
-
Terms of use : http://incubator.apache.org/harmony/mailing.html
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Mikhail Fursov
--
Alexei Zakharov,
Intel Middleware Product Division
-
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